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Test: Methods of Indeterminate Analysis -1 - Civil Engineering (CE) MCQ


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10 Questions MCQ Test - Test: Methods of Indeterminate Analysis -1

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Test: Methods of Indeterminate Analysis -1 - Question 1

The following methods are used for structural analysis:
1. Macaulay method
2. Column analogy method
3. Kani’s method
4. Method of sections

Those used for indeterminate structural analysis would include

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 1

Macaulay's method is used for deflection and slope calculation due to point loads in prismatic beams. Method of sections is used for statically determinate trusses.

Test: Methods of Indeterminate Analysis -1 - Question 2

Match List-l (Names of persons with whom the methods of analysis are associated) with List-ll (Method) and select the correct answer using the codes given below the lists:
List-l
1. Clapeyron
2. Hardy cross
3. Lame
4. Euler 

List-ll
A. Moment distribution method
B. Method for determining crippling load on a column
C. Theorem of Three moment
D. Thick cylinders

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Test: Methods of Indeterminate Analysis -1 - Question 3

A loaded porta! frame is shown in figure. The profile of its Bending Moment diagram will be

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 3

- The horizontal force will be distributed to both the supports.
- The bending moment at hinged end will be zero and fixed end will have some B.M.
- The B.M.D. for columns will be linear.
- The B.M.D. for beam will be parabolic.
The choice now remains between (b) and (d). In diagram (b) and (c) the Left column has negative B.M. in upper half or at top. The beam at left end in (b) shows negative B.M. while in (c) it shows a positive B.M.

Test: Methods of Indeterminate Analysis -1 - Question 4

The given figure shows a portal frame with one end fixed and other hinged. The ratio of the fixed end moments MBA/MCD due to side sway will be

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 4

Due to sway, the deflection of point B will be equal to that of point C.

Test: Methods of Indeterminate Analysis -1 - Question 5

The distribution factors for members CB, CD and CG for the frame shown in the figure ( EI constant) will be respectively

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 5

Test: Methods of Indeterminate Analysis -1 - Question 6

A fixed beam AB is subjected to a triangular load varying from zero at end A to W per unit length at end B. The ratio of fixed end moment at A to B will be

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 6


Test: Methods of Indeterminate Analysis -1 - Question 7

The fixed end moment MA for the beam shown in the given figure is

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 7

For part BD.

For Part AB

Test: Methods of Indeterminate Analysis -1 - Question 8

If the flexural rigidity of the beam BC of the portal frame shown in the given figure is assumed to be zero, then the horizontal displacement of the beam would be

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 8

As the beam BC has no rigidity, so end B of column behaves as free end.
For a cantilever beam subjected to concentrated load at free end, the stiffness is 3EI/L3
Stiffness of given system,

Test: Methods of Indeterminate Analysis -1 - Question 9

A portal frame is shown in the given figure. If θB - θc = 400/EI radian, then the value of moment at B will be

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 9

The deformed shape of structure will have translation at B and C,

Test: Methods of Indeterminate Analysis -1 - Question 10

For the frame as shown in the figure below, the final end moment MBC has been calculated as -40 kN-m. What is the end moment MCD?

Detailed Solution for Test: Methods of Indeterminate Analysis -1 - Question 10

The shear force at end A should be equal and opposite to shear force at D, Let -40 kN-m denotes the clockwise moment so moment at end B of column AB is 40 kN-m anticiockwise and the shear force at A is10 kN towards left.
Therefore shear force at D is 10 kN towards right. Thus end moment at C is 30 kN-m clockwise or -30 kN-m.

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