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JEE Main Practice Test- 7 - JEE MCQ


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30 Questions MCQ Test - JEE Main Practice Test- 7

JEE Main Practice Test- 7 for JEE 2024 is part of JEE preparation. The JEE Main Practice Test- 7 questions and answers have been prepared according to the JEE exam syllabus.The JEE Main Practice Test- 7 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for JEE Main Practice Test- 7 below.
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JEE Main Practice Test- 7 - Question 1

Work done by the system in closed path ABCA, as shown in figure is

Detailed Solution for JEE Main Practice Test- 7 - Question 1

Work done = area of ΔABC

JEE Main Practice Test- 7 - Question 2

A body executes S.H.M. of period 20 seconds. Its velocity is 5 cm s-1, 2 seconds after it has passed the mean position. Find amplitude of the bob

Detailed Solution for JEE Main Practice Test- 7 - Question 2

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JEE Main Practice Test- 7 - Question 3

Calculate the gas constant for 1g of a gas from the following data: cp = 0.245calg-1oC-1;cv = 0.165calg-1°C-1

Detailed Solution for JEE Main Practice Test- 7 - Question 3


JEE Main Practice Test- 7 - Question 4

A balloon is moving upwards with a speed of 20 m/s. When it is at a height of 14 m from ground in front of a plane mirror in as shown in figure, a boy drops himself from the balloon. Find the time duration for which he will see the image of source S placed symmetrically before plane mirror during free fall.

Detailed Solution for JEE Main Practice Test- 7 - Question 4




FC = 2 + 10 = 12 m

The boy has dropped himself at point F. So, his velocity is 20 m/s in upward direction.
Let us first find the time to move from F to topmost point and then from topmost point to point C. From

Solving this equation we get, t1 = 4.53 s.
Velocity of boy at point Q,
 (v2 = u2 - 2gh)
Time taken to move the boy from Q to topmost point and then from topmost point to Q will be. 

∴Time required time is : t = t1 - t2 = 1.7 s

JEE Main Practice Test- 7 - Question 5

Prism angle & refractive index for a prism are 60o & 1.414. Angle of minimum deviation will be

Detailed Solution for JEE Main Practice Test- 7 - Question 5

JEE Main Practice Test- 7 - Question 6

If a gas is heated at constant pressure then what percentage of total heat supplied is used for doing work ? (Given : γ for gas = 4/3)

Detailed Solution for JEE Main Practice Test- 7 - Question 6

Heat supplied dQ = nCpdT
Heat used for work = dw = nRdT

= 25%
Thermodynamics Process
The process of change of state of a system involves change of thermodynamic variables such as pressure P, volume V and temperature T of the system. This process is known as thermodynamic process

JEE Main Practice Test- 7 - Question 7

Four persons K, L, M, N are initially at the four corners of a square of side d. Each person now moves with a uniform speed  v in such a way that K always moves directly towards L, L directly towards M, M directly towards N, and N directly towards K. The four persons will meet at a time .....

Detailed Solution for JEE Main Practice Test- 7 - Question 7

The velocity of K throughout the motion towards the centre of the square is  v cos45  and the displacement covered by this velocity will be KO.

JEE Main Practice Test- 7 - Question 8

Estimate the speed of sound in air at standard temperature and pressure. The mass of 1 mole of air is 29.0 × 10-3 kg

Detailed Solution for JEE Main Practice Test- 7 - Question 8

At N.T.P., P = 1.013 x 105 N m-2
volume of air, V = 22400 cm3 = 2.24 x 10-2 m3
mass of 1 mole of air M = 29.0 x 10-3 kg Therefore, density of air at N.T.P.,

JEE Main Practice Test- 7 - Question 9

A pendulum bob is suspended on a flat car that moves with velocity v0. The flat car is stopped by a bumper
(i) What is the angle through which the pendulum swings.
(ii) If the swing angle is θ = 60° and l = 10m, what was the initial speed of the flat car?

Detailed Solution for JEE Main Practice Test- 7 - Question 9

When the flat car collides with the bumper, due to inertia of motion the bob swings forward No work is done by tension of string on the bob therefore energy is conserved

JEE Main Practice Test- 7 - Question 10

Two slits, 4 mm apart, are illuminated by light of wavelength 6000Å. What will be the fringe width on a screen placed 2 m from the slits?

