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Test: Probability Part:- 1 - Mathematics MCQ


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20 Questions MCQ Test - Test: Probability Part:- 1

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Test: Probability Part:- 1 - Question 1

A fair dice is rolled twice. The probability that an odd number will follow an even number is 

Detailed Solution for Test: Probability Part:- 1 - Question 1

Here the sample space S = 6
Therefore P(even number) = 3/6 = 1/2
since events are independent, therefore, p(odd/even) = 1/2 x 1/2 = 1/4

Test: Probability Part:- 1 - Question 2

A probability density function is of the form

The value of K is 

Detailed Solution for Test: Probability Part:- 1 - Question 2

As (x) is a probability density funciton

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Test: Probability Part:- 1 - Question 3

Three companies X, Y and Z supply computers to a university. The percentage of computers supplied by them and the probability of those being defective are tabulated below 

Given that a computer is defective, the probability that it was supplied by Y is

Test: Probability Part:- 1 - Question 4

If E denotes expectation, the variance of a random variable X is given by

Detailed Solution for Test: Probability Part:- 1 - Question 4

Test: Probability Part:- 1 - Question 5

An examination consists of two papers, Paper 1 and Paper 2. The probability of failing in Paper 1 is 0.3 and that in Paper 2 is 0.2. Given that a student has failed in Paper 2, the probability of failing in Paper 1 is 0.6. The probability of a student failing in both the papers is

Detailed Solution for Test: Probability Part:- 1 - Question 5

Let A be the event that 'faied in paper 1'.
B be the event that 'failed in paper 2'.
Given P(A) = 0.3, P(B) = 0.2.
And also given 
we know 
⇒ P(A∩B) = 0.6 x  0.2 = 0.12

Test: Probability Part:- 1 - Question 6

Px(x) = M exp(–2|x|) – N exp(–3 |x|) is the probability density function for the real random variable X, over the entire x axis. M and N are both positive real numbers. The equation relating M and N is

Detailed Solution for Test: Probability Part:- 1 - Question 6

Given Px (x ) is the probability density function for the random variable X.

Test: Probability Part:- 1 - Question 7

A fair coin is tossed 10 times. What is the probability that ONLY the first two tosses will yield heads? 

Detailed Solution for Test: Probability Part:- 1 - Question 7

Let A be the event that first toss is head
And B be the event that second toss is head.

By the given condition rest all 8 tosses should be tail
∴ The probability of getting head in first two cases

Test: Probability Part:- 1 - Question 8

A fair coin is tossed independently four times. The probability of the event "the number of time heads shown up is more than the number of times tails shown up" is

Detailed Solution for Test: Probability Part:- 1 - Question 8

Here we have to find
P(H,H,H,T) + P(H,H,H,H)

Test: Probability Part:- 1 - Question 9

In a manufacturing plant, the probability of making a defective bolt is 0.1. The mean and standard deviation of defective bolts in a total of 900 bolts are respectively

Detailed Solution for Test: Probability Part:- 1 - Question 9

It’s a poission distribution. Here n = 900, p = 0.1
∴ mean (m)= np = 900 × 0.1 = 90
Standard deviat ion (σ)= 
= √81 = 9 (∵ σ > 0).,

Test: Probability Part:- 1 - Question 10

Consider the continuous random variable with probability density function
f(t) = 1 + t for -1 ≤ t ≤ 0
= 1 - t for 0 ≤ t ≤ 1
The standard deviation of the random variables is 

Detailed Solution for Test: Probability Part:- 1 - Question 10

Var 
T being the random variable of f(t).

Test: Probability Part:- 1 - Question 11

The standard deviation of a uniformly distributed random variable between 0 and 1 is

Detailed Solution for Test: Probability Part:- 1 - Question 11

Here p.d.f is f(x) = 
∴ mean(m) = E(x) = 
∴ Var (x) =  
∴ 

Test: Probability Part:- 1 - Question 12

The probability that two friends share the same birth-month is

Detailed Solution for Test: Probability Part:- 1 - Question 12

Let A = the event that the birth month of first friend
And B= that of second friend. 
∴ P( A )= 1, as 1st friend can born in any month
and P(B) = 1/12, by the condition.
∴ Probability of two friends share same birth-month is 1 x 1/12 = 1/12

Test: Probability Part:- 1 - Question 13

The probability of a defective piece produced in a manufacturing process is 0.01. The probability that out of 5 successive pieces, only one is defective, is

Detailed Solution for Test: Probability Part:- 1 - Question 13

The required probability = 

Test: Probability Part:- 1 - Question 14

A box contains 5 block balls and 3 red balls. A total of three balls are picked from the box one after another, without replacing them back. The probability of getting two black balls and one red ball is

Detailed Solution for Test: Probability Part:- 1 - Question 14

Here the possible combination of picking up three balls without replacement is BBR, BRB, RBB
(B = Black ball, R = Red balls)

∴ Probability of getting two black balls and one red ball is 15/28.

Test: Probability Part:- 1 - Question 15

An unbiased coin is tossed three times. The probability that the head turns up in exactly two cases is 

Detailed Solution for Test: Probability Part:- 1 - Question 15

Required probability = 

Test: Probability Part:- 1 - Question 16

Two dice are thrown. What is the probability that is the sum of the numbers on the two dice is eight?

Detailed Solution for Test: Probability Part:- 1 - Question 16

Here sample space = 6 × 6 = 36
Here, there are five such points whose sum is 8. They are (2,6), (3,5), (4,4),  (5,3), (6,2). 
∴ Requireprobability = 5/36

Test: Probability Part:- 1 - Question 17

Manish has to travel from A to D changing buses at stops B and C enroute. The maximum waiting time at either stop can be 8 minutes each, but any time of waiting up to 8 minutes is equally likely at both places. He can afford up to 13 minutes of total waiting time if he is to arrive at D on time. What is the probability that Manish will arrive late at D?

Test: Probability Part:- 1 - Question 18

Arrivals at a telephone booth are considered to be poison, with an average time of 10 minutes between successive arrivals. The length of a phone call is distributes exponentially with mean 3 minutes. The probability that an arrival does not have to wait before service is

Test: Probability Part:- 1 - Question 19

A box contains 5 black and 5 red balls. Two balls are randomly picked one after another from the box, without replacement. The probability for both balls being red is

Detailed Solution for Test: Probability Part:- 1 - Question 19

The probability of drawing two red balls without replacement

Test: Probability Part:- 1 - Question 20

From a pack of regular from a playing cards, two cards are drawn at random. What is the probability that both cards will be Kings, if first card in NOT replaced

Detailed Solution for Test: Probability Part:- 1 - Question 20

Here sample space S = 52 
∴The probability  of drawing both cards are king without replacement  

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