IIT JAM Exam  >  IIT JAM Tests  >  Centre Of Mass MCQ Level - 2 - IIT JAM MCQ

Centre Of Mass MCQ Level - 2 - IIT JAM MCQ


Test Description

10 Questions MCQ Test - Centre Of Mass MCQ Level - 2

Centre Of Mass MCQ Level - 2 for IIT JAM 2024 is part of IIT JAM preparation. The Centre Of Mass MCQ Level - 2 questions and answers have been prepared according to the IIT JAM exam syllabus.The Centre Of Mass MCQ Level - 2 MCQs are made for IIT JAM 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Centre Of Mass MCQ Level - 2 below.
Solutions of Centre Of Mass MCQ Level - 2 questions in English are available as part of our course for IIT JAM & Centre Of Mass MCQ Level - 2 solutions in Hindi for IIT JAM course. Download more important topics, notes, lectures and mock test series for IIT JAM Exam by signing up for free. Attempt Centre Of Mass MCQ Level - 2 | 10 questions in 45 minutes | Mock test for IIT JAM preparation | Free important questions MCQ to study for IIT JAM Exam | Download free PDF with solutions
Centre Of Mass MCQ Level - 2 - Question 1

A particle of mass m is moving along the x-axis with speed v when it collides with a particle of mass 2m initially at rest. After the collision, the first particle has come to rest and the second particle has split into two equal-mass pieces that are shown in the figure. Which of the following statements correctly describes the speeds of the two pieces? (θ > 0)

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 1

After collision by momentum conservation :

Along y-axis

Along x-axis

The correct answer is: Each piece moves with speed greater than v/2.

Centre Of Mass MCQ Level - 2 - Question 2

A system of the blocks A and B are connected by an inextensible massless string as shown in the figure. The pulley is massless and frictionless. Initially the system is at rest when, a bullet of mass m moving with a velocity u hits the block B and gets embedded into it. The impulse imparted by tension force to the block of mass 3m is :

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 2

By conservation of linear momentum along the string.
mu = (m + m + 3m)v
or v = u/5

and impulse on the block 

The correct answer is: 

1 Crore+ students have signed up on EduRev. Have you? Download the App
Centre Of Mass MCQ Level - 2 - Question 3

A smooth ball A moving with velocity v collides with another smooth identical ball at rest. After collision both the balls move with same speed with angle between their velocities 60°. No external force acts on the system of balls. The speed of each ball after collision is :

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 3

From conservation of momentum

Centre Of Mass MCQ Level - 2 - Question 4

A canon shell moving along a straight line burst into two parts. Just after the burst one part moves with momentum 20 Ns making an angle 30° with the original line of motion. The minimum momentum of the other parts of shell just after the burst is :

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 4

P1 = 20  Ns

Let the minimum momentum of  other part be  P2

Applying conservation of momentum in y direction :

P1sin30= P2​sinθ

20×1/2 ​= P2​sinθ

⟹P2​sinθ = 10 N s

Now for P2 to be minimum, sinθ must be maximum   i.e  sinθ=1

⟹ P​= 10  N s

Centre Of Mass MCQ Level - 2 - Question 5

On a smooth carom board, a coin moving in negative y-direction with a speed of 3m/s is being hit at the point (4,6) by a striker moving along negative x-axis. The line joining centres of the coin and the striker just before the collision is parallel to x-axis. After collision the coin goes into the hole located at the origin. Masses of the striker and the coin are equal. Considering the collision to be elastic, the initial and final speeds of the striker in m/s will be:

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 5

The line of impact for duration of collision is parallel to x-axis.

The situation of striker and coin just before the collision is given as

Because masses of coin and striker are same, their components of velocities along line of impact shall exchange. Hence the striker comes to rest and the x-y component of velocities of coin are u and 3m/s as shown in figure.

For coin to enter hole,

its velocity must be along PO


or u = 2m/s
The correct answer is: (2, 0)

Centre Of Mass MCQ Level - 2 - Question 6

In given figure, the small block of mass 2m is released from rest when the string is in horizontal position,

Displacement of the ring when string makes an angle θ = 37° with the vertical will be :

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 6

Taking 'O' as the origin;

Centre Of Mass MCQ Level - 2 - Question 7

A train of mass M is moving on a circular track of radius R with constant speed V. The length of the train is half of the perimeter of the track. The linear momentum of the train will be :

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 7

If we treat the train as a ring of mass M then its centre of mass will be at a distance

2R/π from the centre of the circle. Velocity of centre of mass is :

As the linear momentum of the system = MVCM

∴ The linear momentum of the train = 

The correct answer is: 

Centre Of Mass MCQ Level - 2 - Question 8

The figure shows a hollow cube of side a of volume V. There is a small chamber of volume V/4 in the cube as shown. This chamber is completely filled by m kg of water. Water leaks through a hole H. The the work done by gravity in this process assuming that the complete water finally lies at the bottom of the cube is :

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 8

Let h be the height of water surface, finally

∴ C.M. gets lowered by 

Centre Of Mass MCQ Level - 2 - Question 9

AB is and L shaped object fixed on a horizontal smooth table. A ball strikes if at A, gets deflected and restrikes it at B. If the velocity vector before collision is and coefficient of restitution of each collision is ‘e’, then the velocity of ball after its second collision at B is :

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 9

During 1st collision perpendicular component of  becomes e times, while IInd component v|| remains unchanged and similarly for second collision. The end result is that both v|| and  becomes e times their initial value and hence  (the (–) sign indicates the reversal of direction).

The correct answer is: 

Centre Of Mass MCQ Level - 2 - Question 10

A gun is firing 20 balls per seconds of mass 20 gm each on the smooth horizontal table surface ABCD. If the collision is perfectly elastic and balls are striking at the centre of table with a speed 5 m/sec at an angle of 60° with the vertical just before collision, then force exerted by one of the leg on ground is (assume total weight of the table is 0.2 kg and g = 10 m/s2) :

Detailed Solution for Centre Of Mass MCQ Level - 2 - Question 10

Force on table due to collision of balls :

Net force one leg 

The correct answer is: 1 N

Information about Centre Of Mass MCQ Level - 2 Page
In this test you can find the Exam questions for Centre Of Mass MCQ Level - 2 solved & explained in the simplest way possible. Besides giving Questions and answers for Centre Of Mass MCQ Level - 2, EduRev gives you an ample number of Online tests for practice
Download as PDF