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Test: Isomerism In Coordination Compounds- II - JEE MCQ


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25 Questions MCQ Test - Test: Isomerism In Coordination Compounds- II

Test: Isomerism In Coordination Compounds- II for JEE 2024 is part of JEE preparation. The Test: Isomerism In Coordination Compounds- II questions and answers have been prepared according to the JEE exam syllabus.The Test: Isomerism In Coordination Compounds- II MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Isomerism In Coordination Compounds- II below.
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Test: Isomerism In Coordination Compounds- II - Question 1
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Only One Option Correct Type

Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

Q. Which type of isomerism is shown by [Co(NH3)4 Br2CI]? 

Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 1

[Co(NH3)4Br2]CI can show both geometrical and ionisation isomerism.

[Co(NH3)4Br2]CI or [Co(NH3)4BrCI]Br

Test: Isomerism In Coordination Compounds- II - Question 2
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The complex that exists as a pair of enantiomers is

Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 2

[Co(en)3]3+, where, en = (NH2CH2CH2NH2)
The complex show optical isomerism. Optical isomers are mirror image that cannot be superimposed on one another. These are called as enantiomers. The molecules or ions that cannot be superimposed are called chiral.

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Test: Isomerism In Coordination Compounds- II - Question 3
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Which of the following will have three stereoisomeric form ?

i. [Cr(NO3)3(NH3)3]
ii. K3[Co(C2O4)3]
iii. K3[Co(C2O4)2CI2]
iv. [Co(en)2CIBr]

Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 3

The complex [Co(C2O4)2Cl2]3- show both geometrical and optical isomers.

Test: Isomerism In Coordination Compounds- II - Question 4
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A coordination compound of cobalt has the molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three ions in an aqueous solution. The aqueous solution on treatment with an excess of AgNO3 gives two moles of AgCI as a precipitate. The formula of the complex and the isomerism shown by this is
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 4

The complex [CO(NH3)5NO2]CI2  produces three ions in aqueous solution.

[Co(NH3)5NO2]CI2 → [Co(NH3)5NO2]+ + 2Cl-
The aqueous solution on treatment with an excess of AgNO3 gives two moles of AgCI because we have 2 moles of Cl- ion in aqueous solution.
Linkage isomers

[Co(NH3)5NO2]CI2 and [Co(NH3)5(ONO)]CI2
The nitrite ligand is bound through oxygen (—ONO)in red form. The nitrite ligand is bound through nitrogen (—NO2) in yellow form.

Test: Isomerism In Coordination Compounds- II - Question 5
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Which of the following will give maximum number of isomers?
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 5

[Cr(SCN)2(NH3)4]+ shows linkage, geometrical and optical isomerism.

Test: Isomerism In Coordination Compounds- II - Question 6
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Which of the following coordination compounds would exhibit optical isomerism?
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 6

Test: Isomerism In Coordination Compounds- II - Question 7
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Which one of the following is expected to exhibit optical isomerism?

(en = ethylenediamine)
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 7

Test: Isomerism In Coordination Compounds- II - Question 8
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How the isomeric complexes [Co(NH3)6] [Cr(NO2)6] and [Cr(NH3)6] [Co(NO2)6] can be distinguished from one another by
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 8

In [Co(NH3)6] [Cr(NO2)6], the [Co(NH3)6]3+ ion migrates towards the negative electrode where cobalt would be deposited. In [Cr(NH3)6] [Co(NO2)6], the [Cr(NH3)6]3+ ion migrates towards the negative electrode where chromium would be deposited.

Test: Isomerism In Coordination Compounds- II - Question 9
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The complexes [Co(NH3)6] [Cr(CN)6] and [Cr(NH3)6] [Co(CN)6] are the examples of which type of isomerism?

[AIEEE 2011]
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 9

The given complexes are the examples of coordination isomers

Test: Isomerism In Coordination Compounds- II - Question 10
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The isomerism shown by [Co(EDTA)]- ion is
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 10

*Multiple options can be correct
Test: Isomerism In Coordination Compounds- II - Question 11
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Direction (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q. 

[Co(NH3)4 (NO2)2]Cl exhibits
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 11

The compound [Co(NH3)4((NO2)2]Cl exhibits linkage, ionisation and geometrical isomerism.
Hence, its linkage isomers are

(i) [Co(NH3)2(NO2)2]Cl and [Co(NH3)4(ONO)2]Cl

(ii) Its ionisation isomers are 
[Co(NH3)4 (NO2)Cl]NO2 and [Co(NH3)4(NO2)2]Cl

(iii) Its geometrical isomers are

*Multiple options can be correct
Test: Isomerism In Coordination Compounds- II - Question 12
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The complex [Co(NH3)5Br] SO4 and [Co(NH3)5SO4] Br can be identified by
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 12

Both given complexes can be identified by BaCI2, AgNO3 and PbCI2

*Multiple options can be correct
Test: Isomerism In Coordination Compounds- II - Question 13
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The pair(s) of coordination complexes/ions exhibiting the same kind of isomerism is/are
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 13

(a) [Cr(NH3)5CI]2+ no isomerism and [Cr(NH3)4CI2]+ show only geometrical.
(b) [Cr(NH3)4CI2]+ only geometrical and [Pt(NH3)2(H2O)CI]+ only geometrical.
(c) [CoBr2CI2]2- no isomerism because complex is tetrahedral and [ptBr2CI2]2- show geometrical.
(d) [Pt(NH3)3NO3]CI only ionisation and [Pt(NH3)3CI]Br only ionisation.

