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Mechanical Engineering Exam  >  Mechanical Engineering Test  >  Fluid Mechanics  >  Test: Introduction & Properties of Fluid Level- 2 - Mechanical Engineering MCQ

Introduction & Properties of Fluid Level- 2 - GATE ME Mechanics Free MCQ


MCQ Practice Test & Solutions: Test: Introduction & Properties of Fluid Level- 2 (15 Questions)

You can prepare effectively for Mechanical Engineering Fluid Mechanics for Mechanical Engineering with this dedicated MCQ Practice Test (available with solutions) on the important topic of "Test: Introduction & Properties of Fluid Level- 2". These 15 questions have been designed by the experts with the latest curriculum of Mechanical Engineering 2026, to help you master the concept.

Test Highlights:

  • - Format: Multiple Choice Questions (MCQ)
  • - Duration: 20 minutes
  • - Number of Questions: 15

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Test: Introduction & Properties of Fluid Level- 2 - Question 1
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In general decrease in temperature, results in

Detailed Solution: Question 1

The viscosity of fluids (liquids and gases) generally behaves differently with changes in temperature. Here's how temperature affects viscosity:

- **Liquids**: In general, as temperature decreases, the viscosity of liquids tends to increase. This is because lower temperatures reduce the kinetic energy of the liquid molecules, causing them to move more slowly and thus increasing viscosity.

- **Gases**: For gases, as temperature decreases, viscosity tends to decrease. This is because lower temperatures reduce the frequency of collisions between gas molecules, decreasing internal friction and thus reducing viscosity.

Given these behaviors, the most accurate statement regarding the effect of temperature on viscosity is:

**Option 3: an increase in the viscosity of liquids and a decrease in that of gases**

This option correctly reflects the general trend observed in viscosity changes with temperature for both liquids and gases.

Test: Introduction & Properties of Fluid Level- 2 - Question 2
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What is the radius of Mohr’s stress (in kPa) circle for a point inside a fluid mass which rotates like a solid body in a cylindrical container. The pressure at the point is 200 kPa.

Detailed Solution: Question 2

For a fluid mass which moves as a solid body, the shear stress at any plane passing through any point is zero. Hence, the stress on all the planes passing through a point is equal. In such a condition Mohr’s circle is a point on the normal stress axis (−ve) and the distance of the point from origin is equal to pressure at the point.

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Test: Introduction & Properties of Fluid Level- 2 - Question 3
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Which one of the following is the bulk modulus K of a fluid? (Symbols have the usual meaning)

Detailed Solution: Question 3

For any fluid particle m = ρV As this fluid particle will experience a change in pressure, it’s ρ and V will change but m will remain constant.

∴ dm = d(ρV)

0 = ρdV + Vdρ

−dV / V = dp / ρ

As per definition of Bulk Modulus

K = dp / (−dV / V)

Therefore

K = dp / dρ/ρ

K = ρ dp / dρ

Test: Introduction & Properties of Fluid Level- 2 - Question 4
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If angle of contact of a drop of liquid is acute, then

Detailed Solution: Question 4

If contact angle of liquid is acute, that means the liquid can easily wet the surface i.e., the force of adhesion between the liquid and surface is stronger than the cohesive forces acting between the molecules of the liquid. Example: water

Test: Introduction & Properties of Fluid Level- 2 - Question 5
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Which of the following fluids exhibit a certain shear stress at zero shear strain rate followed by a straight line relationship between shear stress and shear strain rate?

Detailed Solution: Question 5

The shear stress vs. rate of strain behavior of different fluids is as shown in the figure.

Where

1 → Dilatants like quicksand, oobleck

2 → Newtonian fluids like water, air

3 → Pseudo plastics like blood, milk

4 → Bingham substances like mayonnaise, toothpaste

Bingham substances are those which undergo static deformation upto a limiting value (τ) of shear stress and behave as solids but beyond this limiting value they deform continuously and behave as fluids.

Thus if τ < τ0,="" even="" though="" there="" will="" be="" deformation="" but="" the="" rate="" of="" deformation="" will="" be="">

Test: Introduction & Properties of Fluid Level- 2 - Question 6
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An increase in pressure of a liquid from 7.5 MPa to 15 MPa results into 0.2 percent decrease in its volume. The coefficient of compressibility of the liquid in m2/N is

Detailed Solution: Question 6

Given p2 = 15 × 106 Pa p1 = 7.5 × 106 Pa

ΔV / V× 100 = −0.2

⇒ ΔV / V= −2 × 10-3

K = Δp / −Δ? / ?

