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Work, Power And Energy MSQ - Physics MCQ


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10 Questions MCQ Test - Work, Power And Energy MSQ

Work, Power And Energy MSQ for Physics 2024 is part of Physics preparation. The Work, Power And Energy MSQ questions and answers have been prepared according to the Physics exam syllabus.The Work, Power And Energy MSQ MCQs are made for Physics 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Work, Power And Energy MSQ below.
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*Multiple options can be correct
Work, Power And Energy MSQ - Question 1
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One end of an unstretched vertical spring is attached to the ceiling and an object attached to the other end is slowly lowered to its equilibrium position. If S be gain in spring energy and G be loss in gravitational potential energy in the process, then which of the following is false.

Detailed Solution for Work, Power And Energy MSQ - Question 1

 (loss in gravitationl potential energy)
⇒ G = 2S
The correct answers are: S = G, S = 2G, S = 3G

*Multiple options can be correct
Work, Power And Energy MSQ - Question 2
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A block of mass 2kg is hanging over a smooth and light pulley through a light string. The other end of the string is pulled by a constant force F = 40N. The kinetic energy of the particle increase 40J in a given interval of time. Then : (g = 10m/s2)

Detailed Solution for Work, Power And Energy MSQ - Question 2

Free body diagram of block is as shown in figure.
From work-energy theorem

Work done by gravity is 

and work done by tension is

The correct answers are: tension in the string is 40N, displacement of the block in the given interval of time is 2m, work done by tension is 80J

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Work, Power And Energy MSQ - Question 3
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For a particle moving on a straight line the variation of acceleration with time is given by the graph as shown initially the particle was at rest. Then the corresponding kinetic energy of the particle versus time graph will be :

Detailed Solution for Work, Power And Energy MSQ - Question 3

The above graphs show v-t graph from a-t graph and then v2-t graph, which are self explanatory.

The correct answer is: D

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Work, Power And Energy MSQ - Question 4
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The potential energy for a force field is given by U(x, y) = cos(x + y). The force is acting on a particle at position given by coordinates  then which of the following statement is true.
Detailed Solution for Work, Power And Energy MSQ - Question 4

The correct answers are: 

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Work, Power And Energy MSQ - Question 5
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There are two massless springs A and B of spring constant KA and KB respectively and KA > KB. If WA and WB be denoted as work done on A and work done on B respectively, then :
Detailed Solution for Work, Power And Energy MSQ - Question 5

If the springs are compressed to same amount :

If the springs are compressed by same force.

The correct answers are: If they are compressed to same distance, WA > WB, If they are compressed by same force (upto equilibrium state) WA < WB

*Multiple options can be correct
Work, Power And Energy MSQ - Question 6
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Which of the following is/are conservative force(s)?
Detailed Solution for Work, Power And Energy MSQ - Question 6

Clearly for forces  the integration do not require any information of the path taken.


Taking : x2 + y2 = t
2xdx + 2ydy = dt

which is solvable.

Hence  are conservative forces.

But 
requires some more information on path. Hence non-conservative.
The correct answers are: 

*Multiple options can be correct
Work, Power And Energy MSQ - Question 7
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The potential energy (in Joules) of a particle of mass 1kg moving in a plane is given by V = 3x + 4y, the position coordinates of the point being x and y, measured in metres. If the particle is at rest at (6,4); then 
Detailed Solution for Work, Power And Energy MSQ - Question 7

Let at time 't' particle crosses y-axis


⇒ Particle crosses y-axis at y = –4
At (6, 4) U = 34 & KE = 0
At (0, 4); U = –16
⇒ KE = 50


⇒ v = 10 m/s  while crossing y-axis
The correct answers are: its acceleration is of magnitude 5m/s2, its speed when it crosses the y-axis is 10m/s, it crosses the y-axis (x = 0) at y = –4

*Multiple options can be correct
Work, Power And Energy MSQ - Question 8
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In the figure shown the potential energy U of a particle is plotted against its position x  from origin. Then which of the following statement is incorrect.
Detailed Solution for Work, Power And Energy MSQ - Question 8

x = x1 and x = x3 are not equilibrium positions because du/dx ≠  0 at these points.  x = x2 is unstable, as U is maximum at this point.

 

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Work, Power And Energy MSQ - Question 9
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Work done by a force on an rigid object having no rotational motion will be zero, if :
Detailed Solution for Work, Power And Energy MSQ - Question 9

(a) If velocity and acceleration are not in same direction, work done by force perpendicular to acceleration will not be zero.
(b) If the object is at rest no force can do work
(c) If force is perpendicular to velocity work done will be zero
(d) If the point on the body has velocity component in direction of application of force work done will be non-zero.

The correct answers are: the object is at rest relative to ground but the point of application of force moves on the object, the force is always perpendicular to velocity of object

*Multiple options can be correct
Work, Power And Energy MSQ - Question 10
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An engine can pull 4 coaches at a maximum speed of 20m/s. Mass of the engine is twice the mass of every coach. Assuming resistive force to be proportional to the weight. (Power of engine remains constant) :
Detailed Solution for Work, Power And Energy MSQ - Question 10

When 4 coaches (m each) are attached with engine (2m)
according to questions P = K 6mgv    ...(1)
(constant power), (K being proportionality constant)
Since resistive force is proportional to weight
Now if 12 coaches are attached

   ...(2)

Since engine power is constant
So by equation (1) and (2)

Similarly for 6 coaches

The correct answers are: maximum speed of engine when it pulls 12 coaches is 8.5m/s, maximum speed of engine when it pulls 6 coaches is 15m/s

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