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Second Law Of Thermodynamics NAT Level - 1 - Physics MCQ

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10 Questions MCQ Test - Second Law Of Thermodynamics NAT Level - 1

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*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 1

Two ends of a rod are kept at 127ºC and 227ºC. When 2000 cal of heat flows in this rod, then change in entropy (in cal/K) is

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 1

ΔS = 20 cal/K
The correct answer is: 20

*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 2

One mole of helium and one mole of oxygen contained in two vessels. If temperature of Helium be 300K, what is the temperature of oxygen in Kelvin

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 2

Entropy of a gas containing N particles is
given as
where m is mass of particle
∴ For the given situation (N = N_a)

∴ m₀T₀ = m_He TH_e
⇒

The correct answer is: 37.5

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*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 3

An engine absorbs heat at temperature of 1000K and rejects heat at 600K. If the engine operates at maximum possible efficiency, the amount of work performed by the amount of work performed by the engine for 200J heat input is (in Joules)

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 3

= 80J
The correct answer is: 80

*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 4

1kg of ice melts at 0ºC into water at the same temperature. The change in entropy is (in cal/K) ____.

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 4

Change in entropy

L = Latent heat of vapourization

The correct answer is: 293

*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 5

A heat pump working on the Carnot cycle maintains the inside temperature of a house at 22ºC by supplying 450 kJ/s. If the outside temperature is 0ºC, the heat taken, in kJ/s, from the outside air is approximately.

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 5

The efficiency of Carnot heat engine may be defined as

Q₁ = 450kJ/s, Q₂ = ?
T₁ = 22 + 273 = 295K
T₂ = 273K
Hence,

= 416.44 kJ/s
The correct answer is: 416.44

*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 6

A reversible engine cycle is shown in the following T-S diagram. The efficiency of the engine (in percentage) is

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 6

Available energy per cycle is

= T₁ S₁
and Q₁ = 3T₁ S₁

The correct answer is: 33.33

*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 7

The efficiency of a heat engine working between heat reservoirs at temperature 327ºC and 27ºC respectively (in percentage) is

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 7

T₁ = 327ºC
= 600 K
T₂ = 27°C
= 300 K

⇒ η = 50%
The correct answer is: 50

*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 8

An amount of heat 1000kJ is transferred from a heat reservoir at temperature T_A to another heat reservoir at temperature T_B . If T_A = 800K and and T_B = 500K, what is the change in entropy ΔS of the combined system in JK^-1

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 8

Conventionally, heat given to the system is taken to be positive and heat extracted from the system is taken to be negative,

ΔS = ΔS_A + ΔS_B
ΔS = 750JK^-1
The correct answer is: 750

*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 9

A Carnot engine operating between 27ºC and 127ºC has efficiency equal to (in percentage).

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 9

⇒ η = 25\%
The correct answer is: 25

*Answer can only contain numeric values

Second Law Of Thermodynamics NAT Level - 1 - Question 10

For a reversible heat engine, the efficiency can be 100% if the temperature of the sink (in K) is

Detailed Solution for Second Law Of Thermodynamics NAT Level - 1 - Question 10

The correct answer is: 0

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