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30 Questions MCQ Test - Full Test 1 - EKT EEE

Full Test 1 - EKT EEE for AFCAT 2024 is part of AFCAT preparation. The Full Test 1 - EKT EEE questions and answers have been prepared according to the AFCAT exam syllabus.The Full Test 1 - EKT EEE MCQs are made for AFCAT 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Full Test 1 - EKT EEE below.
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Full Test 1 - EKT EEE - Question 1

If f(x) = x + |x2 - 8| then the derivative of f(x) at x = 3 is

Detailed Solution for Full Test 1 - EKT EEE - Question 1

For x = 3, (x2 – 8) > 0 so |x2 - 8| = x2 – 8

f(x) = x + (x2 – 8)

f’(x) = 1 + 2x

f’(3) = 1 + 2(3) = 7

Full Test 1 - EKT EEE - Question 2

Given P(A) = 1/4, P(B) = 1/3 and P(AUB) = 1/2. Value of P(A/B) is

Detailed Solution for Full Test 1 - EKT EEE - Question 2

Conditional probability P(A/B): 

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Full Test 1 - EKT EEE - Question 3

The angle between two vectors a = i + 2j – k and b = 2i + j + k is

Detailed Solution for Full Test 1 - EKT EEE - Question 3

Angle between two vectors:

θ = 60°

Full Test 1 - EKT EEE - Question 4

The order and degree of the differential equation 

Detailed Solution for Full Test 1 - EKT EEE - Question 4

Order of a differential equation is defined as the order of the highest order derivative and the degree of a differential equation, when it is a polynomial equation in derivatives, is defined as the highest power (positive integral index) of the highest order derivative.

The highest order derivative present in the given differential equation is  so it’s order is two. It is a polynomial equation in  the highest power raised to  is one, so its degree is one.

Full Test 1 - EKT EEE - Question 5

The rank of the matrix  is

Detailed Solution for Full Test 1 - EKT EEE - Question 5

Doing row operation on the given matrix, we get

 

Since the number of non-zero rows is one,

∴ ρ(A) = 1

Full Test 1 - EKT EEE - Question 6

Lorentz force is given by

Detailed Solution for Full Test 1 - EKT EEE - Question 6

Lorentz force is the combination of electric force  and magnetic force  Thus the Lorentz force is given by  

Full Test 1 - EKT EEE - Question 7

The sum of kinetic and potential energy of a falling body _____.

Detailed Solution for Full Test 1 - EKT EEE - Question 7

Kinetic energyrepresents energy the mass possesses by virtue of its motion. Likewise, potential energy (PE=mgh) represents energy the mass possesses by virtue of its position.
E=KE+PE
E is the total energy of the mass: i.e., the sum of its kinetic and potential energies. It is clear that E is a conserved quantity: i.e., although the kinetic and potential energies of the mass vary as it falls, its total energy remains the same and one form of energy is being converted into other form of energy.

Full Test 1 - EKT EEE - Question 8

A Farad is defined as

Detailed Solution for Full Test 1 - EKT EEE - Question 8

1 farad = 1 coulomb/volt
One farad is defined as the capacitance of a capacitor which requires a charge of one coulomb to establish a potential difference of one volt between its plates.

Full Test 1 - EKT EEE - Question 9

Process of emission of electrons from hot metal surface is called

Detailed Solution for Full Test 1 - EKT EEE - Question 9

The process of electron emission from a metal surface by supplying thermal energy to it is known as thermionic emission.

The factors on which it depends are:

(i) the nature of the metal

(ii) the temperature of the surface of the metal.

Full Test 1 - EKT EEE - Question 10

The strength of the magnetic field due to a long straight conductor is

Detailed Solution for Full Test 1 - EKT EEE - Question 10

The Magnetic field due to a long straight conductor is given as  where r is the distance from the conductor.

Full Test 1 - EKT EEE - Question 11

Which of the following represents a damped oscillation?

Detailed Solution for Full Test 1 - EKT EEE - Question 11

For a damped oscillation, we need a decaying exponential multiplied with a sinusoid. Only  y=ae−αtcos(ωt+α)satisfies that criteria.

Full Test 1 - EKT EEE - Question 12

A quadrilateral whose opposite sides are equal and parallel, but angles are not right angle is known as:

Detailed Solution for Full Test 1 - EKT EEE - Question 12

Full Test 1 - EKT EEE - Question 13

Consider the following statements

i) Astable Multivibrator can be used for generating a square wave

ii) Bistable Multivibrator can be used for storing binary information

Detailed Solution for Full Test 1 - EKT EEE - Question 13

Astable Multivibrator shifts between two states thereby generating a square wave. In Bistable Multivibrator, a trigger pulse is needed for change from one stable state to another stable state (from 0 to 1 and 1 to 0) hence can be used to state binary data.

Full Test 1 - EKT EEE - Question 14

A working diode must have

Detailed Solution for Full Test 1 - EKT EEE - Question 14

A working diode means the diode is biased or connected with the DC source. When a diode is forward biased (+ve terminal to anode and -ve terminal to cathode), it provides a low resistance path because it helps the majority carrier to crossover the barrier potential and conduct the flow of current. When a diode is reversed biased (-ve terminal to anode and +ve terminal to cathode) it provide a high resistance path because the majority carriers are flows away from the junction and no current conduction takes place.

Full Test 1 - EKT EEE - Question 15

In experimentally obtaining the frequency response curve of an amplifier

Detailed Solution for Full Test 1 - EKT EEE - Question 15

The Frequency Response of an amplifier is presented in a form of a graph that shows output amplitude (or, more often, voltage gain) plotted versus frequency. Typical plot of the voltage gain of an amplifier versus frequency. The gain is null at zero frequency, then rises as frequency increases, level off for further increases in frequency, and then begins to drop again at high frequencies. The frequency response of an amplifier can be divided into three frequency regions.

