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Class 5 Exam  >  Class 5 Tests  >  Olympiad Test: Roman Numbers - 1 - Class 5 MCQ

Olympiad Test: Roman Numbers - 1 - Class 5 MCQ


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10 Questions MCQ Test - Olympiad Test: Roman Numbers - 1

Olympiad Test: Roman Numbers - 1 for Class 5 2024 is part of Class 5 preparation. The Olympiad Test: Roman Numbers - 1 questions and answers have been prepared according to the Class 5 exam syllabus.The Olympiad Test: Roman Numbers - 1 MCQs are made for Class 5 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Roman Numbers - 1 below.
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Olympiad Test: Roman Numbers - 1 - Question 1
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The Roman numeral ‘ LXXV’ is equal to :

Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 1
Explanation:

  • Conversion of Roman numeral 'LXXV' to Arabic numeral:

    • L = 50

    • X = 10

    • X = 10

    • V = 5



  • Calculation:

    • 50 (L) + 10 (X) + 10 (X) + 5 (V) = 75




Therefore, the Roman numeral 'LXXV' is equal to 75. Hence, the correct answer is option C: 75.
Olympiad Test: Roman Numbers - 1 - Question 2
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Write MDCCCXXXVI as a number.

Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 2
Conversion of MDCCCXXXVI to a number:

  • Start by breaking down the Roman numeral into its components:


    • M = 1000

    • D = 500

    • CCC = 300 (100 + 100 + 100)

    • X = 10

    • X = 10

    • X = 10

    • V = 5

    • I = 1


  • Add up all the components to get the total value:


    • 1000 + 500 + 300 + 10 + 10 + 10 + 5 + 1 = 1836



Therefore, the Roman numeral MDCCCXXXVI is equal to the number 1836.

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Olympiad Test: Roman Numbers - 1 - Question 3
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The Roman numeral ‘ CXI ‘ is equal to :

Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 3
Explanation:

  • Roman Numeral Conversion: In Roman numerals, C represents 100, X represents 10, and I represents 1.

  • Combining Values: To find the value of CXI, we add the values of C, X, and I together.

  • Calculation: C (100) + X (10) + I (1) = 100 + 10 + 1 = 111

  • Answer: Therefore, the Roman numeral CXI is equal to 111.

Olympiad Test: Roman Numbers - 1 - Question 4
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The Roman numeral ‘ IV ‘ is equal to :
Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 4
Explanation:

  • Roman numeral IV represents the number 4 in Roman numerals.

  • Each Roman numeral has a specific value, and IV specifically represents 4.

  • It is formed by combining the Roman numerals I (1) and V (5) in a specific way.

  • When I (1) is placed before V (5), it represents subtraction, so IV is equal to 5-1, which is 4.

Olympiad Test: Roman Numbers - 1 - Question 5
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Convert 1,866 to Roman Numerals.
Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 5

1,866 = 1,000 + 500 + 300 + 50 + 10 + 5 + 1
1,000 = M, 500 = D, 300 = CCC, 50 = L, 10 = X, 5 = V and 1 = I so 1,866 = MDCCCLXVI

Olympiad Test: Roman Numbers - 1 - Question 6
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Write DCLXIV as a number.
Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 6
Converting DCLXIV to a number

  • D = 500

  • C = 100

  • L = 50

  • X = 10

  • I = 1

  • Adding these values together: 500 + 100 + 50 + 10 + 1 = 661


Conclusion

  • Therefore, DCLXIV in Roman numerals is equal to 664 in standard number form.

Olympiad Test: Roman Numbers - 1 - Question 7
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Write 524 as a Roman Numeral.
Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 7
Converting 524 to Roman Numerals:

  • Step 1: Start by finding the largest Roman numeral that fits into 524, which is D (500).

  • Step 2: Subtract 500 from 524 to get 24.

  • Step 3: The next largest Roman numeral that fits into 24 is X (10).

  • Step 4: Subtract 10 from 24 to get 14.

  • Step 5: The next largest Roman numeral that fits into 14 is X (10) again.

  • Step 6: Subtract 10 from 14 to get 4.

  • Step 7: The last Roman numeral needed is IV (4).


Final Answer:

DXXIV


Therefore, 524 in Roman numerals is DXXIV.

Olympiad Test: Roman Numbers - 1 - Question 8
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Convert MMDCCLXXIV to ordinary numerals.
Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 8

MM = 2,000, D = 500, CC = 200, 
L = 50, XX = 20, and IV = 4 2,000 + 500 + 200 + 50 + 20 + 4 = 2,774
so MMDCCLXXIV = 2,774

Olympiad Test: Roman Numbers - 1 - Question 9
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Convert 2328 to a Roman numeral.
Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 9
Converting 2328 to a Roman numeral

  • Step 1: Start by breaking down 2328 into its Roman numeral components. The largest Roman numeral that fits into 2328 is 1000, which is represented by the letter M.


  • Step 2: Subtract 1000 from 2328, leaving us with 1328. The largest Roman numeral that fits into 1328 is 1000 again, so we add another M to our Roman numeral representation.


  • Step 3: Repeat this process until we have represented all of 2328 in Roman numerals. Continuing this process, we find that 2328 = 2000 (MM) + 300 (CCC) + 20 (XX) + 8 (VIII).


  • Step 4: Putting it all together, we get MMCCCXXVIII as the Roman numeral representation of 2328.


Therefore, the correct answer is MMCCCXXVIII.

Olympiad Test: Roman Numbers - 1 - Question 10
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Convert 2752 to a Roman numeral.
Detailed Solution for Olympiad Test: Roman Numbers - 1 - Question 10
Conversion of 2752 to Roman Numerals

  • Step 1: Write down the Roman numeral symbols and their corresponding values:

    • M = 1000

    • D = 500

    • C = 100

    • L = 50

    • X = 10

    • V = 5

    • I = 1




  • Step 2: Find the largest Roman numeral that fits into 2752, which is 2000 (represented as MM).


  • Step 3: Subtract 2000 from 2752 to get the remaining value, which is 752.


  • Step 4: Repeat the process for 752:

    • Find the largest Roman numeral that fits into 752, which is 500 (represented as D).

    • Subtract 500 from 752 to get the remaining value, which is 252.




  • Step 5: Repeat the process for 252:

    • Find the largest Roman numeral that fits into 252, which is 200 (represented as CC).

    • Subtract 200 from 252 to get the remaining value, which is 52.




  • Step 6: Repeat the process for 52:

    • Find the largest Roman numeral that fits into 52, which is 50 (represented as L).

    • Subtract 50 from 52 to get the remaining value, which is 2.




  • Step 7: Repeat the process for 2:

    • Find the largest Roman numeral that fits into 2, which is 2 (represented as II).

    • Subtract 2 from 2 to get the remaining value, which is 0.




  • Step 8: Combine all the Roman numerals found in each step to get the final answer: MMDCCLII.

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