Detailed Solution for JEE Main Practice Test- 7 - Question 10

JEE Main Practice Test- 7 - Question 11

A car moves uniformly along a horizontal sine curve y = a sin (x/α), where a and α are certain constants. The coefficient of friction between the wheels and the road is equal to k. At what velocity will the car ride without sliding?

Detailed Solution for JEE Main Practice Test- 7 - Question 11

Step I : Determine the radius of curvature of given curve at point P (x, y)

∴ radius of curvature is 

Step II : Relate the fnction and centnpetal acceleration In this case, centripetal acceleration is provided by force of fnction

From equation (i), for minimum value of radius of curvature,

JEE Main Practice Test- 7 - Question 12

A large tank filled with water to a height 'h' is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from h to h/2 and from h/2 to zero is

Detailed Solution for JEE Main Practice Test- 7 - Question 12

Time taken for the level to fall from H to H'

According to problem the time taken for the level to fall from h to h/2

and similarly time taken for the level to fall from h/2

JEE Main Practice Test- 7 - Question 13

A bullet of mass 2 g is having a charge of 2μC. The potential difference it must be accelerated through, starting from rest, to acquire a speed of 10 m/s is

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JEE Main Practice Test- 7 - Question 14

A wire of length L and 3 identical cells of negligible internal resistance are connected in series. Due to the current, the temperature of the wire is raised by ΔT in a time t. A number of N similar cells are now connected in series with a wire of the same material and area of cross-section but of length 2L. The temperature of the wire is raised by the same amount ΔT in the same time . The value of N is

Detailed Solution for JEE Main Practice Test- 7 - Question 14

In the first case

When length of the wire is doubled, resistance and mass both are doubled. Therefore, in the second case,

Dividing Eq.(ii) by (i) we get

JEE Main Practice Test- 7 - Question 15

The intensity of the light coming from one of the slits in YDSE is double the intensity from the other slit. Find the ratio of maximum intensity to minimum intensity in the interference fringe pattern observed.

Detailed Solution for JEE Main Practice Test- 7 - Question 15


JEE Main Practice Test- 7 - Question 16

Consider α-particles, β-particles and γ- rays each having an energy of 0.5 MeV. In increasing order of penetrating powers, the radiations are

Detailed Solution for JEE Main Practice Test- 7 - Question 16

Penetrating power is maximum for γ - rays, then of β -particles and then α - particles because basically it depends on the velocity. However, ionization power is in reverse order.

JEE Main Practice Test- 7 - Question 17

A battery is supplying power to a tape-recorder by cable of resistance of 0.02 Ω . If the battery is generating 50 W power at 5V, then power received by tape-recorder is :

Detailed Solution for JEE Main Practice Test- 7 - Question 17

P = VI,
50 = 5 × I
I = 10 A
Power lost in cable= I2R = 10 × 10 × 0·02 = 2W
Power supplied to T. R= 50  W - 2  W   = 48 W 

JEE Main Practice Test- 7 - Question 18

A uniform rod of mass m and length ℓ is rotating with constant angular velocity ω about an axis which passes through its one end and perpendicular to the length of rod. The area of cross section of the rod is A and its Young's modulus is Y. Neglect gravity. The strain at the mid point of the rod is :

Detailed Solution for JEE Main Practice Test- 7 - Question 18


⇒ 

∴ Tension at mid point is :
 

JEE Main Practice Test- 7 - Question 19

Initially car A is 10.5 m ahead of car B. Both start moving at time t = 0 in the same direction along a straight line. The velocity time graph of two cars is shown in figure. The time when the car B will catch the car A, will be ;

Detailed Solution for JEE Main Practice Test- 7 - Question 19

JEE Main Practice Test- 7 - Question 20

Two masses m1 and m2 are connected by a string of length l. They are held in a horizontal plane at a height H above two heavy plates A and B made of different material placed on the floor. Initially distance between two masses is a < l. When the masses are released under gravity they make collision with A and B co - efficient of restitution 0.8 and 0.4 respectively. The time after the collision when the string becomes tight is

Detailed Solution for JEE Main Practice Test- 7 - Question 20

String will become tight when


∴ 

*Answer can only contain numeric values
JEE Main Practice Test- 7 - Question 21

The difference between (n + 2)th Bohr radius and nth Bohr radius is equal to the (n – 2)th Bohr radius. The value of n is ?


