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Central Forces MCQ Level – 1 - IIT JAM MCQ


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10 Questions MCQ Test - Central Forces MCQ Level – 1

Central Forces MCQ Level – 1 for IIT JAM 2024 is part of IIT JAM preparation. The Central Forces MCQ Level – 1 questions and answers have been prepared according to the IIT JAM exam syllabus.The Central Forces MCQ Level – 1 MCQs are made for IIT JAM 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Central Forces MCQ Level – 1 below.
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Central Forces MCQ Level – 1 - Question 1

A point mass m is placed inside a spherical shell of radius R and mass M at a distance R / 2 form the centre of the shell. The gravitational force exerted by the shell on the point mass is

Detailed Solution for Central Forces MCQ Level – 1 - Question 1

If a point mass is placed inside a uniform spherical shell, the gravitational force on the point mass is zero. Hence, the gravitational force exerted by the shell on the point mass is zero.

Central Forces MCQ Level – 1 - Question 2

With what angular velocity the earth should spin in order that a body lying at 37° latitude may become weightless.

Detailed Solution for Central Forces MCQ Level – 1 - Question 2

Due to effect of rotation of earth

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Central Forces MCQ Level – 1 - Question 3

A planet revolving around sun in an elliptical orbit has a constant :

Detailed Solution for Central Forces MCQ Level – 1 - Question 3

In elliptical orbit sun is at one of the foci hence the distance between the planet and sun changes as planet revolves hence linear speed, kinetic energy and potential energy of planet do not remain constant.
Angular momentum about the sun remains constant.

The correct answer is: angular momentum about the sun

Central Forces MCQ Level – 1 - Question 4

A tunnel is dug along the diameter of the earth (Radius R and mass M). There is particle of mass m  at the centre of the tunnel. Find the minimum velocity given to the particle so that it just reaches to the surface of the earth :

Detailed Solution for Central Forces MCQ Level – 1 - Question 4

Let the minimum speed imparted to the particle of mass  m  so that it just reaches surface of earth is  v.
Applying conservation of energy

Solving we get 
The correct answer is: 

Central Forces MCQ Level – 1 - Question 5

A satellite of mass m revolves around the earth of radius R at a height  x from its surface. If is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is :

Detailed Solution for Central Forces MCQ Level – 1 - Question 5

The correct answer is: 

Central Forces MCQ Level – 1 - Question 6

Which of the following graph represents the time period of the planet moving around the sun. [R = semi major axis of the path]

Detailed Solution for Central Forces MCQ Level – 1 - Question 6

T2 ∝ R3

The correct answer is: 

Central Forces MCQ Level – 1 - Question 7

At what height above the earth’s surface does the acceleration due to gravity fall to 1% of its value at the earth’s surface?

Detailed Solution for Central Forces MCQ Level – 1 - Question 7

Acceleration due to gravity at a height h from earth surface 

⇒ h = 9 R
The correct answer is: 9R

Central Forces MCQ Level – 1 - Question 8

Two particles, each of mass M move around in a circle of radius R under the action of their mutual gravitational attraction. The speed of each particle is

Detailed Solution for Central Forces MCQ Level – 1 - Question 8



⇒ 
The correct answer is: 

Central Forces MCQ Level – 1 - Question 9

A geostationary satellite is one :

Detailed Solution for Central Forces MCQ Level – 1 - Question 9

A geostationary satellite has time period  same as that of earth.

The correct answer is: whose time period is same as that of earth

Central Forces MCQ Level – 1 - Question 10

Three particles each of mass m are kept at vertices of an equilateral triangle of side L. The gravitational field at centre due to these particles is :

Detailed Solution for Central Forces MCQ Level – 1 - Question 10

Let us put a test mass mat the center. Forces acting on it are 


These forces are of equal magnitude and act at 120° with each other .
Hence, 

∴ Fg = 0
The correct answer is: 0

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