Application Of Schrodinger Equation MCQ - Physics MCQ

The correct answer is: 1/2

Correct Answer :- d

Explanation : φ = A cos nπx/L

x = φxφ dx

= A² ∫(0 to L) xcos² nπx/L dx

= A² ∫(0 to L) x/2(cos² nπx/L - 1) dx

= (A²)/2 ∫(0 to L) xcos² nπx/L dx

= 0

p = d/dt (x)

= 0

Out of all the given options, sin x is the only function, that is continuous and single-valued. All the rest of the functions are either discontinuous or double-valued.

The correct answer is: Infinite square well which is not symmetric about the y axis, has only odd parity states, whereas the asymmetric potential well has both even & odd parity states

For particle in a box

For ψ₁(x), probability density does not vanish in the middle
for

 

probability density vanishes in the middle

Similarly, it does not vanish for  vanishes for  in the middle of the well.

The correct answer is: states of even n(n = 2, 4...)

The probability distributions for the quantum states of the oscillator without the barrier.

Infinite barrier at the origin means a node at origin, or the wave function goes to zero at x = 0.

By symmetry, the ground state will disappear, as well all the even states.  Odd values remain

The Energy of a wave particle is given as ℏ ω while the momentum of the particle is given as ℏ k. These are the desired relation.

Solving the Schrodinger equation for the region from a to b.

So, in the region from x = a to b, the wave function are in the form of exponential rise/fall.

The correct answer is: ~ 10⁷

The correct answer is: 6 MeV