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Test: Ray Optics - 2 - Class 10 MCQ


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15 Questions MCQ Test - Test: Ray Optics - 2

Test: Ray Optics - 2 for Class 10 2024 is part of Class 10 preparation. The Test: Ray Optics - 2 questions and answers have been prepared according to the Class 10 exam syllabus.The Test: Ray Optics - 2 MCQs are made for Class 10 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Ray Optics - 2 below.
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Test: Ray Optics - 2 - Question 1

When white light passes through a prism, it splits into its component colours. This phenomenon is called

Detailed Solution for Test: Ray Optics - 2 - Question 1

The dispersion of light is the phenomenon of splitting of a beam of white light into its seven constituent colours when passed through a transparent medium. It was discovered by Isaac Newton in 1666. Newton discovered that light is made up of seven different colours. He passed a beam of sunlight through a glass prism. The glass prism split the light into a band of seven colours on his wall. He called this band of colours the ‘spectrum’. Thus the spectrum is a band of seven colours which is obtained by splitting of white light by a glass prism. The order of colours from the lower end of spectrum is violet (V), indigo (I), blue (B), green (G), yellow (Y), orange (O), and red (R). The sequence of the 7 colours so obtained in a spectrum can be remembered by using the acronym ‘VIBGYOR’. 

Test: Ray Optics - 2 - Question 2

A deviation in the path of a ray of light can be produced

Detailed Solution for Test: Ray Optics - 2 - Question 2

The bending of light as it passes from one medium to another is called refraction. The angle and wavelength at which the light enters a substance and the density of that substance determine how much the light is refracted. The bending occurs because light travels more slowly in a denser medium.

Hence, by a glass prism as well as a rectangular glass slab

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Test: Ray Optics - 2 - Question 3

The wavelengths corresponding to violet, yellow and red lights are λv , λy and λr respectively.

Detailed Solution for Test: Ray Optics - 2 - Question 3

Explanation:- because we know, the wavelength of red colour is the maximum, then comes yellow, and then Violet.

Test: Ray Optics - 2 - Question 4

Indicate the only correct statement.

Detailed Solution for Test: Ray Optics - 2 - Question 4

​​​​​​Option D: "A concave mirror can never form a diminished virtual image."

Correct. A concave mirror can form a diminished real image but never a diminished virtual image. Virtual images formed by concave mirrors are always enlarged.

Test: Ray Optics - 2 - Question 5

In a museum a child walks towards a large concave mirror. He will see that

Detailed Solution for Test: Ray Optics - 2 - Question 5

Correct Answer :- C

Explanation:- Concave mirrors can form inverted and real images and also virtual and erect images. Size can be smaller, larger or of the same size depending on the position of the object. Smaller than the size of the object, always.

 

If the mirror is a convex mirror, your image (actual size) will be smaller than you are. If the mirror is a concave mirror, your image (actual size) will usually be bigger than you are, depending on your distance from the mirror.

Test: Ray Optics - 2 - Question 6

The magnification of an object placed 10 cm from a convex mirror of radius of curvature 20 cm will be

Detailed Solution for Test: Ray Optics - 2 - Question 6
0.5 is the magnification

it came because....
u= -10cm
f=10 cm
v=5cm {1/f=1/v+1/u}

magnification=-v/u
m=5/10
magnification=0.5
Test: Ray Optics - 2 - Question 7

The angle of incidence for a light ray incident on a plane mirror is 30 degrees. What will be the angle of reflection?

Detailed Solution for Test: Ray Optics - 2 - Question 7

- The angle of incidence is the angle between the incoming ray and the normal (a line perpendicular to the surface).
- According to the law of reflection, the angle of incidence is equal to the angle of reflection.
- Given that the angle of incidence is 30 degrees, the angle of reflection will also be 30 degrees.
- Therefore, the correct answer is A: 30 degrees.