Detailed Solution for JEE Main Practice Test- 7 - Question 21

*Answer can only contain numeric values
JEE Main Practice Test- 7 - Question 22

The figure shows an RC circuit with a parallel plate capacitor. Before switching on the circuit, plate A of the capacitor has a charge –Q0 while plate B has no net charge. Now, at t = 0, the circuit is switched on. How much time (in second) will elapse before the net charge on plate A becomes zero.

 

(GivenC=1μF, Q0=1mC, ε=1000V and 


Detailed Solution for JEE Main Practice Test- 7 - Question 22

Let at any time t charge flown through the plate B to plate A is Q and instantaneous current is I

Now for charge on plate A to zero q = Q0

Putting value of C1 ,Q0 ,∈ and R , we get t = 2 seconds

*Answer can only contain numeric values
JEE Main Practice Test- 7 - Question 23

A thin non conducting disc of mass M = 2kg, charge Q = 2x10–2 C and radius R = 1/6m is placed on a frictionless horizontal plane with its centre at the origin of the coordinate system. A non uniform, radial magnetic field  exists in space, where B0 = 10T and  is a unit vector in the radially outward direction. The disc is set in motion with an angular velocity w = x*102 rad/sec, about an axis passing through its centre and perpendicular to its plane, as shown in the figure. At what value of x, the disc will lift off from the surface.


Detailed Solution for JEE Main Practice Test- 7 - Question 23

The force an any small part of the disc is in the vertically upward direction

*Answer can only contain numeric values
JEE Main Practice Test- 7 - Question 24

All springs, string and pulley shown in figure are light. Initially when both the springs were in their natural state, the system was released from rest. The maximum displacement of block m is  calculate x


Detailed Solution for JEE Main Practice Test- 7 - Question 24

*Answer can only contain numeric values
JEE Main Practice Test- 7 - Question 25

In Young’s Double slit experiment, a thin glass mica strip of thickness (t = 8λ) is pasted infront of slit S1. If the same strip is now shifted in front of other slit S2. If the number of fringes which will cross the central point on the screen is N. Find N? (d >> D, λ << d and nmica = 1.5)


Detailed Solution for JEE Main Practice Test- 7 - Question 25

(μ - 1)t = nλ
n = number of fringes  shifted
(1.5 - 1)8λ = nλ
n = 4
If the number of fringes which will cross the central point on the screen is  N
N, then 
N = 2 n = 8
Hence the total number of fringes shifted is 
8

JEE Main Practice Test- 7 - Question 26

A saturated aqueous solution of sparingly soluble salt AB3 has the vapour pressure 0.08 mm lesser than the vapour pressure 17.33 mm of solvent at 25oC. The solubility product of AB3 is :

Detailed Solution for JEE Main Practice Test- 7 - Question 26


JEE Main Practice Test- 7 - Question 27

Photoelectric emission is observed from a surface for frequencies v1 and v2 of the incident radiation (v1 > v2). If the maximum kinetic energies of the photoelectrons in the two cases are in the ration l : k then the threshold frequency v0 is given by :

Detailed Solution for JEE Main Practice Test- 7 - Question 27

JEE Main Practice Test- 7 - Question 28

In the following electron dot structure calculate the formal charge from left to right nitrogen atom ?

Detailed Solution for JEE Main Practice Test- 7 - Question 28

1.Left N
⇒ 5 - 4 - 1/2 (4) = - 1
2.Central N
⇒ 5 - 0 - 1/2 (8) = + 1
3.Right N
⇒ 5 - 4 - 1/2 (4) = - 1

JEE Main Practice Test- 7 - Question 29

A 50 litre vessel is equally divided into three parts with the help of two stationary semi permeable membrane (SPM). The vessel contains 60 g H2 gas in the left chamber, 160 g O2 in the middle and 140 g N2 in the right one. The left SPM allows transfer of only H2 gas while the right one allows the transfer of both H2 and N2. The final ratio of pressure in the three chambers.

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JEE Main Practice Test- 7 - Question 30

Acetamide is treated separately with the following reagents. Which of these would give methylamine ?

Detailed Solution for JEE Main Practice Test- 7 - Question 30

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