Test: Fluid Properties - 1 - Civil Engineering (CE) MCQ

μ = 0.05 Ns/m²
G = 0.5
∴  ρ = 0.5 x 1000 = 500 kg/m³

∴ 
= 1 cm²/s = 1 stokes

Bulk modulus of elasticity
k = Δp/(Δv/v) = 18/1/100
= 1800 MN/m²

Height of capillary rise is given by,

The soap bubble has two interfaces
∴ Work done
= 0.04 x 4π x (6 x 10^-2)² x 2
= 36.2 x 10^-4 Nm

Pressure inside the liquid droplet is given by
 Δp=4σ/d  

σ is the surface tension = 0.075 N/m = (0.075/100) N/cm
d is the diameter = 0.075 mm= (0.075/10) cm

Therefore, pressure = [4 x (0.075/100)] / [0.075/10]
= 0.4 N/cm²

Specific volume(v) is defined as the volume(V ) per unit mass(m).
v = v⁄m = 1 / m⁄v = 1⁄p
where p is the mass density. Thus, if p1 > p2, the relation between the specific volumes v1 and v2
will be represented by v1 < v2.

In general, surface tension decreases when temperature increases because cohesive forces decrease with an increase of molecular thermal activity. The influence of the surrounding environment is due to the adhesive action of liquid molecules that they have at the interface.

Surface tension

• It is the property of a liquid by virtue of which it tries to minimize its free surface area.
• It happens due to the cohesive force between liquid molecules. 

Capillary action is caused by the combination of cohesive forces of the liquid and the adhesive forces between the liquid and tube material. Cohesion and adhesion are two types of intermolecular forces.