The frequency response begins with the lower frequency region designated between 0 Hz and lower cut off frequency. At lower cutoff frequency fL, the gain is equal to 0.707 Amid. Amid is a constant midband gain obtained from the midband frequency region. The third, the upper frequency region covers frequency between upper cutoff frequency and above. Similarly, at upper cutoff frequency, fH, the gain is equal to 0.707 Amid. After the upper cutoff frequency, the gain decreases with frequency increases and dies off eventually.

Full Test 1 - EKT EEE - Question 16

Frequency distortion in an amplifier is caused by

Detailed Solution for Full Test 1 - EKT EEE - Question 16

Harmonic distortion in amplifiers is usually caused by the amplifier needing more voltage than its power supply can provide. It can also be caused by some part of the internal circuit (usually the output transistors) exceeding its output capacity

Full Test 1 - EKT EEE - Question 17

In the circuit below, Vo is (in V)

Detailed Solution for Full Test 1 - EKT EEE - Question 17

In positive feedback op-Amp acts in its saturation region

Full Test 1 - EKT EEE - Question 18

The feedback factor of a Wien bridge oscillator using Op-Amp is

Detailed Solution for Full Test 1 - EKT EEE - Question 18

At the resonant frequency, the feedback factor (R2/R1) of a Wien bridge oscillator using Op-Amp, is 1/2. Hence, the amplifier gain must be greater than 2 to maintain sustained oscillations.

Full Test 1 - EKT EEE - Question 19

Which family of logic circuits uses field effect transistors?

Detailed Solution for Full Test 1 - EKT EEE - Question 19

CMOS uses field effect transistors. It is a technology for constructing integrated circuits. CMOS technology is used in microprocessors, microcontrollers, static RAM, and other digital logic circuits.

Full Test 1 - EKT EEE - Question 20

Which of the following hexadecimal numbers represents an odd decimal number?

Detailed Solution for Full Test 1 - EKT EEE - Question 20

FF is a hexadecimal number which has value 255 in decimal which is an odd number.

Full Test 1 - EKT EEE - Question 21

BCD equivalent of Gray code number 1001 is

Detailed Solution for Full Test 1 - EKT EEE - Question 21

If G0G1G2G3 is a gray code number then the BCD equivalent number B0B1B2B3 can be estimated using:

B3 = G3

B2 = B3 ⊕ G2

B1 = B2 ⊕ G1

B0 = B1 ⊕ G0

So, using the above rules, the BCD equivalent of gray code number 1001 is 1110

Full Test 1 - EKT EEE - Question 22

Binary 1000 when multiplied by binary 1111 results in binary

Detailed Solution for Full Test 1 - EKT EEE - Question 22

In binary multiplication, we only need to remember the following rules:

0 x 0 = 0

0 x 1 = 0

1 x 0 = 0

1 x 1 = 1

So, by using above rules when we will multiply binary 1000 with binary 1111 we will get binary 11110000 as the product.

Full Test 1 - EKT EEE - Question 23

When load on a normally excited synchronous motor is increased, its power factor tends to

Detailed Solution for Full Test 1 - EKT EEE - Question 23

In normal excitation, if load is increased the change in current is greater than the change in power factor and the power factor tends to become increasingly lagging.

Full Test 1 - EKT EEE - Question 24

A large series motor is never started without some load on it, otherwise

Detailed Solution for Full Test 1 - EKT EEE - Question 24

In case of DC series motor, field generated depends on armature current. At no load, current drawn is very less hence the field generated is less. Since the back emf remains constant hence speed is inversely proportional to the flux. Thus the initial speed will get very high and the motor may get damaged at no load.

Full Test 1 - EKT EEE - Question 25

Transformer oil used in transformer provides

Detailed Solution for Full Test 1 - EKT EEE - Question 25

Transformer oil is a highly refined mineral oil that is stable at high temperatures and has excellent electrical insulating properties. It is used in oil-filled transformers. Its function is to provide insulation and cooling.

Full Test 1 - EKT EEE - Question 26

Equalizer rings can be used by

Detailed Solution for Full Test 1 - EKT EEE - Question 26

Equalizer rings are used in lap wounded armatures only to remove any circulating currents in parallel paths.

Full Test 1 - EKT EEE - Question 27

Shunt reactors are connected with transmission lines for

Detailed Solution for Full Test 1 - EKT EEE - Question 27

A shunt reactor is connected in parallel with a transmission line or other load. They are used in transmission systems to counteract the effect of line parasitic capacitance. Thus they deal with the reactive component.

Full Test 1 - EKT EEE - Question 28

Which of the following method of biasing provides the best operating point stability

Detailed Solution for Full Test 1 - EKT EEE - Question 28

Self-bias are emitter biased circuit. Generates it's own DC bias voltage .For the emitter which has a considerable effect, on the base current .Any circuit which does generate such bias voltage without actually directly depending on an explicit power supply is a self-bias.

Full Test 1 - EKT EEE - Question 29

Conduction electrons have more mobility than holes because they

Detailed Solution for Full Test 1 - EKT EEE - Question 29

The mobility of electrons is more than that of holes because the probability of an electron having the energy required to move to an empty state in the conduction band is much greater than the probability of an electron having the energy required to move to the empty state in valance band. The mobility of hole is about half that of electrons.

Full Test 1 - EKT EEE - Question 30

Forbidden energy gap between valence band and conduction band is least in the case of _____.

Detailed Solution for Full Test 1 - EKT EEE - Question 30

Forbidden energy gap between valence band and conduction band is least in the case of impure silicon.

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