Electrical Engineering (EE) Exam > Electrical Engineering (EE) Tests > Test: Transient Response of DC & AC Networks - 1 - Electrical Engineering (EE) MCQ
Test: Transient Response of DC & AC Networks - 1 - Electrical Engineering (EE) MCQ
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Test: Transient Response of DC & AC Networks - 1 - Question 1
The natural response of an RLC circuit is described by the differential equation
The v(t) is
The v(t) is
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Test: Transient Response of DC & AC Networks - 1 - Question 2
The differential equation for the circuit shown in fig. P1.6.2. is
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Test: Transient Response of DC & AC Networks - 1 - Question 3
The differential equation for the circuit shown in fig. P1.6.3 is
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Test: Transient Response of DC & AC Networks - 1 - Question 4
In the circuit of fig. P.1.6.4 vs = 0 for t > 0. The initial condition are v(0) = 6 V and dv(0) dt = -3000 Vs. The v(t) for t > 0 is
Detailed Solution for Test: Transient Response of DC & AC Networks - 1 - Question 4
Test: Transient Response of DC & AC Networks - 1 - Question 5
The circuit shown in fig. P1.6.5 has been open for a long time before closing at t = 0. The initial condition is v(0) = 2 V. The v(t) for t > is
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Test: Transient Response of DC & AC Networks - 1 - Question 6
Circuit is shown in fig. P.1.6. Initial conditions are i1(0) = i2(0) = 11A
Q. i1 (1 s) = ?
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Test: Transient Response of DC & AC Networks - 1 - Question 7
Circuit is shown in fig. P.1.6. Initial conditions are i1(0) = i2(0) = 11A
Q. i2 (1 s) = ?
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Test: Transient Response of DC & AC Networks - 1 - Question 9
The circuit shown in fig. P1.6.9 is in steady state with switch open. At t = 0 the switch is closed. The output voltage vC(t) for t > 0 is
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Test: Transient Response of DC & AC Networks - 1 - Question 10
The switch of the circuit shown in fig. P1.6.10 is opened at t = 0 after long time. The v(t) , for t > 0 is
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