Olympiad Test: Data Handling - Class 7 Maths Free MCQ with solutions

 Average =hours

The range of a given data is the difference between its highest and lowest values. From the given data, range =154−128=26.

At 6 p.m., the sales of fruits were lesser than the sales of vegetables. This is indicated by the bar graph:

• The height of the fruit sales bar is lower than that of the vegetable sales bar.
• This visual representation clearly shows the difference in sales at this time.

To determine the total kilograms of fruits sold during the four hours (from 6 p.m. to 9 p.m.), we sum the sales for each hour:

• 6 p.m.: 35 kg
• 7 p.m.: 26 kg
• 8 p.m.: 45 kg
• 9 p.m.: 20 kg

Total fruit sales: 35 + 26 + 45 + 20 = 126 kg.

Mean of first 5 natural numbers = 
Median of 1,2,◯3,4,5,=3

No. of kilograms of fruits sold during the four hours

= 25 + 38 + 35 + 20 = 118

No. of kilograms of vegetables sold during the four hours

= 35 + 26 + 45 + 20 = 126

We can see that the sale of vegetables is more than the fruits

As we can see Nandan's performance is going the highest among all
Hence, Nandan is the right answer.

Since two dice are thrown simultaneously total numbers of outcomes are 6*6=36 . We make pairs of it
(1,1)   (2,1)   (3,1).....(6,1)
   :         :         :    :::::     :
(1,6)   (2,6)   (3,6).....(6,6)

As we can see in the bar graph , Sharanya and Shravan have secured the same marks. 

Total number of outcomes = 10
No. of favourable outcomes = 2 red balls
Probability of red balls =  No. of favourable outcomes/Total number of outcomes
= 2/10= 1/5 

total number of outcomes = 10
favourable(getting a blue ball) = 3
Probability(getting a blue ball) = 3/10

Number of red balls = 2

Total number of balls = 2 + 3 + 5

Performing addition

Total number of balls = 10

Keep the values in formula to find the probability of getting black ball.

Performing division

Probability of getting black ball = 5/10

Hence, the probability of getting a black ball is 1/2

total number of outcomes = 10
favourable(not getting a blue ball) = 7
Probability(not getting a blue ball) = 7/10

The number of black balls =5 

Probability of getting black ball = 5/10 = 1/2

Probability of getting a non black ball = 1 - Probability of getting a black ball

= 1 -1/2 = 1/2

Understanding Class Intervals

In a frequency distribution table, class intervals represent the ranges of data grouped together. The size of a class interval is the difference between the upper limit and the lower limit of any class.

Analyzing the Table

From the table, we can observe the following class intervals:

• 100-125
• 125-150
• 150-175
• 175-200
• 200-225
• 225-250
• 250-275
• 275-300
• 300-325

Calculating the Size

Let's take the first class interval as an example: 100-125.

• Upper limit = 125
• Lower limit = 100

Size of the class interval = Upper limit - Lower limit = 125 - 100 = 25

Consistent Size

If we calculate the size of other class intervals in the same way, we will find that they all have the same size of 25.

Conclusion

Therefore, the size of the class intervals in the given table is 25.

As we can see in the frequency table, 200-225 is the interval which corresponds to the highest value of frequency among all i.e 140

The frequency corresponding to the class interval 300-325 is the lowest among all intervals, with only:

• 20 workers falling into this range.

The upper limit of a class interval includes all values up to that number. Hence, for the interval 250-275, the upper limit is 275.

As we can see, frequency corresponding to 300-325 is 20
Hence , 20 is the right ans.