Test: Building With Bricks - 3 - Class 4 MCQ

Explanation:

Counting Triangles:

- Start by counting the smaller triangles within the figure.
- There are 4 small triangles in the center.
- Moving outwards, there are 4 triangles on each side.
- Finally, there is 4 large triangle encompassing all the smaller ones from square.

so a total of 12 triangles

GH symmetrically divides the figure.

All are closed figures with different number of sides and a closed figure is called a polygon.

Perimeter of the given figure = 44 cm.

Only one square must be shaded to divide the figure into two equal parts.

                    
The squares formed are 12, 34, 56, 78, 2367 and 12345678 i.e., 6 in number.

We have,
AB + GH + CD = FE
⇒ 3 cm + GH + 6 cm = 12 cm
⇒ GH = 12 cm - 9 cm = 3 cm

Perimeter of a figure is the sum of all of its sides.
Perimeter of I=5+2+5+2= 14cm Perimeter of II = 2+2+2=6cm
Perimeter of III = 4+4+4+4=16cm Hence III has highest perimeter,

GH symmetrically divides the figure.

In rectangle IJKL, we have
IJ = LM + MK (opposite sides are equal in a rectangle.) ⇒8=5+MK
∴ MK = 3 cm
In rectangle MNOP, we have
MP = NO ⇒ MK + KP = NO
⇒ 3 + KP = 12
⇒ KP = 9 cm.