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Test: Determinacy & Indeterminacy -1 - Civil Engineering (CE) MCQ


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10 Questions MCQ Test - Test: Determinacy & Indeterminacy -1

Test: Determinacy & Indeterminacy -1 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Determinacy & Indeterminacy -1 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Determinacy & Indeterminacy -1 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Determinacy & Indeterminacy -1 below.
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Test: Determinacy & Indeterminacy -1 - Question 1

Total degree of indeterminacy (both internal and external) of the plane frame shown in the given figure is

Detailed Solution for Test: Determinacy & Indeterminacy -1 - Question 1

The degree of indeterminacy,

Number of external reactions = re
= 3 + 3 + 3 + 3 = 12
Number of rigid joints,
j= 10
Number of joints at which releases are located, 
j= 1
Number of members, 
m = 12
As the hinge is located at a point where 4 members meet. Hence it is equivalent to three hinges.
Therefore number of releases, r= 3.

Test: Determinacy & Indeterminacy -1 - Question 2

If there are m unknown member forces, r unknown reaction components and j number of joints, then the degree of static indeterminacy of a pin-jointed plane frame is given by​

Detailed Solution for Test: Determinacy & Indeterminacy -1 - Question 2

Ds for a pin jointed frame = m+r-2j
Ds for a rigid jointed frame = 3m+r -3j
m- No. of members, r- no. of reactions, j- no. of joints

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Test: Determinacy & Indeterminacy -1 - Question 3

Degree of kinematic indeterminacy of a pin jointed plane frame is given by where j is number of joints and r is reaction components.

Detailed Solution for Test: Determinacy & Indeterminacy -1 - Question 3

Dk = 2j –r for a pin jointed frame
Dk = 3j –r for a rigid jointed frame
j number of joints and r number of reactions.

Test: Determinacy & Indeterminacy -1 - Question 4

A pin-jointed plane frame is unstable if where m is number of members r is reaction components and j is number of joints

Test: Determinacy & Indeterminacy -1 - Question 5

The degree of static indeterminacy of a pin- jointed space frame is given by

Test: Determinacy & Indeterminacy -1 - Question 6

The degree of kinematic indeterminacy of a pin-jointed space frame is given by

Detailed Solution for Test: Determinacy & Indeterminacy -1 - Question 6

- Kinematic indeterminacy refers to the number of possible independent movements of a structure.
- For a pin-jointed space frame, each joint has 3 degrees of freedom (translations in x, y, and z directions).
- Formula: (3j - r), where (j) is the number of joints and (r) is the number of reaction components or constraints.
- This formula accounts for the three-dimensional nature of space frames, unlike planar frames, which have 2 degrees of freedom per joint.

Test: Determinacy & Indeterminacy -1 - Question 7

The degree of static indeterminacy of the pin- jointed plane frame shown in figure is

Detailed Solution for Test: Determinacy & Indeterminacy -1 - Question 7

External indeterminacy,

Internal indeterminacy,

No, of members, m = 21
Number of joints, j = 11

Test: Determinacy & Indeterminacy -1 - Question 8

The portal frame as shown in the given frame is statically indeterminate to the

Detailed Solution for Test: Determinacy & Indeterminacy -1 - Question 8

m=3; r= 3+3 =6 ; j=4
Ds = 3m+r-3j = 3(3) + 6 -3(4) = 3

Test: Determinacy & Indeterminacy -1 - Question 9

A perfect plane frame having n number of members and j number of joints should satisfy the relation​

Detailed Solution for Test: Determinacy & Indeterminacy -1 - Question 9

A perfect plane frame means a determinate structure, so

Test: Determinacy & Indeterminacy -1 - Question 10

Neglecting axial deformation, the kinematic indeterminacy of the structure shown in the figure below is

Detailed Solution for Test: Determinacy & Indeterminacy -1 - Question 10

j = 11; r=8; m=11
Dk = 3j-r-no. of inextensible members = 3(11) – 8 -11 = 14

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