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R.C. Mukherjee Test: Chemical Kinetics - JEE MCQ


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30 Questions MCQ Test - R.C. Mukherjee Test: Chemical Kinetics

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R.C. Mukherjee Test: Chemical Kinetics - Question 1

The rate of a reaction is expressed in different ways as follows :

 = 

The reaction is :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 1

B + 3D = 2C + 4A

R.C. Mukherjee Test: Chemical Kinetics - Question 2

The rate constant for the forward reaction A(g)  2B(g) is 1.5 × 10-3 s-1 at 100 K. If 10-5 moles of A and 100 moles of B are present in a 10 litre vessel at equilibrium then rate constant for the backward reaction at this temperature is

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 2


Kf = = 1.5 × 10–3 s–1
At eq.m, Rf = Rb
Kf  [A] = Kb[B]2
On solving : Kb = 1.5 × 10-11

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R.C. Mukherjee Test: Chemical Kinetics - Question 3

Reaction A + B → C + D follow's following rate law : rate = k[A]+1/2[B]1/2. Starting with initial conc. of 1 M of A and B each, what is the time taken for concentration of A of become 0.25 M.

Given : k = 2.303 × 10-3 sec-1.

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 3

Rate= K[A]1/2[B]1/2 

Overall order of reaction is = 1/2+1/2=1

∴ It is a 1st order reaction.

 

For concentration of A to become 0.5M:-t1/2​=0.693​/k

 

It will require 2 half times for the concentration of A to become .0.25M.

∴ Time taken= 2×t1/2 sec

​=2×300

=600sec

R.C. Mukherjee Test: Chemical Kinetics - Question 4

Consider the following first order competing reactions :

 A+ B      and y  C+D

if 50% of the reaction of X was completed when 96% of the reaction of Y was completed, the ratio of their rate constants   is

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 4


R.C. Mukherjee Test: Chemical Kinetics - Question 5

Units of rate constant for first and zero order reactions in terms of molarity (M) are respectively.

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 5

sec–1, Msec–1

R.C. Mukherjee Test: Chemical Kinetics - Question 6

The rate of a chemical reaction doubles for every 10°C rise of temperature. If the temperature is raised by 50°C, the rate of the reaction increases by about

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 6

For every 10°C rise of temperature, the rate is doubled. Thus, the temperature coefficient of the reaction = 2
When temperature is increased by 50°, rate becomes
=2(50/10) = 25 times = 32 times

R.C. Mukherjee Test: Chemical Kinetics - Question 7

For a reaction pA + qB → products, the rate law expression is r = k[A]l[B]m, then :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 7

pA + qB  → Products r = k[A]l[B]m
(p + q) may or may not be equal to (l + m) (order may or may not be equal to stoichiometric coefficient for a complex reaction.

R.C. Mukherjee Test: Chemical Kinetics - Question 8

In the reaction : A + 2B → 3C + D, which of the following expression does not describe changes in the conc. of various species as a function of time :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 8

R.C. Mukherjee Test: Chemical Kinetics - Question 9

 A first order reaction is 87.5% complete in an hour. The rate constant of the reaction is

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 9

The correct answer is Option A.
     KT  =   ln (a0 / at)
⇒ K*60 = ln (a0 / at
87.5 % completed in 1 hour.
Therefore, at = a0 - 0.875 a0
                    at = 0.125 a0
     K * 60 = ln (a0 / 0.125 a0)
⇒ K * 60 = ln 8
⇒ K = 2.079 / 60
⇒ K = 0.0346 min-1

R.C. Mukherjee Test: Chemical Kinetics - Question 10

Half-life period of a second order reaction is

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 10

The correct answer is Option B.
 
Relation between half-life period of a reaction and initial concentration is as follows: 
For first order reaction         (Half life α a0 )
For second order reaction    (Half life ∝ 
1/a)
For third order reaction         (Half life ∝ 1a2)

R.C. Mukherjee Test: Chemical Kinetics - Question 11

A first order reaction is 50% completed in 20 minutes at 27°C and in 5 min at 47°C. The energy of activation of the reaction is

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 11

t1/2 = 20 min at 300 K
t’1/2 = 5 min at 320 K



On solving, Ea = 55303.12 J
= 55.3 KJ

R.C. Mukherjee Test: Chemical Kinetics - Question 12

For the first order reaction A → B + C, carried out at 27°C if 3.8 × 10-16% of the reactant molecules exists in the activated state, the Ea (activation energy) of the reaction is

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 12

A → B + C

Ea = 100 KJ/mol

R.C. Mukherjee Test: Chemical Kinetics - Question 13

The rate constant, the activation energy and the Arrhenius parameter (A) of a chemical reaction at 25°C are 3.0 × 10-4 s-1, 104.4 kJ mol-1 and 6.0 × 10-4s-1respectively. The value of the rate constant at T → ∞ is

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 13

At temperature = ∞
Rate constant = Arrhenious constant.

R.C. Mukherjee Test: Chemical Kinetics - Question 14

The following mechanism has been proposed for the exothermic catalyzed complex reaction.

If k1 is much smaller than k2. The most suitable qualitative plot of potential energy (P.E.) versus  reaction coordinate for the above reaction.

