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Test: Open Channel Flow Level - 3 - Civil Engineering (CE) MCQ


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20 Questions MCQ Test - Test: Open Channel Flow Level - 3

Test: Open Channel Flow Level - 3 for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Test: Open Channel Flow Level - 3 questions and answers have been prepared according to the Civil Engineering (CE) exam syllabus.The Test: Open Channel Flow Level - 3 MCQs are made for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Open Channel Flow Level - 3 below.
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Test: Open Channel Flow Level - 3 - Question 1

Hydraulic jump forms in a horizontal rectangular channel carrying a discharge of 60 m3 /min at a depth of 180 mm and the width of the channel is 150 cm. This jump is classified as (take g = 9.81 m/s2)

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 1
Q = 60 m3/min, depth = 180 mm = 0.18 m width = 1.5 m

Fr = 2.787 Hence, this is oscillating jump

Test: Open Channel Flow Level - 3 - Question 2

A very wide rectangular channel is designed to carry a discharge of 8 m3 /s per metre width. The design is based on the Manning’s equation with the roughness coefficient obtained from the grain size using Strickler’s equation and results in a normal depth of 2 m. By mistake however, the engineer used the grain diameter in mm in the Strickler’s equation instead of in metre. The correct normal depth should be __________ in metre. (Report your answer upto two place of decimal)


Detailed Solution for Test: Open Channel Flow Level - 3 - Question 2
Given data, q = 8 m3 /s/meter width

By using Strickler’s equation

y = 1.0027 meter

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Test: Open Channel Flow Level - 3 - Question 3

A Trapezoidal channel is required to carry 1296 MLD of water at a bed slope of 1 in 1600 for lined concrete, Chezy’s constant C = 75. If the cost of lining per square meter is Rs. 225 and cost of excavation per cubic meter is Rs. 600, then what is the depth of the most efficient lined channel?

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 3

C = 75

S = 1 / 1600

P = 2√3y

y = 2.118 m

Test: Open Channel Flow Level - 3 - Question 4

What is the width of the lined channel?

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 4
b = 1.1547 × 2.1184 b = 2.4461 meter

Test: Open Channel Flow Level - 3 - Question 5

What is the total cost of the most efficient lined Trapezoidal channel to carry the given discharge report your answer is Rs. (nearest integer) for per unit meter length of channel.


Detailed Solution for Test: Open Channel Flow Level - 3 - Question 5
Cost of excavation = Volume × Cost of excavation per m3

= (By + my2) × 1 × 600

Total cost = 1651.125 + 4663.64 = Rs 6314.76

Test: Open Channel Flow Level - 3 - Question 6

In order to ensure that no scouring take place in the bed of a channel of bed slope ‘S’ constructed on alluvial soil of particle size ‘d’ m the flow velocity should be restricted to


Detailed Solution for Test: Open Channel Flow Level - 3 - Question 6
For No Scouring in channel d = 11RS

Test: Open Channel Flow Level - 3 - Question 7

The Chezy’s coefficient C is related to Darcy Weisbach friction factor F as


Detailed Solution for Test: Open Channel Flow Level - 3 - Question 7

Test: Open Channel Flow Level - 3 - Question 8

A short reach of a 3 m wide rectangular open channel has its bed level rising in the direction of flow at a slope of 1 in 10000 it carries a discharge of 5 m3 /s and its Manning’s roughness coefficient is 0.01. The flow in this reach is gradually varying. At a certain section in this reach the depth of flow was measured as 0.5 m. The rate of change of the water depth with distance dy/dx at this section is __________ (use g = 10 m/s2)

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 8
Given data b = 3m,

So = −1 / 10000

Q = 5 m3⁄s , n = 0.01, y = 0.5 m

Test: Open Channel Flow Level - 3 - Question 9

Match List-I (surface) with List-II (approximate range of Manning’s n) and select the correct answer.

List-I List-II

(a) Gravel river bed with 50 mm diameter bed 1. 0.02 to 0.022

(b) Badly maintained unlined irrigation 2. 0.025 to 0.04

channel with weed growth

(c) Concrete lined channel 3. 0.013 to 0.017

(d) Channel with brick lining 4. 0.04 to 0.08

Code: a b c d

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 9
Manning’s n is a parameter representing the integrated effect of the channel cross-section resistance. So as the roughness of channel cross-section increases, value of n also increases

Test: Open Channel Flow Level - 3 - Question 10

Water surface profiles that are asymptotic at one end and terminated at the other end would include

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 10

Considering the above three situation, in the given choices (C) is the appropriate one, because as the profile is descending hence dy / dx < 0="" and="" the="" profile="" is="" in="" the="" second="" zone="" i.e.,="" in="" between="" cdl="" and="" ndl.="" chances="" of="" />2 omits as the statement in question is “surface profiles that are asymptotic at one end”.

Test: Open Channel Flow Level - 3 - Question 11

A rectangular channel 6.5 m wide carries a discharge of 18 m3/s under uniform flow condition with normal depth of 1.8 m Manning’s n is 0.018.

