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Important Questions: Surface Areas & Volumes - Class 10 MCQ


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10 Questions MCQ Test - Important Questions: Surface Areas & Volumes

Important Questions: Surface Areas & Volumes for Class 10 2024 is part of Class 10 preparation. The Important Questions: Surface Areas & Volumes questions and answers have been prepared according to the Class 10 exam syllabus.The Important Questions: Surface Areas & Volumes MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Important Questions: Surface Areas & Volumes below.
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Important Questions: Surface Areas & Volumes - Question 1

A funnel figure is the combination of

Important Questions: Surface Areas & Volumes - Question 2

A surahi is the combination of

Detailed Solution for Important Questions: Surface Areas & Volumes - Question 2

        

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Important Questions: Surface Areas & Volumes - Question 3

A cubical ice cream brick of edge 22 cm is to be distributed among some children by filling ice cream cones of radius 2 cm and height 7 cm upto its brim. How many children will get the ice cream cones?

Detailed Solution for Important Questions: Surface Areas & Volumes - Question 3

A cubical ice cream brick of edge 22 cm is to be distributed among children by filling ice cream cones of radius 2 cm and height 7 cm. Let's calculate how many children can get ice cream cones.

Step 1: Volume of the Cubical Ice Cream Brick
The volume of a cube is given by:
Volume = edge3
Here, edge = 22 cm:
Volume = 223 = 10648 cm3

Step 2: Volume of One Ice Cream Cone
The volume of a cone is given by:
Volume = (1/3) π r2 h
Here, radius (r) = 2 cm and height (h) = 7 cm:
Volume = (1/3) π (22) (7)
Volume = (1/3) π (4) (7) = (28/3) π cm3
Using π ≈ 3.1416:
Volume ≈ (28/3) × 3.1416 ≈ 29.32 cm3

Step 3: Number of Children
The number of children who can get cones is:
Number of children = Volume of cube / Volume of one cone
Number of children = 10648 / 29.32 ≈ 363
Answer: c) 363

Important Questions: Surface Areas & Volumes - Question 4

Match the column 

Detailed Solution for Important Questions: Surface Areas & Volumes - Question 4

Correct Option: (b) 1 → F, 2 → A, 3 → C, 4 → E

Important Questions: Surface Areas & Volumes - Question 5

The volume of the largest right circular cone that can be cut out from a cube of edge 4.2 cm is

Detailed Solution for Important Questions: Surface Areas & Volumes - Question 5

The volume of the largest right circular cone that can be cut out from a cube of edge 4.2 cm is 19.404 cm3.


Edge of the cube = 4.2 cm

i.e 2r = 4.2

r = 4.2/2 = 2.1 cm

h = 4.2 cm

Volume of the cone = 1/3 * pi * r2 * h

=> 1/3 * 22/7 * 2.1 * 2.1 * 4.2

=> 19.404 cm3

Hence, the volume of the largest right circular cone that can be cut out from a cube of edge 4.2 cm is 19.404 cm3.

Important Questions: Surface Areas & Volumes - Question 6

The radius (in cm) of the largest right circular cone that can be cut out from a cube of edge 4.2 cm is 

Detailed Solution for Important Questions: Surface Areas & Volumes - Question 6

Edge of the cube = 4.2 cm
Diameter of base of largest possible cone = 4.2 cm
∴ Radius = 4.2/2 = 2.1 cm

Important Questions: Surface Areas & Volumes - Question 7

A shuttle cock used for playing badminton has the shape of the combination of

Important Questions: Surface Areas & Volumes - Question 8

How many bags of grain can be stored in a cuboid granary 12 m x 6 m x 5 m. If each bag occupies a space of 0.48 m3 ?

Detailed Solution for Important Questions: Surface Areas & Volumes - Question 8

Important Questions: Surface Areas & Volumes - Question 9

In a swimming pool measuring 90 m x 40 m, 150 men take a dip. If the average displacement of water by a man is 8 m3, then rise in water level is

Detailed Solution for Important Questions: Surface Areas & Volumes - Question 9

Volume of water displaced = 150 x 8 = 1200 m3 
⇒ 90 x 40 x h = 1200
⇒ 

Important Questions: Surface Areas & Volumes - Question 10

A solid piece of iron in the form of a cuboid of dimensions 49 cm x 33 cm x 24 cm, is moulded to form a solid sphere. The radius of the sphere is

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