Differential Calculus NAT Level - 2 - IIT JAM MCQ

Differential Calculus NAT Level - 2 - IIT JAM MCQ

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10 Questions MCQ Test - Differential Calculus NAT Level - 2

Differential Calculus NAT Level - 2 for IIT JAM 2024 is part of IIT JAM preparation. The Differential Calculus NAT Level - 2 questions and answers have been prepared according to the IIT JAM exam syllabus.The Differential Calculus NAT Level - 2 MCQs are made for IIT JAM 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Differential Calculus NAT Level - 2 below.
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*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 1

Maximum area of a rectangle which can be inscribed in a circle of given radius R is given by αR2. Find the value of α.

Detailed Solution for Differential Calculus NAT Level - 2 - Question 1

Let rectangle has width b and height h.
Area = h·b
Also,  b2 + h2 = (2R)2 = 4R2

Area is maximum when A2 is maxima
A2 = h2(4R2 – h2)]
f(h) = h2(4R2 – h2)
For maxima,
⇒   = h2(–2h) + (4R2 – h2)2h = 0

h2 + 4R2 – h2 = 0
h2 = 2R2
h = √2

From physical nature of problem, it is clear that this should be maximum area since minimum area will tend towards zero.

Hence, value of α = 2

*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 2

The radius of a right circular cylinder increases at a constant rate. Its altitude is a linear function of the radius and increases three times as fast as radius. When the radius is 1 cm the altitude is 6 cm. When the radius is 6 cm, the volume is increasing at the rate of 1 cm/s. When the radius is 36 cm, the volume is increasing at a rate of n cm3/s. The value of 'n' is equal to :

Detailed Solution for Differential Calculus NAT Level - 2 - Question 2

h = αr + c
α = 3
h = 3r + c
h = 6, r = 1
c = 3

= 33 cm3/second

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*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 3

The maximum value of  is given as (λ/e). The value of  λ is

Detailed Solution for Differential Calculus NAT Level - 2 - Question 3

⇒
For maxima or minima of y.

⇒
and

Hence, y attains maximum value at
The value of λ = 1.

*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 4

Consider the function  If α is the length of interval of decrease and β be the length of interval of increase, then β/α is

Detailed Solution for Differential Calculus NAT Level - 2 - Question 4

f(x) is decreasing in  and increasing in

*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 5

The ratio of absolute maxima and minima of  is

Detailed Solution for Differential Calculus NAT Level - 2 - Question 5

Absolute Maxima = 3
and The Absolute Minima = 1/3

*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 6

If the interval of monotonicity of the function  Find the value of  α?

Detailed Solution for Differential Calculus NAT Level - 2 - Question 6

⇒
⇒
⇒
Hence,    value of α = 1

*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 7

The least area of a circle circumscribing any right triangle of area S is given as απS. Find the value of α.

Detailed Solution for Differential Calculus NAT Level - 2 - Question 7

Area of
S = r2sin θ
⇒
Area of circle =
Least area = πS

So,               Value of α = 1

*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 8

Let  f(x) = 2x3 + ax2 + bx - 3cos2 x is an increasing function for all  x∈R  such that  ma2 + nb + 18 < 0 then the value of m + n + 7 is

Detailed Solution for Differential Calculus NAT Level - 2 - Question 8

Given

D < 0

m = 1, n = – 6
m + n + 7 = 1 – 6 + 7
= 8 – 6 = 2

*Answer can only contain numeric values
Differential Calculus NAT Level - 2 - Question 9

If the maximum value of the function f(x) = (sin-1 x)3 + (cos-1 x)3, -1 << 1 is α and minimum value is β and α - β is of the form n · π3. Find the value of n.

Detailed Solution for Differential Calculus NAT Level - 2 - Question 9

Let

π/4  is point of minima

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Differential Calculus NAT Level - 2 - Question 10

If a, b, c, d are real numbers such that then the equation ax3 + bx2 + cx + d = 0  has at least one root in (0, α). Find the value of α.

Detailed Solution for Differential Calculus NAT Level - 2 - Question 10

⇒  6a + 4b + 3c + 3d = 0
Let

f(0) = e

Since f(x) is continuous and differentiable in (0,2) and f(0) = f(2) = e

Hence, according to Rolle's Theorem, the equation

has at least one root in (0,2). Thus, value of α = 2.