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Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Tests  >  Test: Magnetically Coupled Circuits- 2 - Electrical Engineering (EE) MCQ

Test: Magnetically Coupled Circuits- 2 - Electrical Engineering (EE) MCQ


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10 Questions MCQ Test - Test: Magnetically Coupled Circuits- 2

Test: Magnetically Coupled Circuits- 2 for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Test: Magnetically Coupled Circuits- 2 questions and answers have been prepared according to the Electrical Engineering (EE) exam syllabus.The Test: Magnetically Coupled Circuits- 2 MCQs are made for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Magnetically Coupled Circuits- 2 below.
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Test: Magnetically Coupled Circuits- 2 - Question 1
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The overall inductance of two coils connected in series, with mutual inductance opposing self-inductance is L1; with mutual inductance aiding self-inductance the overall inductance is L2. The mutual inductance M is given by

Detailed Solution for Test: Magnetically Coupled Circuits- 2 - Question 1


Let the self inductances of two coils be  L'1 and L'2 respectively.
Then, L1 = L'1 + L'2 - 2M (For opposing)
and L2 = L'1 +  L'2  + 2M (For adding)
So, L2 - L1 = 4M
or, 

Test: Magnetically Coupled Circuits- 2 - Question 2
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In case all the flux from the current in coil-1 links with coil-2, the coefficient of coupling will be

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Test: Magnetically Coupled Circuits- 2 - Question 3
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In series circuit shown below, for series resonant frequency of 1 rad/s, the value of coupling coefficient K will be

Detailed Solution for Test: Magnetically Coupled Circuits- 2 - Question 3

Using coupling coefficient formula, wo have

Now, for resonance,



or, 


or, 15 + 12 k = 18
or, K = 3/12 = 0.25

Test: Magnetically Coupled Circuits- 2 - Question 4
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The equivalent inductance for the following inductive circuit is
Detailed Solution for Test: Magnetically Coupled Circuits- 2 - Question 4

The given circuit is the combination of series and parallel inductances. We have drawn equivalent circuits after getting  each equivalent inductance for each part and we have started from right side. 

Test: Magnetically Coupled Circuits- 2 - Question 5
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The resonant frequency of the given series circuit is
Detailed Solution for Test: Magnetically Coupled Circuits- 2 - Question 5

Leq = L + L + 2 M
= 2 + 2 + 2 x 1 = 6 H

Test: Magnetically Coupled Circuits- 2 - Question 6
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A 3 H inductor has 1000 turns. What should be the number of turns to increase the inductance to 5 H?
Detailed Solution for Test: Magnetically Coupled Circuits- 2 - Question 6

We know that


or, 

Test: Magnetically Coupled Circuits- 2 - Question 7
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What is the equivalent inductance between the terminals A and B for the circuit shown below? (Given, M = 1H)
Detailed Solution for Test: Magnetically Coupled Circuits- 2 - Question 7

Due to same polarity, the effect of mutual inductance will he positive.

Test: Magnetically Coupled Circuits- 2 - Question 8
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Assertion (A): To determine the relative polarity of the induced voltage in the coupled coil, the coils are marked with dots.
Reason (R): One each coil, a dot is placed at the terminals which are instantaneously of the same polarity on the basis of mutual inductance alone.
Test: Magnetically Coupled Circuits- 2 - Question 9
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Assertion (A): When a current changes in a circuit, the magnetic fiux linking the same circuit changes and an emf is induced in the circuit.
Reason (R): Mutual inductances is the bilateral property of the linked circuit.
Detailed Solution for Test: Magnetically Coupled Circuits- 2 - Question 9

The reason for assertion is that, emf is induced due to Faraday’s law of electromagnetic induction. Reason (R) and assertion (A) are individually true.

Test: Magnetically Coupled Circuits- 2 - Question 10
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Match List- I (Connection) with List-ll (Equivalent inductance) and select the correct answer using the codes given below the lists:

Codes:
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