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Olympiad Test: Lines And Angles - 1 - Class 7 Mathematics Free MCQ


MCQ Practice Test & Solutions: Olympiad Test: Lines And Angles - 1 (10 Questions)

You can prepare effectively for Class 7 Mathematics Olympiad Class 7 with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Olympiad Test: Lines And Angles - 1". These 10 questions have been designed by the experts with the latest curriculum of Class 7 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 10

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Olympiad Test: Lines And Angles - 1 - Question 1

What is the supplement of 64°?

Detailed Solution: Question 1

The supplement of an angle is calculated by subtracting the given angle from 180°
Therefore, Supplement of 64° is 180° – 64° = 116°

Olympiad Test: Lines And Angles - 1 - Question 2

What is the value of x in the given figure?

Detailed Solution: Question 2

64 + x + 93 = 180
⇒ 157 + x = 180°
⇒ x = 180° – 157° = 23°

Olympiad Test: Lines And Angles - 1 - Question 3

What is the complement of 67°?

Detailed Solution: Question 3

The complement of an angle is calculated by subtracting the given angle from 90 degrees 

Complement of 67 degrees = (90 −67) degrees =23 degrees 

Olympiad Test: Lines And Angles - 1 - Question 4

​In the following figure, if AB ∥ CD, ∠ BAP = 108° and ∠ PCD = 120°, what is the measure of ∠ APC?

Detailed Solution: Question 4


AB ∥ PQ 
∴ ∠APQ = 180° – 108° = 72°
PQ ∥CD 
∠ CPQ = 180° –120° = 60°
∠ APC= ∠APQ+ ∠CPQ = 72° + 60°
= 132°

Olympiad Test: Lines And Angles - 1 - Question 5

In the given figure MN ∥ PQ ∠MNE = 120°, ∠EPQ = 100°.What is the value of x?

Detailed Solution: Question 5


Given, MN ∥PQ 
∠PON = 100°
∴ ∠NOE = 180° – 100 = 80°
∠ENO = 180° – 120° = 60°
x = 180° – (80° + 60°)
= 180° –140° = 40°

Olympiad Test: Lines And Angles - 1 - Question 6

In the given figure AB ∥ CD and EF is transversal. If ∠1 and ∠2 are in the ratio 5:7 what is the measure of ∠8?

Detailed Solution: Question 6

5x + 7x = 180°
⇒ 12x = 180°
⇒ x = 180° / 12 = 15°
∠1 = 5x = 5×15 = 75°
∠2 = 7x = 7×15 = 105°
∠1 = ∠5 = 75°
∠8 = 180° – 75° = 105°

Olympiad Test: Lines And Angles - 1 - Question 7

What is the value of x in the following figure?

Detailed Solution: Question 7

Here, 2x –10° + 3x + 20° = 180°
⇒ 5x + 10° = 180°
⇒  5x = 170°
⇒ x = 170° / 5 = 34°

Olympiad Test: Lines And Angles - 1 - Question 8

Find the angle which is equal to its complement

Detailed Solution: Question 8

Complementary angles are those angles that add up to 90 degrees.

Let the angle be x.

Therefore, the complement of this angle will also be x.
[Since, it's given that the angle is equal to its complement]

We know that the sum of the measure of a pair of complementary angles is 90°.

x + x = 90°
2x = 90°
x = 90° / 2
x = 45°

Thus, the angle which is equal to its complement is 45°.

Olympiad Test: Lines And Angles - 1 - Question 9

In the given figure, ABC is a straight line. What is the value of y?

Detailed Solution: Question 9


In ∆ABP
∠ ABP = 180° –(26°+38°)
= 180° – 64 = 116°
∠PBC = 180° – 116° = 64°
PB = PC
∠PBC = 64°
y = 180° – (64° + 64°)
= 180° –128°
= 52°

Olympiad Test: Lines And Angles - 1 - Question 10

One of the angles forming a linear is a right angle. What will be the other angle?

Detailed Solution: Question 10

- A linear pair of angles forms a straight line and sums to 180 degrees.
- If one angle is a right angle, it measures 90 degrees.
- The sum of the two angles must be 180 degrees.
- Subtracting the right angle (90 degrees) from 180 degrees leaves another 90 degrees.
- Therefore, the other angle must also be a right angle.
- Thus, the correct answer is C: Right Angle.

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