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Civil Engineering (CE) Exam  >  Civil Engineering (CE) Tests  >  Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Civil Engineering (CE) MCQ

Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Civil Engineering (CE) MCQ


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7 Questions MCQ Test - Test: Tacheometric, Curve & Hydrographic Surveying - 2

Test: Tacheometric, Curve & Hydrographic Surveying - 2 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Tacheometric, Curve & Hydrographic Surveying - 2 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Tacheometric, Curve & Hydrographic Surveying - 2 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Tacheometric, Curve & Hydrographic Surveying - 2 below.
Solutions of Test: Tacheometric, Curve & Hydrographic Surveying - 2 questions in English are available as part of our course for Civil Engineering (CE) & Test: Tacheometric, Curve & Hydrographic Surveying - 2 solutions in Hindi for Civil Engineering (CE) course. Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free. Attempt Test: Tacheometric, Curve & Hydrographic Surveying - 2 | 7 questions in 20 minutes | Mock test for Civil Engineering (CE) preparation | Free important questions MCQ to study for Civil Engineering (CE) Exam | Download free PDF with solutions
Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 1
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If the focal length of the object glass is 25 cm and the distance from object glass to the trunnion axis is 15 cm, the additive constant is

Detailed Solution for Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 1

Additive constant = f + d = 0.25 + 0.15 = 0.40

Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 2
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If the spacing of cross hairs in a stadia diaphragm of a tacheometer is 1.2 mm and the focal length of object glass is 24 cm, then the multiplying constant of tacheometer is

Detailed Solution for Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 2

To find the multiplying constant of a tacheometer, we can use the following formula:

Multiplying constant (K) = (Focal length of object glass) / (Spacing of cross hairs in a stadia diaphragm)

In this case, the focal length of object glass is 24 cm (or 240 mm) and the spacing of cross hairs in a stadia diaphragm is 1.2 mm. Plugging these values into the formula, we get:

K = (240 mm) / (1.2 mm)

K = 200

So, the multiplying constant of the tacheometer is 200.

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Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 3
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If an upgrade of 1.5% is followed by a downgrade of 0.5% and rate of change of grade is 0.2% per 20 m chain, then the length of vertical curve is

Detailed Solution for Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 3

Length of vertical curve,

Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 4
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If ‘g1 ’ and ‘g2’ are the two gradients, ‘r’ is the rate of change of grade (%) per chain, the length of the vertical curve will be
Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 5
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A transition curve is required for a circular curve of 200 m radius, the gauge being 1.5 m and maximum superelevation restricted to 15 cm. The transition is to be designed for a velocity such that no lateral pressure is imposed on the rails and rate of gain of radial acceleration is 30 cm/s2. The required length of transition curve will be
Detailed Solution for Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 5


⇒  V = 14 m/s
∴ 

Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 6
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The lengths of long chord and tangents of a circular curve are equal for a deflection angle of
Detailed Solution for Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 6

The length of long chord (L) = 2RsinΔ/2 and the

Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 7
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The staff intercepts on a vertically held staff at a distance of 50 m and 200 m were found to be 0.49 m and 1.99 m respectively. The constants of instrument used are
Detailed Solution for Test: Tacheometric, Curve & Hydrographic Surveying - 2 - Question 7

D1 = 50 = 0.49 K + C   .......(i)
D2 = 200 = 1.99 K + C   ......(ii)
On solving (i).and (ii) we get,
K = 100 and C = 1

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