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Olympiad Test: Area, Perimeter And Volume - Class 5 MCQ


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20 Questions MCQ Test - Olympiad Test: Area, Perimeter And Volume

Olympiad Test: Area, Perimeter And Volume for Class 5 2024 is part of Class 5 preparation. The Olympiad Test: Area, Perimeter And Volume questions and answers have been prepared according to the Class 5 exam syllabus.The Olympiad Test: Area, Perimeter And Volume MCQs are made for Class 5 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Area, Perimeter And Volume below.
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Olympiad Test: Area, Perimeter And Volume - Question 1

Find the area of the triangle shown.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 1

Area of triangle = 1/2 (b*h)

= 1/2 (13*5)

= 65/2

= 32.5 cm2

Olympiad Test: Area, Perimeter And Volume - Question 2

Find the perimeter of the triangle shown in the previous question.

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Olympiad Test: Area, Perimeter And Volume - Question 3

Find the area of the parallelogram shown.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 3

area of parallelogram = base x height = 10 x 20 = 200 cm2

Olympiad Test: Area, Perimeter And Volume - Question 4

Find the perimeter of the parallelogram shown in the previous question.

Olympiad Test: Area, Perimeter And Volume - Question 5

Find the area of the trapezoid shown.

Olympiad Test: Area, Perimeter And Volume - Question 6

Find the perimeter of the trapezoid shown in the previous question.

Olympiad Test: Area, Perimeter And Volume - Question 7

Find the area of the circle shown.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 7

πr2
π(4)2
16π
16x3.14
50.24

Olympiad Test: Area, Perimeter And Volume - Question 8

Find the perimeter of the circle.

A circle is inscribed in a square as shown. If the radius of the circle is  4cm, then the perimeter of the square is\n \n \n \n \n A. 28 cm B.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 8

2πr
2π(4)

8x3.14
25.12

Olympiad Test: Area, Perimeter And Volume - Question 9

Find the area of the figure shown.

Olympiad Test: Area, Perimeter And Volume - Question 10

Find the perimeter of the figure shown in the below

Olympiad Test: Area, Perimeter And Volume - Question 11

A square has an area of 64 cm2. What is the length of each side?

Olympiad Test: Area, Perimeter And Volume - Question 12

The figure below is made up of 3 squares of sides 5 cm. What is the perimeter of the figure?

Olympiad Test: Area, Perimeter And Volume - Question 13

The figure below is made up of three squares. Find the perimeter of the figure.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 13

there are 8 boundry lines so  8 * a  = 8*6 = 48 

Olympiad Test: Area, Perimeter And Volume - Question 14

The area of the figure above is _____ 
m2.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 14

first break it into a rectangle and square


rectangle of LxB=9x7
square of side=5
so area of rectangle = 9x7 =63
area of square = 5x5 = 25
so total  area = 63 +25
                      = 88

Olympiad Test: Area, Perimeter And Volume - Question 15

The perimeter of a square is 20 cm. What is the length of each side of the square?

Olympiad Test: Area, Perimeter And Volume - Question 16

Which of the following figures have the same shaded area?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 16

Figures R and each have 7 black squares, so they have the same area.

Olympiad Test: Area, Perimeter And Volume - Question 17

Which one of the following rectangles had the biggest perimeter?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 17

A) Area = 96m2

Breadth = 8m

Area = l*b

96 = l*8

l =12

Perimeter = 2(l+b)

= 2(12+8) = 40

 

B) Area = 110m2

Breadth = 10cm = 0.1m

Area = l*b

110 = l*0.1

l =1100

Perimeter = 2(l+b)

= 2(1100+0.1) = 2200.2

 

C) Area = 90m2

Length = 15cm = 0.15m

Area = l*b

90 = 0.15*b

b = 600m

Perimeter = 2(l+b)

= 2(0.15+600) = 1200.3

 

D) Area = 100m2

Length = 25cm = 0.25m

Area = l*b

100 = 0.25*b

b = 400m

Perimeter = 2(l+b)

= 2(0.25+400) = 800.5

Olympiad Test: Area, Perimeter And Volume - Question 18

The perimeter of the figure shown below is 36 m. What is the length of DE?

Olympiad Test: Area, Perimeter And Volume - Question 19

Calculate the area of rectangle if one square represents an area of 1 cm.

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 19

There are 6×4=24 squares and each square has an area of = 1cm2. So, the area of rectangle = 6×4×1=24cm2.

Olympiad Test: Area, Perimeter And Volume - Question 20

A rectangular garden measures 25 m by 20 m. What is the cost of erecting a wooden fence around it if every 5 metres of wooden fencing cost $ 27?

Detailed Solution for Olympiad Test: Area, Perimeter And Volume - Question 20

Let's take perimeter of recatngular garden=
2(20m+25m)= 90m

Cost of fencing every 5 m= Rs 27
Cost of fencing 90 m= $ 27/5 ×90
= $ 27× 18= $ 486

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