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 14


Since
K1 <<< K2 = most Imp. peack will be higher

R.C. Mukherjee Test: Chemical Kinetics - Question 15

The activation energy of a reaction at a given temperature is found to be 2.303 RT J mol–1. The ratio of rate constant to the Arrhenius factor is

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 15

The correct answer is option A
Arrhenius equation is,
rate constant, k=Ae−Ea​/RT
k=Ae−2.303RT/RT ⇒ k/A = e-2.303
On solving, we get
k/A = 10-1 or 0.1

R.C. Mukherjee Test: Chemical Kinetics - Question 16

Consider  + heat, If activation energy for forward reaction is 100 kJ/mole then activation energy for backward reaction and heat of reaction is :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 16


Eaf = 100 KJ/mol
Eab = ? heat of reaction  = ?

Only one option because
Eb = Ea + ΔH.O. reaction

R.C. Mukherjee Test: Chemical Kinetics - Question 17

In a reaction, the thershold energy is equal to :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 17

In a reaction, the threshold energy is equal to : Activation energy + Normal energy of reactants.

R.C. Mukherjee Test: Chemical Kinetics - Question 18

The first order rate constant k is related to temperature as log k = 15.0 - (106/T). Which of the following pair of value is correct ?

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 18


log A = 15
⇒ A = 1015

Ea = 1.9 × 104  KJ

R.C. Mukherjee Test: Chemical Kinetics - Question 19

When a graph between log K and 1/T is drawn a straight line is obtained. The temperature at which line cuts y-axis and x-axis.

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 19


When line cuts y axis

When it cut  X -axis
log K = 0

R.C. Mukherjee Test: Chemical Kinetics - Question 20

The rate constant, the activation energy and the frequency factor of a chemical reaction at 25°C are 3.0 × 10-2 s-1, 104.4 KJ mol-1 and 6.0 × 1014 s-1 respectively. The value of the rate constant as T → ∞ is :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 20

K = 3 × 10–2 s–1
Ea = 104.4 KJ/mol
A = 6 × 1014
Value of rate constant at T = ∞ will be equal to frequency factor  i.e. A = 6 × 1014 s-1

R.C. Mukherjee Test: Chemical Kinetics - Question 21

The rate data for the net reaction at 25°C for the reaction X + 2Y → 3Z are given below :

[X0]   [Y0]   Time required for [Z] to increase by 0.005 mol per litre.

0.01   0.01   72 sec

0.02   0.005  36 sec

0.02   0.01    18 sec

The intial rate (as given by Z) is :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 21


Since,
Rate becomes four times by doubling the concentration of A
⇒ Order w.r.t  A is 2
Also,
by doubling the concentration of B, the rate becomes double
⇒ Order w.r.t. B is 1.

R.C. Mukherjee Test: Chemical Kinetics - Question 22

The rate of production of NH3 in N2 + 3H2 → 2NH3 is 3.4 kg min-1. The rate of consumption of H2 is :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 22


= 5.1 Kgmin-1

R.C. Mukherjee Test: Chemical Kinetics - Question 23

For a given reaction of first order it takes 20 min. for the conc. to drop from 1.0 M to 0.60 M. The time required for the conc. to drop from 0.60 M to 0.36 M will be :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 23


Also,

Since, Rate constant will be equal

On solving, t = 20 min

R.C. Mukherjee Test: Chemical Kinetics - Question 24

For a first order reaction, the concentration of reactant :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 24

For a first order reaction, the concentration of the reactant varies exponentially with time (A = A0e–kt)

R.C. Mukherjee Test: Chemical Kinetics - Question 25

Radioactivity of a sample (z = 22) decreases 90% after 10 years. What will be the half-life of the sample?

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 25

Reaction is or zero order hence, Option C will be correct.

R.C. Mukherjee Test: Chemical Kinetics - Question 26

Mathematical representation for t1/4 life for first order reaction is over is given by :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 26

t1/4 = time taken for   decomposition.

R.C. Mukherjee Test: Chemical Kinetics - Question 27

For a reaction A → Products, the conc. of reactant C0, aC0, a2C0, a3C0............ after time interval 0, t, 2t ............ where 'a' is constant. Then :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 27

If we calculate K, it comes constant every time i.e. reaction is of first order.

R.C. Mukherjee Test: Chemical Kinetics - Question 28

 Half-life is independent of conc. of A. After 10 minutes volume N2 gas is 10 L and after complete reaction 50 L. Hence rate constant in min-1 :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 28


Half life is independent of concentration
⇒ reaction is of first order


R.C. Mukherjee Test: Chemical Kinetics - Question 29

In a zero-order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10°C to 100°C, the rate of the reaction will become 

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 29

For rise in temperature, n=1
Therefore rate = 2n
= 21
= 2
When temperature is increased from 10o C to 100oC    
change in temperature = 100 − 10 = 90o
therefore n=9 therefore, rate = 29
= 512 times.

R.C. Mukherjee Test: Chemical Kinetics - Question 30

In acidic medium the rate of reaction between (BrO3)- & Br- ions is given by the expression, –[d(BrO3-) /dt] = K[BrO3-][Br-][H +]It means :

Detailed Solution for R.C. Mukherjee Test: Chemical Kinetics - Question 30


D option is correct.

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