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Test: Fluid Dynamics Level - 1 - Mechanical Engineering MCQ


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10 Questions MCQ Test - Test: Fluid Dynamics Level - 1

Test: Fluid Dynamics Level - 1 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Test: Fluid Dynamics Level - 1 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The Test: Fluid Dynamics Level - 1 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Fluid Dynamics Level - 1 below.
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Test: Fluid Dynamics Level - 1 - Question 1
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A piezometer and a Pitot tube are tapped into a horizontal water pipe, as shown in figure. The velocity of water at the center of the pipe is

Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 1
Applying Bernoulli’s equation between point ① and ②

Considering basic assumptions of the equation to be applicable.

② is a stagnation point

i. e. V2 = 0 Also y1 = y2 Substituting the two conditions in Bernoulli’s equation

Test: Fluid Dynamics Level - 1 - Question 2
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Both free vortex and forced vortex can be expressed mathematically in terms of tangential velocity V at the corresponding radius r. Choose the correct combination.

Free vortex Forced vortex

Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 2
A vortex represents motion of fluid mass revolving around an axis.

Free vortex is an example of irrotational flow represented by V × r = constant Forced vortex is an example of rotational flow given by V = r × constant

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Test: Fluid Dynamics Level - 1 - Question 3
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At point A in a pipeline carrying water, the diameter is 1 m, the pressure 98 kPa and the velocity 1m/s. At point B, 2 m higher than A, the diameter is 0.5 m and the pressure 20 kPa.

The direction of flow would be [

Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 3
Applying continuity equation between sections at A and B

V2 = 4 m/s

Since Head at B is small. Flow occurs from A to B. The difference between two heads represents head loss.

Test: Fluid Dynamics Level - 1 - Question 4
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Which configuration measures the stagnation pressure?
Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 4

Stagnation pressure head = p ρg + V2 / 2g

Configuration (A) will measure the gauge pressure in the pipe. Configuration (B) will measure the velocity head as the difference of height of manometric fluid. Configuration (C) will measure Gauge stagnation pressure. Configuration (D) is the same as (A).

Test: Fluid Dynamics Level - 1 - Question 5
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The pressure at a point in the fluid is 4.9 N/cm2. Find height when the fluid under consideration is in oil of specific gravity of 0.85.

Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 5

Height = p / ρg 
= 48620 / 850 * 9.81 
= 5.83 m.

Test: Fluid Dynamics Level - 1 - Question 6
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A submarine moves through seawater (SG = 1.03) at a depth of 50 m with velocity V0 = 5.0 m/s as shown in Fig. Determine the pressure at the stagnation point on the front of the submarine (in kPa).

Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 6
Consider relative motion of water with respect to submarines.

Maybe the streamline formation will be as shown in the figure. Consider the center most straight streamline 1 → 2 where 1 is a point far away from the submarine where the fluid particle is actually at absolute rest but in another frame of reference i.e. with respect to the submarine it is moving with a speed of 5 m/sec. ∴ V1 = 5.0 m/sec.

V2 = 0

and as fluid is at absolute rest at 1, p1 = ρgh where h = 50 m Let us apply Bernoulli’s equation between 1 and 2.

p2 = 518090 Pa or 518.09 kPa

Note: Even though flow is unsteady in actual but by changing the frame of reference and writing motion relative to submarine flow becomes steady and Bernoulli’s equation is applicable.

Test: Fluid Dynamics Level - 1 - Question 7
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A light plane flies at 720 km/hr in standard air at an altitude of 1000 m. Determine the absolute stagnation pressure at the leading edge of the wing. Take, pair = 9.0 × 104 N/m2, ρ = 1.1 kg/m3.
Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 7
Consider the cross-section of wing

Similar to previous question

Also, p1 = 9 × 104 Pa [for away point in atmosphere] V1 = 720 km/hr V1 = 200 m/sec y1 = y2

V2 = 0

Substituting these conditions in the Bernoulli’s equation

∴ p2 = 112 kPa

Test: Fluid Dynamics Level - 1 - Question 8
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A vertical water pipe, 1.5 m long, diverges from 75 mm diameter at the bottom to 150 mm diameter at the top and the rate of flow is 50 L/s upwards. If the pressure at the bottom end is 150 kN/m2 , the pressure at the top will be nearly

(!) 195.2 kN⁄m2
Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 8

p1 = 150 × 103

Q = 50 L/s

Applying continuity equation at 1 and 2

V1 x A1 = V2 x A2

V1/V2 = (150/75)2

V1=4 V2

Applying Bernoulli equation and 1 and 2

V2 = 2.83m/sec

Test: Fluid Dynamics Level - 1 - Question 9
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An open tank contains water upto a depth of 350 cm and above it an oil of specific gravity 0.65 for a depth of 2.5 m. Find the pressure intensity at the extreme bottom of the tank.

Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 9

p = (specific gravity of water* height of water + specific gravity of oil* height of oil) * 9.81 
= 5.027 N/cm2.

Test: Fluid Dynamics Level - 1 - Question 10
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Statement (I): There exists a positive pressure difference between the inlet and throat of a venturi meter.

Statement (II): The coefficient of discharge of a venturi meter accounts for the nonuniformity of flow at both inlet and throat.
Detailed Solution for Test: Fluid Dynamics Level - 1 - Question 10
The throat section of a venturimeter has the highest velocity and hence by the application of Bernoulli’s equation, the lowest pressure. So there is a positive pressure difference between the inlet and throat of a venturimeter, even if the flow is ideal, uniform and has no losses. The coefficient of discharge in the venturimeter is to compensate for the error due to non-uniformity of flow, as well as losses in the flow. Hence both statements are correct but (II) is not the collected explanation for statement (I).

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