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Test: Static & Dynamic Force Analysis - 2 - Mechanical Engineering MCQ


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8 Questions MCQ Test - Test: Static & Dynamic Force Analysis - 2

Test: Static & Dynamic Force Analysis - 2 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Static & Dynamic Force Analysis - 2 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Static & Dynamic Force Analysis - 2 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Static & Dynamic Force Analysis - 2 below.
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Test: Static & Dynamic Force Analysis - 2 - Question 1

Any distributed mass can be replaced by two point masses to have same dynamical properties if

Test: Static & Dynamic Force Analysis - 2 - Question 2

A couple M of magnitude 1.5 kN-m is applied to the crank of the engine system shown in figure below. What is the force P required to hold the system in equilibrium?

Detailed Solution for Test: Static & Dynamic Force Analysis - 2 - Question 2



FBD of whole engine system: 

∴ 
FBD of piston:


Now,

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Test: Static & Dynamic Force Analysis - 2 - Question 3

Rod CD is attached to the collar D and passes through a collar welded to end B of level AB. Neglecting the effect of friction, what is the couple M required to hold the system in equilibrium when θ = 300?
(AB ⊥ CD and point D and A are collinear)

Detailed Solution for Test: Static & Dynamic Force Analysis - 2 - Question 3

FBD of DC:





∴ M = 207.85 N-m

Test: Static & Dynamic Force Analysis - 2 - Question 4

A body of mass m and radius of gyration K is to be replaced by two masses m1 and m2 located at distances h1 and h2 from the C.G. of original body. These will be dynamically equivalent to original body. If

Detailed Solution for Test: Static & Dynamic Force Analysis - 2 - Question 4

Conditions for dynamically equivalence:
1. The sum of their masses is equal to the total mass of the body i.e., m = m1 + m2.
2. The centre of gravity of two masses coincide with that of the body.
3. The sum of mass moment of inertia of the masses about their centre of gravity is equal to the mass moment of inertia of the body.

Test: Static & Dynamic Force Analysis - 2 - Question 5

When the crank is at the inner dead centre in a horizontal reciprocating steam engine then the velocity of the piston will be 

Test: Static & Dynamic Force Analysis - 2 - Question 6

Acceleration of the piston in a reciprocating engine is maximum at dead centre and is given by

Test: Static & Dynamic Force Analysis - 2 - Question 7

A disc type flywheel having a mass of 10 kg and radius 0.2 m is replaced in a single cylinder engine by a system of dynamically equivalent concentrated masses m1 and m2 rotating about the fly wheel axis as shown below, if the distance x1 is 0.1 m then the distance x2 is

Detailed Solution for Test: Static & Dynamic Force Analysis - 2 - Question 7

Condition for dynamically equivalent system, 
x1x2 = k2
where k = radius of flywheel 
∴ 0.1 x x2 = (0.2)2
⇒ 

Test: Static & Dynamic Force Analysis - 2 - Question 8

For a slider-crank mechanism with radius of crank r length of connecting rod I, obliquity ratio, crank rotating at an angular velocity ω; for any angle q of the crank, match List-I (Kinematic Variable) with List-II (Equation) and select the correct answer:
List-1
A. Velocity of piston
B. Acceleration of piston
C. Angular velocity of connecting rod
D. Angular acceleration of connecting rod
List-II

Detailed Solution for Test: Static & Dynamic Force Analysis - 2 - Question 8

1. Velocity of piston 
2. Acceleration of piston 
3. Angular velocity of connecting rod 
4. Angular acceleration of connection rod 

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