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GATE Civil Engineering (CE) 2027 Test: Energy Equation & Its Applications


MCQ Practice Test & Solutions: Test: Energy Equation & Its Applications - 2 (9 Questions)

You can prepare effectively for Civil Engineering (CE) GATE Civil Engineering (CE) 2027 Mock Test Series with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Energy Equation & Its Applications - 2". These 9 questions have been designed by the experts with the latest curriculum of Civil Engineering (CE) 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 30 minutes
  • - Number of Questions: 9

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Test: Energy Equation & Its Applications - 2 - Question 1

If a1 and a2 are the cross-sectional areas of a tank and orifice, h the height of water level intank above the centre of the orifice, the velocity of approach is given by

Test: Energy Equation & Its Applications - 2 - Question 2

If the coefficient of velocity of flow through a orifice is cv and coefficient of resistance is cr, then

Detailed Solution: Question 2

Test: Energy Equation & Its Applications - 2 - Question 3

If Cv, Cc, Dand Cr are the hydraulic coefficients of an orifice, then

Test: Energy Equation & Its Applications - 2 - Question 4

The momentum correction factor for triangular velocity distribution for flow between parallel plates as shown in the figure is

Detailed Solution: Question 4

Triangular velocity distribution is achieved for Couette flow.
Average velocity,Vav = V/2 
Momentum correction factor

Energy correction factor,

Test: Energy Equation & Its Applications - 2 - Question 5

If the velocity is zero over half of the cross- sectionai area and is uniform over the remaining half, then the momentum correction factor is

Detailed Solution: Question 5

Momentum correction factor,

Test: Energy Equation & Its Applications - 2 - Question 6

Match List-I with List-I and select the correct answer using the codes given below the lists:
List-I
A. Moment of momentum equation
B. Bernoulli’s equation
C. Euler’s equation
D. Hagen-Poiseuille equation

List-II
1. Equation to find energy loss in a pipeline
2. Equation of motion for one-dimensional steady flow of ideal and incompressible fluid
3. Equation based on conservation of momentum principle applicable to circulatory flows
4. Three-dimensional equation ofmotion based on Principle of conservation of momentum for ideal and incompressible fluid flow

Detailed Solution: Question 6

Bernoulli's equation is derived from equation of motion for one-dimensional steady flow of ideal and incompressible fluid. \

Test: Energy Equation & Its Applications - 2 - Question 7

If velocity is zero over 1/3rd of a cross-section and is uniform over remaining 2/3rd of the cross-section, then the correction factor for kinetic energy is

Detailed Solution: Question 7


∴ v = 3/2 v
∴ Kinetic energy correction factor

Test: Energy Equation & Its Applications - 2 - Question 8

A jet of water issue from a 5cm diameter nozzle, held vertically upwards, at a velocity of 20 m/sec. If air resistance consumes 10% of the initial energy of the jet, then it would reach a height, above the nozzle, of

Detailed Solution: Question 8

Using Bernoulli’s equation,


Test: Energy Equation & Its Applications - 2 - Question 9

The kinetic energy correction factor is

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