Test: Network Theorems - 2 - Electrical Engineering (EE) MCQ

If we solve this circuit direct, we have to deal with three variable. But by simple manipulation variable can be reduced to one. By changing the LHS and RHS in Thevenin equivalent

Thevenin equivalent seen from terminal yy' is

Thevenized the circuit across R, R_TH = 2 Ω

Since both source have opposite polarity, hence short circuit the all straight-through connection as shown in fig. S.1.4.33

Let Thevenin equivalent of both network

using superposition 

 0.8
146.93

Thevenin Theorem

Thevenin’s theorem states that it is possible to simplify any linear circuit, into an equivalent circuit with a single voltage source and a series resistance.

Steps to calculate:

1. Thevenin Resistance (R_th): Open the circuit to the terminal from where the Thevenin resistance has to be found. While finding the Rth, short circuit the independent voltage source and open circuit the independent current source.
2. Thevenin Voltage (V_th): This is the open-circuit voltage across the terminals where the load was connected.

Calculation

The voltage drop across 5Ω is: 

V = 5 × 10 = 50 volts

Applying KVL in loop:

-12 + V - 50 = 0

V = 62 volts