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Bipolar Junction Transistor NAT Level -1 - Physics MCQ

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10 Questions MCQ Test - Bipolar Junction Transistor NAT Level -1

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*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 1

For a transistor circuit, V_CE when V_in = 0V (in volts).

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 1

When V_in = 0V, the transistor is in cut-off (acts like an open switch) and V_CE =V_{CC =}10V.
The correct answer is: 10

*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 2

For a BJT, the current amplification factor ∝ = 0.9 . This transistor is connected in common emitter configurations. When the base current changes by 0.4 mA, the change in collector current will be (in mA).

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 2

The correct answer is: 3.6

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*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 3

A power amplifier gives 150 W output of or an input of 1.5W. The gain in dB is :

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 3

= 40 dB
The correct answer is: 40

*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 4

What is the current gain for a common-base configuration where I_E = 4.2 mA and I_C = 4.0 mA?

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 4

Ie = 4.2ma (Given)

Ic = 4.0ma (Given)

The question follows the common base configuration in the circuit configuration of a bipolar transistor, where the emitter is the input electrode, collector is the output electrode and the base is reference electrode for both input and the output.

Thus,

Current gain = Ic / Ie =I(out)/I(in)

where, IC=Output Current and IE = Input Current

= 4 / 4.2

= 0.95

Therefore, the current gain for a common-base configuration is 0.95

*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 5

Figure shows a common emitter amplifier with β = 100. What is the maximum peak to peak input signal (in mV) for which distortion free output may be obtained Assume V_BE = 0 r_E= 20 Ω

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 5

But for maximum peak to peak input signal

The correct answer is: 80

*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 6

In the following circuit, Tr₁ and Tr₂ are identical transistors having V_BE = 0.7V. The current passing through the transistor Tr₂ is (in mA).

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 6

Applying KVL,
5=100x1 + 0.7

The correct answer is: 43

*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 7

If the transistor amplifier has a gain of 20dB, then the ratio of output to input power is :

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 7

The ratio of output to input power is known as power amplification.

The logarithm of the power amplification is represented in bel.

he correct answer is: 100

*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 8

A common emitter amplifier has voltage gain of 50, an input impedance of 1000Ω and an output impedance of 200Ω. The power gain of the amplifier will be (in dB).

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 8

Power gain = Voltage gain x current gain

The correct answer is: 250

*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 9

The input signal given to a common emitter amplifier having a voltage gain of 20 is V_in = 20 cos (5t + 20°). The corresponding output signal has an amplitude equal to ?

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 9

The correct answer is: 400

*Answer can only contain numeric values

Bipolar Junction Transistor NAT Level -1 - Question 10

The feedback ratio of an amplifier, which an amplification of a negative feedback, changes the voltage gain the voltage gain from - 250 to - 100 is (give magnitude only).

Detailed Solution for Bipolar Junction Transistor NAT Level -1 - Question 10

The correct answer is: 0.006

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