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Kinetic Theory Of Gases NAT Level – 1 - IIT JAM MCQ


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10 Questions MCQ Test - Kinetic Theory Of Gases NAT Level – 1

Kinetic Theory Of Gases NAT Level – 1 for IIT JAM 2024 is part of IIT JAM preparation. The Kinetic Theory Of Gases NAT Level – 1 questions and answers have been prepared according to the IIT JAM exam syllabus.The Kinetic Theory Of Gases NAT Level – 1 MCQs are made for IIT JAM 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Kinetic Theory Of Gases NAT Level – 1 below.
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*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 1

The capacity of a vessel in 3 litres. If contains 6gm oxygen, 8gm nitrogen and 5gm CO2 mixture at 27°C. If R = 8.31 J/mole-K, the pressure the vessel in units of 103 N/m2 will be


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 1

p = p1 + p2 + p3


= 500 × 103 N/m2
The correct answer is: 500

*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 2

22gm of CO2 at 27°C is mixed with 16 gm of O2 at 37°C. The temperature of the mixture (in °C) is?


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 2

Let t be the temperature of mixture
Heat gained by CO2 = Heat lost by O2

⇒ t = 32°C
The correct answer is: 32

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*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 3

N molecule each of mass m of gas A and 2N molecules each of mass 2m of gas B are contained in the some vessel at temperature T. The mean square at temperature T. The mean square of the velocity of molecules of gas B is v2 and the mean square of x component of the velocity of molecules of gas A is w2 . The ratio w2/vupto 2 decimal plane is.


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 3

Mean square velocity of molecule = 3kT/m
For gas A, x component of mean square velocity of molecule = w2    ...(1)
∴ Mean square velocity =  ...(2)
For B gas, mean square velocity  ...(3)
From (1) and (2), 

So,  
= 0.67
The correct answer is: 0.67

*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 4

The gases occupy two containers A and B. Gas in A, of volume 0.1 m3 exerts a pressure of 1.40 MPa and that in B of volume 0.15 m2 exerts a pressure 0.7 MPa. The two containers are united by a tube of negligible volume and gases are allowed to intermingle. Then if the temperature remains constant the final pressure in the container will be (in MPa)


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 4

µA + µB = µ


p = 0.98MPa
The correct answer is: 0.98

*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 5

A gas mixture consists of 2 mole of oxygen and 4 mole of argon at temperature T. Neglecting all vibrational modes, the total internal energy of the system in the units of RT is given as?


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 5

Total internal energy of system
= Uoxygen + Uargon

= 11RT (f1 = 5 for oxygen and f2 = 3 for argon.)
The correct answer is: 11

*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 6

At standard temperature and pressure, the density of a gas is 1.3 kg/m3 and the speed of the sound and the speed of the sound in gas is 330 m/s. Then the degree of freedom of the gas will be?


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 6

Velocity of sound  vs = 330 m/s
Density of gas ρ = 1.5kg/m3
Atmosphere Pressure p = 1.01 × 105 N/m2
Substituting these values in
 we get

Now 

The correct answer is: 5

*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 7

The mean free path of nitrogen molecules at a pressure of 1.0 atm and temperature 0°C is 0.8 × 10-7 m. If the number density of molecules is 2.7 × 1025 /m3 , then the molecular diameter (in Å) is.


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 7


n = 2.7 × 1025 /m3

d = 3.2 × 10-10 m
⇒ d = 3.2Å
The correct answer is: 3.2

*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 8

The root mean square speed of hydrogen molecules of an ideal hydrogen gas kept in a gas chamber at 0°C is 3180 m/s. The pressure of hydrogen gas (in atm) is?
(density of hydrogen gas is 8.99 × 10-2 kg/m3 , 1 atm = 1.0 × 105 N/m2 )


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 8

As 

p = 3.03 × 105 N/m2
p = 3 atm
The correct answer is: 3

*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 9

A cylinder of capacity 20 litres is filled with H2 gas. The total average kinetic energy of translatory motion of its molecules is 1.5 × 105 J. The pressure of hydrogen in the cylinder is (in 106 N/m2).


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 9

Kinetic Energy E = 1.5 × 105J
Volume V = 20 litres = 20 × 10-3 m3
Pressure = 
p = 5 × 106 N/m2
The correct answer is: 5

*Answer can only contain numeric values
Kinetic Theory Of Gases NAT Level – 1 - Question 10

If the mean free path of atoms is doubled, then the pressure of gas will change by what multiplicative factor?


Detailed Solution for Kinetic Theory Of Gases NAT Level – 1 - Question 10

As 

i.e. by increasing ρ two times, pressure will become half.
The correct answer is: 0.5

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