For a Cannizaro reaction, Rate law is derived as : Rate = k [RCHO] 2 [HO - ] 2 From the above rate law, it can be concluded that

reaction involves hydride ion transfer

reaction does not show kinetic isotopic effect

Consider the following reaction, Q. How the product Z can be prepared selectively using X and Y and other reagents?

Treating Y first with LDA followed by subsequent addition of X

Treating X first with LDA followed by subsequent addition of Y

Treating mixture of X and Y with LDA

Treating mixture of X and Y with NaOH and continuous removal of Z [LDA = Lithium diisopropyl amide [(CH 3 ) 2 CH 2 NLi]

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NEET Exam > NEET Tests > Test: Cannizzaro Reaction - NEET MCQ

Test: Cannizzaro Reaction - NEET MCQ

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23 Questions MCQ Test - Test: Cannizzaro Reaction

Test: Cannizzaro Reaction for NEET 2024 is part of NEET preparation. The Test: Cannizzaro Reaction questions and answers have been prepared according to the NEET exam syllabus.The Test: Cannizzaro Reaction MCQs are made for NEET 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Cannizzaro Reaction below.

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Test: Cannizzaro Reaction - Question 1

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Only One Option Correct Type

Direction (Q. Nos. 1-10) This section contains 10 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct.

Q.

The major organic product in the following reaction is

Detailed Solution for Test: Cannizzaro Reaction - Question 1

Test: Cannizzaro Reaction - Question 2

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Consider the following reaction,

Detailed Solution for Test: Cannizzaro Reaction - Question 2

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Test: Cannizzaro Reaction - Question 3

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Which is the best hydride (H^-) donor in the key step of Cannizaro reaction?

Detailed Solution for Test: Cannizzaro Reaction - Question 3

Dianion is better hydride donor. Also the electron donating group (CH₃O) increases hydride (H^-) donating a bility .

Test: Cannizzaro Reaction - Question 4

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Consider the following reaction,

The major organic product is

A.
B.
CH₃CH₂OH + CH₃COOH
C.
CH₃CH₂OH
D.
CH₃COOC₂H₆

Detailed Solution for Test: Cannizzaro Reaction - Question 4

It is a simple Tischenko reaction

Test: Cannizzaro Reaction - Question 5

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What is the major organic product in the following reaction?

A.
CH₃—C(CH₂OH)₃
B.
CH₃OH
C.
HCOOH
D.
Both (a) and (c)

Detailed Solution for Test: Cannizzaro Reaction - Question 5

Test: Cannizzaro Reaction - Question 6

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Predict the major organic product in the following reaction.

Detailed Solution for Test: Cannizzaro Reaction - Question 6

Intramolecular Cannizaro reaction occur.

Test: Cannizzaro Reaction - Question 7

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Whta is the major organic product formed in the follwing reaction ?

Detailed Solution for Test: Cannizzaro Reaction - Question 7

Test: Cannizzaro Reaction - Question 8

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For a Cannizaro reaction,

Rate law is derived as : Rate = k [RCHO]² [HO^-]²
From the above rate law, it can be concluded that

A.
reaction is pseudo 2nd orde
B.
reaction involves hydride ion transfer
C.
reaction does not show kinetic isotopic effect
D.
hydride donor is a dianion

Detailed Solution for Test: Cannizzaro Reaction - Question 8

For formation of dianion hydride donor, an additional mole of NaOH is consumed

Hence, rate becomes 2nd order with respect to HO^- and fourth order overall.

Test: Cannizzaro Reaction - Question 9

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Consider the following reaction,

How the product Z can be prepared selectively using X and Y and other reagents?

A.
Treating Y first with LDA followed by subsequent addition of X
B.
Treating X first with LDA followed by subsequent addition of Y
C.
Treating mixture of X and Y with LDA
D.
Treating mixture of X and Y with NaOH and continuous removal of Z [LDA = Lithium diisopropyl amide [(CH₃)₂CH₂NLi]

Detailed Solution for Test: Cannizzaro Reaction - Question 9

Test: Cannizzaro Reaction - Question 10

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What is the major product formed in the following intramolecular Cannizaro reaction?

Detailed Solution for Test: Cannizzaro Reaction - Question 10

—CHO para to electron withdrawing —NO₂ group is better hydride (H^-) acceptor.

*Multiple options can be correct

Test: Cannizzaro Reaction - Question 11

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One or More than One Options Correct Type

Direction (Q. Nos. 11-15) This section contains 5 multiple choice questions. Each question has four choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Consider the cross Cannizaro reaction given below

The expected product(s) is/are

A.
B.
C.
D.
C₆H₅CH₂OH

Detailed Solution for Test: Cannizzaro Reaction - Question 11

(I) is formed by nucleophilic attack in the first step. (I) may undergo intramolecular hydride transfer giving option (a) or may undergo intermolecuiar hydride transfer to C₆H₅CHO giving option (c) and option (d).

*Multiple options can be correct

Test: Cannizzaro Reaction - Question 12

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In the Cannizaro reaction mentioned below

The possible product(s) is/ar

A.
CH₃OH
B.
CH₃OD
C.
HCOOD
D.
H₂CDOH

Detailed Solution for Test: Cannizzaro Reaction - Question 12

*Multiple options can be correct

Test: Cannizzaro Reaction - Question 13

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What is/are the expected organic product(s) in the following reaction?

A.
B.
C.
CH₃OH
D.
HCOOH

Detailed Solution for Test: Cannizzaro Reaction - Question 13

It is a case of cross Cannizaro reaction in which formaldehyde is always oxidised and the other aldehyde is reduced. So, correct option B and D.

