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Basic Concepts - 1 - GATE EE Network Theory Free MCQ Test with solutions


MCQ Practice Test & Solutions: Test: Basic Concepts - 1 (10 Questions)

You can prepare effectively for Electrical Engineering (EE) Network Theory (Electric Circuits) with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Basic Concepts - 1 ". These 10 questions have been designed by the experts with the latest curriculum of Electrical Engineering (EE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 10

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Test: Basic Concepts - 1 - Question 1

A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere is

Detailed Solution: Question 1

The charge (Q) on an object can be calculated using the formula:
Q = n × e

Where:

  • n = number of electrons removed = 1020 electrons
  • e = charge of a single electron = 1.6 × 10-19 C

Now, substitute the values into the formula:

Therefore, the charge on the sphere is 16.02 C.

Thus, the correct answer is D: 16.02 C.

Test: Basic Concepts - 1 - Question 2

A lightning bolt carrying 15,000 A lasts for 100 μs. If the lightning strikes an airplane flying at 2 km, the charge deposited on the plane is

Detailed Solution: Question 2

Test: Basic Concepts - 1 - Question 3

If 120 C of charge passes through an electric conductor in 60 sec, the current in the conductor is

Detailed Solution: Question 3

Test: Basic Concepts - 1 - Question 4

The energy required to move 120 coulomb through 3V is

Detailed Solution: Question 4

The energy (E) required to move a charge (Q) through a potential difference (V) is given by the formula:
E = Q x V

Where:

  • Q = 120 coulombs
  • V = 3 volts

Now, substitute the values into the formula:
E = 120 x 3 = 360 Joules

Therefore, the energy required is 360 Joules.
Answer: B: 360 J

Test: Basic Concepts - 1 - Question 5

i = ?

Detailed Solution: Question 5

Test: Basic Concepts - 1 - Question 6

In the circuit of fig P1.1.6 a charge of 600 C is delivered to the 100 V source in a 1 minute. The value of v1 must be

Detailed Solution: Question 6

In order for 600 C charge to be delivered to the 100 V source, the current must be anticlockwise.

Applying KVL we get

Test: Basic Concepts - 1 - Question 7

In the circuit of the fig P1.1.7, the value of the voltage source E is

Detailed Solution: Question 7

Going from 10 V to 0 V

10 + 5 + E + 1 + 0 = 0 or E =-16 V

Test: Basic Concepts - 1 - Question 8

Consider the circuit graph shown in fig. P1.1.8. Each branch of circuit graph represent a circuit element. The value of voltage v1 is

Detailed Solution: Question 8

To determine the value of voltage v1, we can analyse the circuit graph. The following steps outline the process:

  • Identify the components and their values in the circuit.
  • Apply Kirchhoff's laws to find the relationships between the voltages and currents.
  • Calculate the voltage across each branch, considering the polarity and direction of current flow.
  • Combine the results to find v1.

After performing the calculations based on the circuit parameters, we find that the value of v1 is:

  • 15 V

Test: Basic Concepts - 1 - Question 9

For the circuit shown in fig P.1.1.9 the value of voltage vo is

Detailed Solution: Question 9

Voltage is constant because of 15 V source.

Test: Basic Concepts - 1 - Question 10

R1 = ?​

Detailed Solution: Question 10

Voltage across 60 Ω resistor = 30 V

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