Test: Ray Optics - 2 - Question 8

A concave mirror of focal length 10 cm produces an image five times as large as the object. If the image is in front of the mirror, the distance of the object from the mirror will be

Detailed Solution for Test: Ray Optics - 2 - Question 8

Here, f = -10 cmcm
m = -5 ( image is 5 times larger than the object) 
⇒ -v/ u = -5
⇒ v = 5u 
By using mirror formula, 
1/f  = 1/u + 1/v 
⇒ 1/-10   =  1/u +1/5u 
⇒ 1/-10  = 6/5u 
⇒ 5u  = 6*(-10) cm 
⇒ u =   -60/5 cm
⇒ u  =  -12 cm 
So, the distance of object is 12 cm from the mirror. 

Test: Ray Optics - 2 - Question 9

1. Which of the following statements is true regarding reflection of light?

Detailed Solution for Test: Ray Optics - 2 - Question 9

- The correct answer is B: The angle of incidence is always equal to the angle of reflection.
- This principle is known as the Law of Reflection.
- When light hits a smooth surface, it reflects in such a way that:
- The angle at which the light ray hits the surface (angle of incidence) is equal to the angle at which it leaves (angle of reflection).
- These angles are measured from the normal, an imaginary line perpendicular to the surface at the point of incidence.

Test: Ray Optics - 2 - Question 10

To form an image twice the size of the object, using a convex lens of focal length 20 cm, the object distance must be –

Detailed Solution for Test: Ray Optics - 2 - Question 10

Given, f = 20 cm, h1 = 2h0 

⇒ h1/ho = m = 2 

v / u = 2 => v = 2u

1/ v - 1/ u = 1/ f ( lens formula) 

⇒  1/2u - 1/-u  = 1/ 20 

⇒ 3/ 2u = 1/ 20

⇒ u = 30 cm 

So, option ( c) is the correct answer.

Test: Ray Optics - 2 - Question 11

Refractive index of glass w.r.t. air is 3/2. What is the refractie index of air w.r.t glass ?

Detailed Solution for Test: Ray Optics - 2 - Question 11


If  refractive index of glass w.r.t air is 3/2 , then  refractive index of air w. r. t glass will be it's reciprocal ie. ⅔ ..

Test: Ray Optics - 2 - Question 12

Which of the following conditions are necessary for total internal reflection to take place at the boundary of two optical media?

I. Light is passing from optically denser medium to optically rarer medium.
II. Light is passing from optically rarer medium to optically denser medium.
III. Angle of incidence is greater than the critical angle.
IV. Angle of incidence is less than the critical angle.

Detailed Solution for Test: Ray Optics - 2 - Question 12

Reason:
For total internal reflection to occur:

  1. Light must pass from a denser to a rarer medium (Condition I).
  2. The angle of incidence must be greater than the critical angle (Condition III).
Test: Ray Optics - 2 - Question 13

The speed of light in vacuum is 3.0 × 108 m/s. If the refractive index of a transparent liquid is 4/3, then the speed of light in the liquid is

Detailed Solution for Test: Ray Optics - 2 - Question 13

Refractive index of water :- 
Speed of light in vacuum / speed of light in water
4/3 = (3*108) /x 
x  = 2.25 * 108 m/s

Test: Ray Optics - 2 - Question 14

The refractive indices of water and glass are 4/3 and 3/2 respectively. The refractive index of water with respect to glass is

Detailed Solution for Test: Ray Optics - 2 - Question 14

Refractive index of water, nw =  4/3
Refractive index  of  glass, ng =  3/2 
Refractive index of water w. r. t glass
 ngw = 4/3 / 3/2   =>  8/9

Test: Ray Optics - 2 - Question 15

Which of the following can be used to form a virtual image of an object?
I. convex lens
II. concave lens
III. concave mirror

Detailed Solution for Test: Ray Optics - 2 - Question 15

Analysis of the Options:

  1. I. Convex Lens:

    • A convex lens can form a virtual image when the object is placed between the lens and its focal point. The image is virtual, erect, and magnified.
    • Correct.
  2. II. Concave Lens:

    • A concave lens always forms a virtual, erect, and diminished image regardless of the object's position.
    • Correct.
  3. III. Concave Mirror:

    • A concave mirror forms a virtual image when the object is placed between the pole and the focal point. The image is virtual, erect, and magnified.
    • Correct.
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