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Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  Test: Gears - 2 - Mechanical Engineering MCQ

Test: Gears - 2 - Mechanical Engineering MCQ


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10 Questions MCQ Test - Test: Gears - 2

Test: Gears - 2 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Gears - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Gears - 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Gears - 2 below.
Solutions of Test: Gears - 2 questions in English are available as part of our course for Mechanical Engineering & Test: Gears - 2 solutions in Hindi for Mechanical Engineering course. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Attempt Test: Gears - 2 | 10 questions in 30 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study for Mechanical Engineering Exam | Download free PDF with solutions
Test: Gears - 2 - Question 1
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Lewis equation is applied

Test: Gears - 2 - Question 2
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Match the following parameter pertaining to helical gears:

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Test: Gears - 2 - Question 3
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Select the odd terminology in respect of bevel gears:

Detailed Solution for Test: Gears - 2 - Question 3

Test: Gears - 2 - Question 4
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The role of hunting tooth or hunting cog in a gear transmission is that it
Detailed Solution for Test: Gears - 2 - Question 4

There is concept of ‘hunting tooth’ for uniform distribution of tooth wear. Suppose (ZP = 20), then after every two revolutions of the pinion, the same pair of teeth will engage. If however, we take (ZP = 20) and (Zg = 4), the pinion will rotate 41 times before the same pair of teeth will engage again. This extra teeth is called the hunting tooth. It results in more even distribution of wear.

Test: Gears - 2 - Question 5
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Lewis form factor (y) depends upon
Detailed Solution for Test: Gears - 2 - Question 5

Correct Answer- Option D

Lewis form factor for 200 full depth involute system is given by

Where T = Number of teeth.
Hence the value of y  depends  on the number of teeth and it is independent on size of the tooth.

Test: Gears - 2 - Question 6
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A triple threaded worm has teeth of 6 mm module and pitch circle diameter of 50 mm. If the worm gear has 20 teeth of 200 and the coefficient of friction of the worm gearing is 0.05. The lead angle of worm is 
Detailed Solution for Test: Gears - 2 - Question 6

m = 6, n = 3 mm Dw = 50 mm lead angle

Test: Gears - 2 - Question 7
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In the formulation of lewis equation for toothed gearing. It is assumed that tangential tooth load FT Exacts of the
Test: Gears - 2 - Question 8
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The dynamic load on a gear is due to:
1. Inaccuracies of tooth spacing.
2. Irregularities in tooth profile.
3. Deflection of the teeth under load.
4. Type of service (i.e., intermittent, one shift per day, continuous per day).
Which of the above statements are correct?
Detailed Solution for Test: Gears - 2 - Question 8

The dynamic load between the meshing teeth arises due to following factors:
1. Inaccuracies of tooth profile
2. Error in tooth spacing
3. Runout of gear
4. Gear mesh stiffness variation
5. Inertia of rotating masses
6. Deflection of teeth
7. Stiffness of rotating parts
But dynamic factor mainly depends upon tooth error and pitch line velocity.

Test: Gears - 2 - Question 9
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Large speed reductions (greater than 20) in one stage of a gear train are possible through
Test: Gears - 2 - Question 10
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A spur gear transmits 10 kW at a pitch line velocity of 10 m/s; driving gear has a diameter of 1.0 m. Find the tangential force between the driver and the follower, and the transmitted torque respectively.
Detailed Solution for Test: Gears - 2 - Question 10

Power transmitted = Force x Velocity 

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