The longitudinal slope of the channel is

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 11
Width of rectangular channel

B = 6.5 m

Discharge Q = 18 m3/s

Normal depth = yn = 1.8 m

Manning’s n = 0.018

From Manning’s equation

S = 6.3033 × 10−4

Test: Open Channel Flow Level - 3 - Question 12

A hump is to be provided on the channel bed. The maximum height of the hump without affecting the upstream flow condition is

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 12

Test: Open Channel Flow Level - 3 - Question 13

The channel width is to be contracted. The minimum width to which the channel can be contracted without affecting the upstream flow condition is

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 13
E1 = 1.9206 m

If upstream condition is not affected,

E1 = E2

Flow is sub-critical so we contract the width at section 2 depth of flow will decrease when the depth at section 2 is equal to critical depth flow at section 2 will be critical flow, beyond this further contraction will affect the upstream condition.

E2 = Ec = E1

= 3.9665 m

Test: Open Channel Flow Level - 3 - Question 14

A partially open sluice gate is suddenly raised to its full opening. The resulting surge waves at the gate are

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 14
Positive wave means the wave which results in an increase in the depth of flow, and negative wave causes a decrease in the depth of flow.

Test: Open Channel Flow Level - 3 - Question 15

A hydraulic jump is formed in a 2.5 m wide rectangular channel which is horizontal and frictionless. The post jump depth and velocity are 0.7 m and 0.9 m/s respectively. The pre-jump velocity is _____________ m/s (g = 10 m/s2)


Detailed Solution for Test: Open Channel Flow Level - 3 - Question 15
Given data y2 = 0.7 m v2 = 0.9 m/s

Test: Open Channel Flow Level - 3 - Question 16

A wide channel is 2 m deep and has a velocity of flow 2.86 m/s. If a disturbance is caused, an elementary wave can travel upstream with a velocity of __________ in m/s.


Detailed Solution for Test: Open Channel Flow Level - 3 - Question 16

y1 = 2 m

V1 = 2.86 m/sec

C = √9y

= √9.81 × 2

C = 4.4294 m/sec Since,

C = V1 + Vω

Vω = C − V1 = 4.4294 − 2.86 = 1.5694 m

Test: Open Channel Flow Level - 3 - Question 17

A 2 m wide rectangular channel flowing at its normal depth of 1.2 m carries a discharge of 6.0 m3/s. If at a section, the depth of flow is y then match List-I (value of y) with List-II (type of water surface profile) and select the correct answer using the codes given below the lists. (take g = 9.8)

List-I List-II

(a) 0.63 m 1. M1

(b) 0.90 m 2. M2

(c) 1.1 m 3. M3

(d) 1.42 m 4. S2

5. S3

Code: a b c d

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 17
Given data Q = 6 m3/s, B = 2 m, yn = 1.2 m

yn = 1.2 m

A → y = 0.63 m, yn = 1.2 m, yc = 0.972 m ⇒ M3

B → y = 0.90 m, yn = 1.2 m, yc = 0.972 m ⇒ M3

C → y = 1.1 m, yn = 1.2 m, yc = 0.972 m ⇒ M2

D → y = 1.42 m, yn = 1.2 m, yc = 0.972 m ⇒ M1

Test: Open Channel Flow Level - 3 - Question 18

A rectangular channel has 5 m width and 3 m water depth. If the bed slope of the channel is 1 in 1200, find the minimum width of throat in m, if Manning’s n = 0.02. (Report your answer upto two decimal place)


Detailed Solution for Test: Open Channel Flow Level - 3 - Question 18
Given B = 5 m, S = 1 in 1200, y = 3 m,

n = 0.02

Area = B × y = 5 × 3 = 15 m2

P = B+2y = 5+2×3 = 11m

When channel section is contracted to minimum width and for constant discharge Q, the flow over the contracted section will be critical flow and under assumption that no energy loss has taken place.

E2 = Ec = E1 (Since there is no energy loss)

Test: Open Channel Flow Level - 3 - Question 19

What is the maximum height of the hump (in m) to produce critical depth, without changing the water level at the entrance. (Report your answer upto two decimal place)


Detailed Solution for Test: Open Channel Flow Level - 3 - Question 19
Maximum height of hump In case of maximum height of hump without changing the upstream depth of flow, the flow over the hump will be critical flow.

We know that, E1 = 3.16

3.16 = 2.136 + ∆Zmax

∆Zmax = 1.024 m

Test: Open Channel Flow Level - 3 - Question 20

Water flows in a triangular channel of side slope 1 horizontal : 1 vertical and longitudinal slope of 0.001. Determine the type of channel slope when a discharge of 0.2 m3 /s flows through it. Assume Manning’s n = 0.015.

Detailed Solution for Test: Open Channel Flow Level - 3 - Question 20
Given data For a depth of flow of y in the channel

Area = y2

T = 2y

yn = 0.536 m

Since yn > yc the channel is a mild slope channel for this discharge.

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