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Test: Principal Stress & Strain - 2 - Civil Engineering (CE) MCQ


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10 Questions MCQ Test - Test: Principal Stress & Strain - 2

Test: Principal Stress & Strain - 2 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Principal Stress & Strain - 2 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Principal Stress & Strain - 2 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Principal Stress & Strain - 2 below.
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Test: Principal Stress & Strain - 2 - Question 1

If the principal stresses at point in a strained body are p1 and p2 ( p1 > p2), then th e resu lta n t stress on a plane carrying the maximum shear stress is equal to

Detailed Solution for Test: Principal Stress & Strain - 2 - Question 1

Plane of maximum shear is at 45°

Test: Principal Stress & Strain - 2 - Question 2

If ∈1 and ∈2 ( ∈1 > ∈2) are the m axim um and minimum strains in the neighbourhood of a point in a stressed material of Young’s modulus E and Poisson’s ratio p, then the maximum principal stress will be given by

Detailed Solution for Test: Principal Stress & Strain - 2 - Question 2

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Test: Principal Stress & Strain - 2 - Question 3

On the element shown below in the figure, the stress in MPa are

The radius of Mohr’s circle V and principal stresses σ1, and σ2 are in (MPa) respectively

Detailed Solution for Test: Principal Stress & Strain - 2 - Question 3


⇒ σ1,2 = 70 ± 50
∴ σ1 = 120 MPa
and σ2 = 20 MPa
and, radius of Mohr's circle

Test: Principal Stress & Strain - 2 - Question 4

The radius of Mohr’s circle gives the value of

Test: Principal Stress & Strain - 2 - Question 5

 A body is subjected to two normal strains of magnitude ∈x = 0.003 and ∈y = 0.002. The shearing strain on a plane inclined at 30° with ∈x is

Detailed Solution for Test: Principal Stress & Strain - 2 - Question 5

Shearing strain 
= (∈x - ∈y) sin2θ
= (0.003 - 0.002)sin60°
= √3/2 x 10-3

Test: Principal Stress & Strain - 2 - Question 6

Which one of the following Mohr’s circles represents the state of pure shear?

Test: Principal Stress & Strain - 2 - Question 7

 A bar is subjected to a uniaxial tensile stress ‘σ’. The tangential stress on a plane inclined at θ to the bar would be

Detailed Solution for Test: Principal Stress & Strain - 2 - Question 7

Normal sress = σ cos2 θ
Tangential Stress = σ sin θ cos θ

= σ sin 2θ/2

Test: Principal Stress & Strain - 2 - Question 8

Which of the following formulae is used to calculate tangential stress, when a member is subjected to stress in mutually perpendicular axis and accompanied by shear stress?

Test: Principal Stress & Strain - 2 - Question 9

Normal stresses of equal magnitude a, but of opposite signs, act at a point of a strained material in perpendicular direction. What is the magnitude of the stress on a plane inclined at 45° to the applied stresses?

Detailed Solution for Test: Principal Stress & Strain - 2 - Question 9


Here, σx = σy = -σ and θ = 45°
∴ σθ = 0

Test: Principal Stress & Strain - 2 - Question 10

Two planes xyand yz are passing through a point in a strained material. The normal and shear stresses on xy plane are +80 MPa, -30 MPa respectively and normal and shear stresses on plane yz are +30 MPa and +30 MPa respectively. What is the angle between the planes?

Detailed Solution for Test: Principal Stress & Strain - 2 - Question 10


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