= (15 − 7.5) × 106 / −(−2 × 10−3)

= 3.75 × 109

Compressibility = 1 / K = 2.666 × 10-10

≃ 0.267 × 10−9 m2/N

Test: Introduction & Properties of Fluid Level- 2 - Question 7
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If the surface tension of water-air interface is 0.073 N/m, the gauge pressure inside a rain drop of 1 mm diameter will be

Detailed Solution: Question 7

Cut the raindrop in two halves

For the raindrop to be in equilibrium,

σπd = Δp × π / 4 d2

4σ d = Δp

Substituting values,

Δp = 4 × 0.073 / 1 × 10-3

Δp = 292 N/m2

Test: Introduction & Properties of Fluid Level- 2 - Question 8
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Group I contains the types of fluids while Group II contains the shear stress - rate of shear relationship of different types of fluids, as shown in the figure.

Detailed Solution: Question 8


Test: Introduction & Properties of Fluid Level- 2 - Question 9
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The vapour pressure is the characteristic fluid property involved in the phenomenon of

Detailed Solution: Question 9

If pressure at a point in a flow field drops below the vapor pressure of the liquid, bubble formation will occur at the point. As these bubbles move ahead into high pressure zone, they burst creating turbulence. As a result pitting and corrosion occurs on the nearby solid surfaces.

Test: Introduction & Properties of Fluid Level- 2 - Question 10
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The absolute pressure inside a liquid jet is slightly greater than the atmospheric pressure. This excess pressure (p), the surface tension (σ) of the liquid and diameter (d) of jet are related as

Detailed Solution: Question 10

Cut the liquid jet into two halves and consider FBD of one half

⇒ p × (Ld) = σ × 2L

⇒ p = 2σ / d

Test: Introduction & Properties of Fluid Level- 2 - Question 11
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The Mohr’s stress circle for any point considered inside a fluid at rest is given as

Detailed Solution: Question 11

For a fluid at rest, shear stress at any plane passing through a point is zero hence all the planes are subjected to equal normal stress (pressure). Thus Mohr’s circle is a point on the −ve σ axis. And the distance of the point from origin is equal to pressure.

Test: Introduction & Properties of Fluid Level- 2 - Question 12
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With increase in pressure, the bulk modulus of elasticity for an ideal gas

Detailed Solution: Question 12

Consider an ideal gas initially at a state given by (p, V, T) If the ideal gas undergoes a polytropic process given by pVn = C, an infinitesimal change in state can be given as

d(pVn) = 0

⇒ pnVn−1 dV + dp Vn = 0

⇒ dp = − 1 / npdV − np dV / V

⇒dp / (−dV / V) = np

⇒ K = np

Thus Bulk modulus of an ideal gas is directly dependent upon pressure i.e., if p ↑ K ↑

Test: Introduction & Properties of Fluid Level- 2 - Question 13
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Assertion (A): An open glass tube is dipped in mercury. The mercury level inside the tube shall rise above the level of mercury outside.

Reason (R): The cohesive force between the molecules of mercury is greater than the adhesive force between mercury and glass.

Detailed Solution: Question 13

When a glass tube is introduced into mercury, the level of mercury drops inside the glass tube the cohesive forces within the mercury molecules pull the mercury down along with formation of convex meniscus. Whereas in case of water, the adhesive force between the glass and water is strong and pulls the water upward forming concave meniscus. This capillary rise or depression is because of the difference of cohesive and adhesive forces of liquids for certain surfaces and not because of their density.

Test: Introduction & Properties of Fluid Level- 2 - Question 14
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Which of the following dimensionless no. represents applicability of concept of continuum analysis of a system?

Detailed Solution: Question 14

Knudsen number is the ratio of the molecular mean free path length to a representative physical length scale.

Test: Introduction & Properties of Fluid Level- 2 - Question 15
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The density of water is maximum at a temperature of

Detailed Solution: Question 15

For any liquid the density of the liquid decreases with increasing temperature. But water is an exception and shows maximum density at 4.4°C.

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About this Mechanical Engineering Practice Test

This test contains 15 MCQs on Introduction & Properties of Fluid Level- 2 with detailed solutions for each question. It is part of the Fluid Mechanics for Mechanical Engineering course on EduRev, designed to align with the current Mechanical Engineering syllabus. Each solution explains not just the correct answer but also gives you an understanding of the topic — not just to attempt the question but also help you prepare for the exam with practice.

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