Test: Roman Numerals- 1 - Class 5 MCQ

Lets break down XCI 
X = 10
C = 100
I = 1

In Roman numerals, if a smaller number comes before a larger number, you subtract the smaller number from the larger one. As we know X is smaller than C in Roman Numerals.

Therefore,When X (10) is subtracted from C (100), it leaves 90. Adding I (1) to 90 gives the value 91.

Therefore, XCI is equal to 91. Option 'A' is correct.

• Lets break down LXXI
  L = 50
  X = 10
  X = 10 (there are two X's) 
  I = 1
• If a Larger number comes before a smaller number, you add it.
• As we know L is larger than X in Roman Numerals.
• Therefore,LXXI=50+10+10+1=71
• Option 'B' is correct.

• The numeral XCIII is divided into two main parts: XC and III.
•  X represents 10 and C represents 100, while I represents 1.
• When a smaller numeral appears before a larger one, it is subtracted from the larger numeral.
• In this case, the smaller numeral X appears before C, so XC means 100 - 10 = 90.
• III = 3
• Therefore, XCIII = 93
• Option 'A' is correct,

First, subtract 24 from 75:

75−24=5175 - 24 = 5175−24=51

Now, convert 51 to Roman numerals:

50 = L

1 = I

So, 51 in Roman numerals is LI.

The correct answer is A: LI.

Lets breakdown the Roman Numeral

• X = 10
• X = 10
• X = 10
• V = 5
• III = 3
• Adding them up:
• 10 + 10 + 10 + 5 + 3 = 38.
• So, XXXVIII represents the number 38.
• Option 'B' is correct.