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Test: Basic Concepts - 1 - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test - Test: Basic Concepts - 1

Test: Basic Concepts - 1 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Basic Concepts - 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Basic Concepts - 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Basic Concepts - 1 below.
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Test: Basic Concepts - 1 - Question 1

A solid copper sphere, 10 cm in diameter is deprived of 1020 electrons by a charging scheme. The charge on the sphere is

Detailed Solution for Test: Basic Concepts - 1 - Question 1

Let's calculate the charge on the sphere

Understanding the problem:

  • A copper sphere loses 10^20 electrons.
  • We need to find the total charge on the sphere.

Solution:

  • Charge of one electron (e) = -1.6 x 10^-19 C
  • Number of electrons removed (n) = 10^20

Total charge (Q) = n * e

Q = 1020 * (-1.6 x 10^-19 C) Q = -1.632 x 10^-16 C

Approximately, Q = -16.02 x 10^-17 C

Therefore, the charge on the sphere is -16.02 C.

So, the correct answer is:

4. -16.02 C

Note that the charge is negative because electrons are removed, leaving a net positive charge on the sphere.

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Test: Basic Concepts - 1 - Question 2

A lightning bolt carrying 15,000 A lasts for 100 μs. If the lightning strikes an airplane flying at 2 km, the charge deposited on the plane is

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Test: Basic Concepts - 1 - Question 3

If 120 C of charge passes through an electric conductor in 60 sec, the current in the conductor is

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Test: Basic Concepts - 1 - Question 4

The energy required to move 120 coulomb through 3V is

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W = Qv = 360J

Test: Basic Concepts - 1 - Question 5

i = ?

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Test: Basic Concepts - 1 - Question 6

In the circuit of fig P1.1.6 a charge of 600 C is delivered to the 100 V source in a 1 minute. The value of v1 must be

Detailed Solution for Test: Basic Concepts - 1 - Question 6

In order for 600 C charge to be delivered to the 100 V source, the current must be anticlockwise.

Applying KVL we get

Test: Basic Concepts - 1 - Question 7

In the circuit of the fig P1.1.7, the value of the voltage source E is

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Going from 10 V to 0 V

10 + 5 + E + 1 + 0 = 0 or E =-16 V

Test: Basic Concepts - 1 - Question 8

Consider the circuit graph shown in fig. P1.1.8. Each branch of circuit graph represent a circuit element. The value of voltage v1 is

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Test: Basic Concepts - 1 - Question 9

For the circuit shown in fig P.1.1.9 the value of voltage vo is

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Voltage is constant because of 15 V source.

Test: Basic Concepts - 1 - Question 10

R1 = ?​

Detailed Solution for Test: Basic Concepts - 1 - Question 10

Voltage across 60 Ω resistor = 30 V

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