Test: Line Charts- 1 - CAT MCQ

Given:

A person invests an amount of Rs. 50000 in company Y in 2023 for 1 year

He bought a Television worth of Rs. 20000 in the next year with the amount received

He invested the remaining amount in company X for one year

Concept Used:

Simple interest (SI) = (P × R × T)/100

Where, P = principal amount, R = rate of interest, and T = time of investment

Calculation:

Amount received after 1 year from Y = 50000 + (50000 × 10)/100 = Rs. 55000

Remaining amount after buying television = 55000 - 20000 = Rs. 35000

Interest received on Rs. 35000 in the next year from X = (35000 × 8)/100 = Rs. 2800

∴ The correct answer is option 3

Given:

In 2024, an amount of 1 Lac is invested in company X for 1 year 

The total amount received is invested in company Y for 1 year in 2025

The interest rate of 2025 for Y is the same as 2024

Concept Used:

Simple interest (SI) = (P × R × T)/100

Where, P = principal amount, R = rate of interest, and T = time of investment

Calculation:

Amount received from X in 1 year = 100000 + (100000 × 8)/100 = Rs. 108000

Amount received from Y in 2025 = 108000 + (108000 × 15)/100 = Rs. 124200

∴ The correct answer is option 2

Given:

In 2023, a part of Rs. 45,000 is invested in company X

The rest was invested in company Y for 1 year

The total interest received is Rs. 3100

Concept Used:

Simple interest (SI) = (P × R × T)/100

Where, P = principal amount, R = rate of interest, and T = time of investment

Calculation:

Let, Rs. a is invested in X and Rs. (45000 - a) is invested in Y

According to the question,

(6a/100) + (45000 - a) × 8/100 = 3100

⇒ 6a + 360000 - 8a = 310000

⇒ 2a = 50000

⇒ a = 25000

∴ The amount invested in X was Rs. 25000

Given:

Two different amounts in the ratio 8 : 15 are invested in X and Y respectively in 2022

Concept Used:

Simple interest (SI) = (P × R × T)/100

Where, P = principal amount, R = rate of interest, and T = time of investment

Calculation:

Let, the amount invested in X is = 8a, and in Y is = 15a in 2022

The amount received from X = 8a + (8a × 10)/100 = Rs. (88a/10)

The amount received from Y = 15a + (15a × 5)/100 = Rs. (63a/4)

The respective ratio of amount received from X and Y is

⇒ (88a/10) : (63a/4) = 176 : 315

∴ The correct answer is option 2

Given:

A person invested Rs. 12,500 in company X in the year 2020 for 1 year

Concept Used:

Simple interest (SI) = (P × R × T)/100

Where, P = principal amount, R = rate of interest, and T = time of investment

Calculation:

The interest received from X = (12500 × 12)/100 = Rs. 1500

The interest received from Y = (12500 × 10)/100 = Rs. 1250

He would earn (1500 - 1250) = Rs. 250 less from Y than X

∴ The correct answer is option 2