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Test: Environmental Engineering- 6 - Civil Engineering (CE) MCQ


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10 Questions MCQ Test - Test: Environmental Engineering- 6

Test: Environmental Engineering- 6 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Environmental Engineering- 6 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Environmental Engineering- 6 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Environmental Engineering- 6 below.
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Test: Environmental Engineering- 6 - Question 1

Which kind of plume has minimum downward mixing as its downward motion is prevented by inversion and upward mixing will be quite turbulent and rapid?

Detailed Solution for Test: Environmental Engineering- 6 - Question 1

It is a condition where exists a strong super-adiabatic lapse rate above surface inversion.

Lofting plume has minimum downward mixing due to presence of inversion and is considered as ideal case for dispersion of emission.

Test: Environmental Engineering- 6 - Question 2

According to the Noise Pollution (Regulation and Control) Rules, 2000, of the Ministry of Environment Forests, India, the day time and night time noise level limits in ambient air for residential area expressed in dB (A) Leq are

Detailed Solution for Test: Environmental Engineering- 6 - Question 2

Ambient air quality standards in respect of Noise as per Noise Pollution (Regulation and Control) Rules, 2000, of the Ministry of Environment & Forests, India are tabulated below:

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Test: Environmental Engineering- 6 - Question 3

Which of the following engineering system for air pollution control device can collect a particle size of less than one micrometer and can also have an efficiency as high as 99%

Detailed Solution for Test: Environmental Engineering- 6 - Question 3

The Particulate Control Devices description are as follow:

Hence, Fabric Filtration can collect small particles as one micrometre and can also have an efficiency as high as 99% or more.

Test: Environmental Engineering- 6 - Question 4

Two primary air pollutants are

Detailed Solution for Test: Environmental Engineering- 6 - Question 4

Sulphur dioxide carbon monoxide, nitrogen oxides, lead, hydrocarbons, allergic agents like pollens and spores and radioactive substances are primary pollutants. Sulphuric acid, ozone, formaldehydes & peroxyacylnitrates (PAN) are secondary pollutants.

Test: Environmental Engineering- 6 - Question 5

An air parcel having 40° temperature moves from ground level to 500m elevation in dry air following the “adiabatic lapse rate”. The temperature of air parcel at 500 m elevation will be

Detailed Solution for Test: Environmental Engineering- 6 - Question 5

Dry air cools at the rate of 9.8°C per km and it is called dry adiabatic lapse rate. In saturated (wet) air, this rate is calculated to be 6°C per km and is known as wet adiabatic lapse rate.

Resulting temperature of air
= 40 − 9.8 × 500/1000 = 40 − 4.9 = 35.1C

Test: Environmental Engineering- 6 - Question 6

Arrange the layers of the atmosphere in order of increasing heights from the surface of the earth 

Detailed Solution for Test: Environmental Engineering- 6 - Question 6

The Layers of atmosphere in order of increasing heights form the surge of earth

a) Troposphere_____ 0 to 11 km _____ 15 to -56°C

b) Stratosphere _____ 11 to 50 km _____ 15 to 0.2°C

c) Mesosphere _____ 50 to 85 km _____ -02° to -92°C

d) Thermosphere _____ 85 to 500 km _____ -92° to 1200°C

Test: Environmental Engineering- 6 - Question 7

Two electrostatic precipitators (ESPs) are in series. The fractional efficiencies of upstream and downstream ESPs for size dp are 80% and 65% respectively.

What is the overall efficiency of the system for the same dp?

Detailed Solution for Test: Environmental Engineering- 6 - Question 7


Let X be the concentration of particles in flue gas.

∴ Particles remained after ESP1 = (1-0.8) X = 0.2 X

Particles remained after ESP2 = (1-0.65) 0.2 X = 0.07 X

Test: Environmental Engineering- 6 - Question 8

Assuming annual travel for each vehicle to be 50000 km, the quantity of NOx produced from 200,000 vehicle with emission rate 2.5 gm/km/vehicle is

Detailed Solution for Test: Environmental Engineering- 6 - Question 8

NOx emitted by 200,000 vehicles

= 2.5 × 200,000

= 500,000 g/km

NOx produced by 200,000 vehicles for a distance of 50000 km

= 500,000 × 50000 × 10-6 tonnes

= 25000 tonnes.

Test: Environmental Engineering- 6 - Question 9

The mean indoor airborne chloroform (CHCl3) concentration in a room was determined to be 0.4 µg/m3. Use the following data:

T = 293 K

P = 1 atmosphere

R = 82.05 × 10-6 atm.m3/mol-K

Atomic weights: C = 12, H = 1, Cl = 35.5. The concentration expressed in parts per billion (volume basis, ppbv) is equal to –

Detailed Solution for Test: Environmental Engineering- 6 - Question 9


Molecular weight, M = 12 + 1 + 3 × 35.5 = 119.5

Test: Environmental Engineering- 6 - Question 10

At a location three sound pressure levels were recorded as 40 dB, 50 dB, & 60 dB. The average sound pressure level is ________

Detailed Solution for Test: Environmental Engineering- 6 - Question 10

The average sound pressure level at that location is:

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