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Test: Network Theorems - 1 - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test - Test: Network Theorems - 1

Test: Network Theorems - 1 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Network Theorems - 1 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Network Theorems - 1 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Network Theorems - 1 below.
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Test: Network Theorems - 1 - Question 1

vTH, RTH, = ?

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Test: Network Theorems - 1 - Question 2

iN, RN = ?

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Test: Network Theorems - 1 - Question 3

vTH, RTH = ?

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Test: Network Theorems - 1 - Question 4

A simple equivalent circuit of the 2 terminal network shown in fig. P1.4.4 is

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After killing all source equivalent resistance is R Open circuit voltage = v1

Test: Network Theorems - 1 - Question 5

iN, RN, = ?

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The short circuit current across the terminal is

Test: Network Theorems - 1 - Question 6

vTH, RTH = ?

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For the calculation of RTH if we kill the sources then 20 Ω resistance is inactive because 5 A source will be open circuit

Test: Network Theorems - 1 - Question 7

RTH = ?

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To determine RTHR_{TH}RTH​, the Thevenin equivalent resistance of the given circuit, follow these steps:

  1. Turn off all independent sources:

    • The 2A current source will be open-circuited.
    • The 5V voltage source will be short-circuited.
  2. Analyze the resulting circuit:

    • After turning off the sources, the 6Ω resistors are left connected in parallel.

Here's the process step-by-step:

  1. Turn off the current source:

    • Open-circuit the 2A current source.
  2. Turn off the voltage source:

    • Short-circuit the 5V voltage source.

Test: Network Theorems - 1 - Question 8

The Thevenin impedance across the terminals ab of the network shown in fig. P.1.4.8 is

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After killing all source,

Test: Network Theorems - 1 - Question 9

For In the the circuit shown in fig. P.1.4.9 a network and its Thevenin and Norton equivalent are given

The value of the parameter are

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Test: Network Theorems - 1 - Question 10

v1 = ?

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If we solve this circuit direct, we have to deal with three variable. But by simple manipulation variable can be reduced to one. By changing the LHS and RHS in Thevenin equivalent

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