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Morrison & Boyd Test: Hydrocarbons - NEET MCQ


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30 Questions MCQ Test - Morrison & Boyd Test: Hydrocarbons

Morrison & Boyd Test: Hydrocarbons for NEET 2024 is part of NEET preparation. The Morrison & Boyd Test: Hydrocarbons questions and answers have been prepared according to the NEET exam syllabus.The Morrison & Boyd Test: Hydrocarbons MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Morrison & Boyd Test: Hydrocarbons below.
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Morrison & Boyd Test: Hydrocarbons - Question 1

 

   Major Product 

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Morrison & Boyd Test: Hydrocarbons - Question 2

           

Major Product (A) is : 

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Morrison & Boyd Test: Hydrocarbons - Question 3

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Morrison & Boyd Test: Hydrocarbons - Question 4

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Morrison & Boyd Test: Hydrocarbons - Question 5

Product (B) will be : 

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Morrison & Boyd Test: Hydrocarbons - Question 6

(Major ) Product (A) will be :  

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Morrison & Boyd Test: Hydrocarbons - Question 7

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Morrison & Boyd Test: Hydrocarbons - Question 8

Product (A) will be :

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Morrison & Boyd Test: Hydrocarbons - Question 9

Mono-chloro product (inculding steroisomers)are :

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Morrison & Boyd Test: Hydrocarbons - Question 10

Arrange the following in decreasing order of their boiling points


A) n-butane
B) 2-methylbutane
C) n-pentane
D) 2,2-dimethylpropane

Detailed Solution for Morrison & Boyd Test: Hydrocarbons - Question 10

D is the correct answer.
The boiling point of alkanes increases with increase in molecular mass and for the same alkane, the boiling point decreases with branching. Thus, the decreasing order of their boiling points is:
       C                                     B                                        D                                     
n−Pentane>2−Methylbutane>2,2−Dimethylpropane
> n−Butane
          A

Morrison & Boyd Test: Hydrocarbons - Question 11

  

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Morrison & Boyd Test: Hydrocarbons - Question 12

products.
Which of the following is not the free radical combination product in wurtz process.

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Morrison & Boyd Test: Hydrocarbons - Question 13

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Morrison & Boyd Test: Hydrocarbons - Question 14

Methyl cyclohexane react with Br2 in presence of u.v. light major product will be

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Morrison & Boyd Test: Hydrocarbons - Question 15

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Morrison & Boyd Test: Hydrocarbons - Question 16

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Morrison & Boyd Test: Hydrocarbons - Question 17

 

Correct order of rate of reaction will be

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Reactivity of Alkyl Halide for Wurtz Rxn
R - I > R - Br > R - Cl > R - F

Morrison & Boyd Test: Hydrocarbons - Question 18

Which of the gases evolved on the surface of anode.

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Morrison & Boyd Test: Hydrocarbons - Question 19

Suitable reagent for following cenversion will be :

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Morrison & Boyd Test: Hydrocarbons - Question 20

2, 3-dimethyl butaneWhich of the following anion will be migrates towards anode to prepare 2, 3-dimethyl butane in the given reaction.

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Morrison & Boyd Test: Hydrocarbons - Question 21

Most stableconfomer of product will be (across C2 — C3 bond) :

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[ Most Stable Conformer of h butane across C2 - C3 bond ] 

Morrison & Boyd Test: Hydrocarbons - Question 22

 most stableconfomer of product will be :

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Most stable conformer of n - propane

Morrison & Boyd Test: Hydrocarbons - Question 23

Correct order of mono bromination of given compound is :

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[ Most stable free radical is formed as intermidiate ] Order of Bromination = I > III > II >

Morrison & Boyd Test: Hydrocarbons - Question 24

major product will be

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Morrison & Boyd Test: Hydrocarbons - Question 25

In kolbe’s electrolytic synthesis the pOH of solution will be

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in Kolbe’s eledrolysis process. NaOH / KOH is Formed at cathod so PH increases and POH decrease

Morrison & Boyd Test: Hydrocarbons - Question 26

product will be :

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Morrison & Boyd Test: Hydrocarbons - Question 27

Rate of decarboxylation of following carboxylic acid with sodalime will be in order

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[rater of decorboxylation µ stability of corbanion]
rate of decorboxylation = r1 > r2 > r3

Morrison & Boyd Test: Hydrocarbons - Question 28

Benzoic acid  Product will be

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Morrison & Boyd Test: Hydrocarbons - Question 29

Number of required O2 mole for complete combustion of one mole of propane-

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Morrison & Boyd Test: Hydrocarbons - Question 30

How much volume of air will be needed for complete combustion of 10 lit. of ethane-

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x mole oxygen are present in 5 x air
22.4 liter ethan are Complete Combused to required 7/2   22.4 o2 gas

Required volume of air for complete combustion = 3 5×5 = 175 liter

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