*Multiple options can be correct
Test: Isomerism In Coordination Compounds- II - Question 14
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Which of the following complexes show geometrical isomerism?
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 14

Tetrahedral complexes do not show geometrical isomerism because the relative position of the unidentate ligands attached to the central metal atoms are the same with respect to each other.

*Multiple options can be correct
Test: Isomerism In Coordination Compounds- II - Question 15
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The compound(s) that exhibit(s) geometrical isomerism is/are
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 15


Geometrical isomers (cis and trans) of [Pt(NH3)2Cl2] 

Test: Isomerism In Coordination Compounds- II - Question 16
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Comprehension Type

Direction (Q. Nos. 16 and 17) This section contains a paragraph, each describing theory, experiments, data, etc. Two questions related to the paragraph have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage

A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.

Q.

The formula of complex A
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 16

[Cr(NH3)4CIBr]CI→ [Cr(NH3)4CIBr]+ + Cl-
Complex (A) give white ppt. of AgCI with AgNO3.

Test: Isomerism In Coordination Compounds- II - Question 17
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A metal complex having the composition Cr(NH3)4CI2Br has been isolated in two forms A and B. The form A reacts with AgNO3 to give a white precipitate readily soluble in dilute aqueous ammonia whereas B gives a pale yellow precipitate soluble in cone, ammonia.

Q. 

The isomerism shown by complex A is
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 17


Ionisation isomers [Cr(NH3)4CIBr]CI and [Cr(NH3)4CI2]Br

Test: Isomerism In Coordination Compounds- II - Question 18
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Matching List Type

Direction (Q. Nos. 18 and 19) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d) out of which one is correct.

Q. 

Match the Column I with Column II and mark the correct option from the codes given below.

   
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 18

(i) → (q), (ii) → (p), (iii) → (s), (iv) → (r)

Test: Isomerism In Coordination Compounds- II - Question 19
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Match the Column I with Column II and mark the correct option from the codes given below. 

  
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 19

(i) → (r), (ii) → (q.s), (iii) → (p), (iv) → s

*Answer can only contain numeric values
Test: Isomerism In Coordination Compounds- II - Question 20
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One Integer Value Correct Type

Direction (Q. Nos. 20 -24) This section contains 5 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Q. 

The total number of isomers expected for [Pt(NCS)(en)2]2+ are

Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 20

The complex can be shown in three forms as given below: [Pt(NCS)2(en)2]2+,[Pt(SCN)2(en)2]2+ and [Pt(SCN)(NCS)(en)2]2+, Each one has a trans-isomer and dextro cis and laevo cis. Hence, total isomers are 3 x 3 = 9.

*Answer can only contain numeric values
Test: Isomerism In Coordination Compounds- II - Question 21
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Number of isomers possible for [Co(NH3)5SCN]CI are

Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 21

[Co(NH3)5SCN]CI and [Co(NH3)5NCS]CI
[Co(NH3)5CI]SCN and [Co(NH3)5Cl]NCS

*Answer can only contain numeric values
Test: Isomerism In Coordination Compounds- II - Question 22
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[Fe(EDTA)]- exhibits optical isomerism. In this complex, the number of rings formed are

Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 22

When[Fe(EDTA)]- exhibits optical isomerism, the complex will form five rings.

*Answer can only contain numeric values
Test: Isomerism In Coordination Compounds- II - Question 23
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The number of geometrical isomers possible for the complex [CoCI2Br2]- are

Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 23

This is a tetrahedral complex.

*Answer can only contain numeric values
Test: Isomerism In Coordination Compounds- II - Question 24
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The total number of possible isomers for the complex compound

[CuII(NH3)4] [PtIICI4] are

Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 24

Total 4 isomers are possible: 
i. [Cu(NH3)3Cl][Pt(Cl3)NH3],
ii. [Cu(NH3)2Cl2][PtCl2(NH3)2],
iii. [CuNH3Cl3][PtCl(NH3)3],
iv. [CuCl4][Pt(NH3)4]

Test: Isomerism In Coordination Compounds- II - Question 25
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Statement Type

Direction (Q. No. 25) This section is based on Statement I and Statement II. Select the correct answer from the codes given below.

Q. 

Statement I : Ambidentate ligands lead to linkage isomerism.

Statement II : The ionisation sphere is different in different linkage isomers.
Detailed Solution for Test: Isomerism In Coordination Compounds- II - Question 25

Correct Statement II is the donor atom linking to the central metal atom is different in different linkage isomers.

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