Test: Conductance of Electrolytic Solutions - NEET MCQ

Specific conductance of 0.01 N KCI solution is x Scm^-1 having conductance y S. Thus, specific conductance of 0.01 N NaCI having conductance zS is (in S cm^-1)

In terms of  (molar conductance), (molar conductance of very dilute solution) ionisation constant (K_a) of weak acid is

Given limiting ionic conductance of  H⁺  ion :  = 350 S cm² equi^-1 and of  ion :  = 80 S cm² equi^-1 Thus for H₂SO₄, limiting values of molar conductance and equivalent conductance are

500 mL of an aqueous solution contains 0.1 mole of KCl. If its specific conductance is x Scm^-1, its molar conductance will be (in Scm² mol^-1)

Resistivity of a metal is equal to resistance when cell is constant is

Cell constant is maximum in case of a

Which quantity is temperature independent?

0.1 M H₂SO₄ solution is diluted to 0.01 M H₂SO₄ ?.Hence its molar conductivity will be 

Conductivity (Siemen's S) is directly proportional to the area of the vessel and the concentration of the solution in it, and is inversely proportional to the length of the vessel,then constant of proportionality is expressed in

Given, (Scm² mol^-1)for different electrolytes

Thus, of CH₃COOH is

Resistance of 0.2 M soluton of an electrolyte is 50?. The specific conductance of solution is 1.3 Sm^-1. If resistance of the 0.4 M solution of the same electrolyte is 260Ω, its molar conductivity is

[AlEEE 2011]

The equivalent conductance of NaCl at concentration C and at infinite dilution are λ_c and λ_∞ respectively.The correct relationship λ_c and λ_∞ between  is given as (where constanr B is positive).

At 298 K, given specific conductance of saturated
AgCl solution=3.41 x 10^-6 Ω^-1 cm^-1 and that of water used =1.60 x 10^-6 Ω^-1 cm^-1.
Equivalent conductance of saturated AgCl solution= 138.3 Ω^-1 cm² equiv^-1

Thus, solubility product (K_Sp) of AgCl is

AgNO_{3 (aq)} was added to an aq. KCl solution gradually and the conductivity of the solution was measured.the plot of conductance vs the volume of AgNO₃ is

[IIT JEE 2011]

Resistance of 0.2 M solution of an electrolyte is 50Ω.The specific conductance of this solution is 1.4 Sm^-1. The resistance  0.5 M solution of the same electrolyte is 280Ω. The molar conductivity of 0.5 solution of the electrolyte in Sm²mol^-1 is

[JEE Main 2014]

One or More than One Options Correct Type

This section contains 5 multiple type questions. Each question has 4 choices (a), (b), (c) and (d), out of which ONE or MORE THAN ONE are correct.

Q.

Equivalent conductance of 0.01 N CaCl₂ solution is 126.36 S cm² equiv^-1. This is equal to

Degree of dissociation of very pure water is 1.9 x 10^-9. Also limiting molar conductance of λ₀(H⁺) = 350 Scm² equiv^-1 ,  λ₀(OH⁺) = 200 Scm² equiv^-1

Thus,equivalent conductance of water is

Select the correct statement(s).

Matching List Type

Choices for the correct combination of elements from Column I and Column II are given as options (a), (b), (c) and (d), out of which one is correct

Q.

An aqueous solution of X is added slowly to an aqueous solution of Y as Shown in column I.The variation in conductivity of these reactions is given in Column II.Match Column I with Column II and select the correct answer using the codes given below the lists.

Limiting equivalent conductance (in S cm² equiv^-1) of a weak monobasic acid (HA) at infinite dilution is 100 and that of its 0.01 M solution is 5 at 298K.Match the parameters given in Column I with their values in Column II and select the answer from the codes given.           

Comprehension Type

Direction : This section contains 2 paragraphs, each describing theory, experiments, data, etc. Four questions related to the paragraphs have been given. Each question has only one correct answer among the four given options (a), (b), (c) and (d).

Passage I

Consider the following solutions of an electrolyte 

Q. 

Conductivity.of 0.2 M solution is

Passage I

Consider the following solutions of an electrolyte 

Q.

Molar conductivity of 0.2 M solution is

Passage II

Given molar conductance of 0.001 M NH₄OH solution at 298K = 3.0 x 10^-3Sm²mol^-1.
Limiting molar conductance of

aq. NH₄CI = 1.50 x 10^-2Sm²mol^-1

aq. NaCl = 1.26 x 10^-2Sm² mol^-1

and aq. NaOH = 2.48 x 10^-2 Sm² mol^-1

Q.

Degree of dissociation of NH₄OH at 298 K is 

Passage II

Given molar conductance of 0.001 M NH₄OH solution at 298K = 3.0 x 10^-3Sm²mol^-1.
Limiting molar conductance of

aq. NH₄CI = 1.50 x 10^-2Sm²mol^-1

aq. NaCl = 1.26 x 10^-2Sm² mol^-1

and aq. NaOH = 2.48 x 10^-2 Sm² mol^-1

Q.

pK_b of NH₄OH  is

One Integer Value Correct Type

This section contains 2 questions, when worked out will result in an integer value from 0 to 9 (both inclusive)

Q.

0.01 M aqueous solution of a dibasic acid is diluted to 0.004N such that equivalent conductance is x times.What is the value of x?

At what serial number reciprocal of resistance is given?

(1) Volt
(2) Ampere
(3) Coulomb
(4) Faraday
(5) Conductivity
(6) Resistivity
(7) Siemen
(8) Debye

Only One Option Correct Type

This section contains 1 multiple choice question. A question has four choices (a), (b), (c) and (d), out of which ONLY ONE is correct

 Q.

The equivalent conductance of two strong electrolytes at infinite dilution in H₂O
(where ions move freely through a solution) at 25^°C are given below: 

Q.

What additional information/quantity are needed to calculate of an aqueous solution of acetic acid?