*Multiple options can be correct

Test: Cannizzaro Reaction - Question 14

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Consider the following reaction,

The expected organic product(s) is/are

A.
CH₃COOCH₂CH₂CH
B.
CH₃CH₂COOCH₂CH
C.
CH₃COOCH₂CH₃
D.
CH₃CH₂COOCH₂CH₂CH₃

Detailed Solution for Test: Cannizzaro Reaction - Question 14

It is a case of cross Tischenko reaction.

Here, both can be oxidised or both can be reduced. In the next step ester formation occur by all possible combination of acid and alcohols.

*Multiple options can be correct

Test: Cannizzaro Reaction - Question 15

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Consider the following reaction sequence,

The expected organic product(s) is/are

Detailed Solution for Test: Cannizzaro Reaction - Question 15

Test: Cannizzaro Reaction - Question 16

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Comprehension Type

Direction (Q. Nos. 16-18) This section contains a paragraph, describing theory, experiments, data, etc.
Three questions related to the paragraph have been given. Each question has only one correct answer mong the four given options (a), (b), (c) and (d).

Passage

When aldehydes lacking a-hydrogen is treated with concentrated solution of a strong base, Cannizaro reaction takes place. In this reaction, one molecule of aldehyde is oxidised while other is reduced. The widely accepted mechanism is

Step II

What is the rate law derived from the above mechanism?

A.
R = k [A—CHO] [HO^-]²
B.
R = k [A—CHO]² [HO^-]²
C.
R = k [A—CHO]² [HO^-]
D.
R = k [A—CHO]²

Detailed Solution for Test: Cannizzaro Reaction - Question 16

The intermediate “I” can be determined as
Substituting [I] in Eq (i) gives
R = k₁ K [ACHO]² [HO^-] = k [ACHO]² [OH^-']

Test: Cannizzaro Reaction - Question 17

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Step II

Which of the following observed fact establishes the correctness of the above mechanism?

A.
If A—COD is used, reaction occur at same rate provided all other conditions are same
B.
In mixed Cannizaro reaction, if one aldehyde is H₂CO, it is always oxidise
C.
If reaction is carried out in D₂O in the presence of NaOD, some C—D bond formation occur
D.
If reaction is carried out in D₂Oin the presence of NaOD, no C—D bond formation occur

Detailed Solution for Test: Cannizzaro Reaction - Question 17

When reaction is carried out in D,O , no C—D bond formation occur. It establishes the correctness of above mechanism that reaction proceed by H^- (hydride) transfer in the slow rate determining step.

Test: Cannizzaro Reaction - Question 18

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Step II

In certain experim ental condition, rate is found to be proportional to square of concentration of base (OH^-).This indicates that

A.
with change in condition, Step I may become slow, rate determining step
B.
dianion intermediate is acting as hydride (H^-) don
C.
Both Step I and Step II occur at comparable rate
D.
mechanism changes with nature of aldehyde

Detailed Solution for Test: Cannizzaro Reaction - Question 18

Formation of dianion involves two moles of HO^- per mole of aldehyde

Test: Cannizzaro Reaction - Question 19

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Matching List Type

Direction (Q. Nos. 19 and 20) Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct.

Consider the reactions of Column I and match with the products of Column II. Mark the correct option from the codes given below.

A.
a
B.
b
C.
c
D.
d

Detailed Solution for Test: Cannizzaro Reaction - Question 19

(i) is better H^- acceptor, reduced to FCH₂OH.
(ii) CH₂O is oxidised and C₆H₅CHO is reduced in cross Cannizaro reaction.
(iii) Electron withdrawing —NO₂ makes —CHO a better hydride acceptor, hence p-nitrobenzaldehyde is reduced and benzaldehyde is oxidised.
(iv) p-nitrobenzaldehyde is reduced, p-methoxy benzaldehyde becomes better hydride donor after attack by HO^-, hence oxidised.

Test: Cannizzaro Reaction - Question 20

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Match the reactions of Column I with the type of reactions from Column II. Mark the correct option from the codes given below.

A.
a
B.
b
C.
c
D.
d

Detailed Solution for Test: Cannizzaro Reaction - Question 20

(i) Initially, aldol reaction followed by Cannizaro reaction giving C(CH₂OH)4 + HCOOH.
(ii) F—CHO undergo Cannizaro reaction due to absence of α -H.
(iii) It has difficulty in aldol condensation, hence undergo Cannizaro reaction predominantly.
(iv) All aldol, Cannizaro and Claisen reaction occur.

*Answer can only contain numeric values

Test: Cannizzaro Reaction - Question 21

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One Integer Value Correct Type

Direction (Q. Nos. 21-23) This section contains 3 questions. When worked out will result in an integer from 0 to 9 (both inclusive).

Consider the following Cannizaro reaction,

How many different products are formed?

Detailed Solution for Test: Cannizzaro Reaction - Question 21

Possible products are

*Answer can only contain numeric values

Test: Cannizzaro Reaction - Question 22

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Consider the following Cannizaro reaction,

How many different products are expected in this reaction?

Detailed Solution for Test: Cannizzaro Reaction - Question 22

Possible products are

*Answer can only contain numeric values

Test: Cannizzaro Reaction - Question 23

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Consider the following reaction,

If CH₃OH is formed exclusively by hydride transfer from a dianion intermediat what is the overall order of reaction?

Detailed Solution for Test: Cannizzaro Reaction - Question 23

If dianion is hydride donor, the rate law is
R = k [H₂CO]² [OH^-]²
Hence, reaction is overall fourth order.

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