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Olympiad Test: Exponents And Powers - 2 - Class 8 MCQ


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10 Questions MCQ Test - Olympiad Test: Exponents And Powers - 2

Olympiad Test: Exponents And Powers - 2 for Class 8 2024 is part of Class 8 preparation. The Olympiad Test: Exponents And Powers - 2 questions and answers have been prepared according to the Class 8 exam syllabus.The Olympiad Test: Exponents And Powers - 2 MCQs are made for Class 8 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Olympiad Test: Exponents And Powers - 2 below.
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Olympiad Test: Exponents And Powers - 2 - Question 1

 the value of x will be:

Detailed Solution for Olympiad Test: Exponents And Powers - 2 - Question 1

(2)5 = 32

Olympiad Test: Exponents And Powers - 2 - Question 2

By what number (23)-3 should be multiplied so that the product becomes (69)-1?

Detailed Solution for Olympiad Test: Exponents And Powers - 2 - Question 2

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Olympiad Test: Exponents And Powers - 2 - Question 3

then k will be equal to: 

Detailed Solution for Olympiad Test: Exponents And Powers - 2 - Question 3



 

Olympiad Test: Exponents And Powers - 2 - Question 4

The distance between earth and the sun is 15 ×107 km. Express this distance in metres.

Detailed Solution for Olympiad Test: Exponents And Powers - 2 - Question 4

Distance
  

Olympiad Test: Exponents And Powers - 2 - Question 5

Simplify : 

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Olympiad Test: Exponents And Powers - 2 - Question 6

(6 + 3) × 9-1 ÷ 3-1 + 2-2 =

Detailed Solution for Olympiad Test: Exponents And Powers - 2 - Question 6

Here (6 + 3) × 9-1 ÷ 3-1 + 2-2                 
= 9 × 9-1 ÷ 3-1 + 2-2

Olympiad Test: Exponents And Powers - 2 - Question 7

m ≠ 0, p ≠ 0 and m = n = p

Detailed Solution for Olympiad Test: Exponents And Powers - 2 - Question 7

We have 

Olympiad Test: Exponents And Powers - 2 - Question 8

The size of a plant cell is 0.00001275 m. Express this distance in standard form.

Detailed Solution for Olympiad Test: Exponents And Powers - 2 - Question 8

Size of plant cell
 

Olympiad Test: Exponents And Powers - 2 - Question 9

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Olympiad Test: Exponents And Powers - 2 - Question 10

 then x =

Detailed Solution for Olympiad Test: Exponents And Powers - 2 - Question 10

Here 23x + 5 × (3)2x + 5
= (2)3x + 2 × (3) 3x + 2

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