Olympiad Test : Mensuration - Class 6 MCQ

If x is required length then
x + x + x = 267
3x = 267 ⇒ 

Here, 3 × perimeter of rectangular ground = 7800 m
⇒ 3 [2 (l + b)] = 7800

Perimeter of isosceles triangle
= 8.5 + 8.5 + 7 = 24 cm 

Perimeter of regular hexagon
= 6 × 6.5 cm = 39 cm 

Here, Perimeter 
If l  and b are its length and breadth, then
⇒ 2(l + b) = 110
⇒ 2(l + 23) = 110
⇒ l + 23 = 55 ⇒ l = 55 - 23 = 32m 

Circumference of circle = 66
2πr = 66 where r is radius

Given,
2π r = 264 where r is radius

Circumference of wheel of car
 
∴ Required no. of revolutions 

Circumference of circle 

If b  is breadth of rectangle then

Perimeter = 2 (l + b) = 2 (35 + 18)
= 2 × 53 = 106 cm 

Area of the room = 
If b  is its width then
l × b = 60 

Breadth of rectangle

∴ Perimeter of rectangle = 2 ( 36 + 15)
= 2 × 51 = 102 cm.

Area of square 

= 25 cm²

If 5x and 3x are length and breadth then
2 (5x + 3x) = 128

∴ l = 5 × 8 = 40 m
and b = 3 × 8 = 24 m
Hence, area = l × b = 40 × 24 = 960 m²

Required no. of square tiles

= 9600

Area of one flower bed = 3 × 3 = 9 cm²
Area of five flower beds = 9 × 5 = 45 cm²
Area of rectangular field = 17 × 5    = 85 cm²
Area of remaining part = 85 – 45 = 40 cm²

Missing value = 37 – (5 + 4 + 17)
= 37 – 26 = 11 cm 

Area of square = 2401 = 49 × 49
∴ Side of square = 49 cm
Hence, perimeter of square
= 4 × side = 4 × 49 = 196 cm 

Area of square

= 64
∴ Side of square = 8 cm
Hence, perimeter of square
= 4 × 8 = 32 cm   

Area of floor = 7 × 5 = 35 m²
Area of carpet = 4 × 4 = 16 m²
Remaining part = 35 – 16 = 19 m²