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UGEE SUPR Mock Test- 4 - JEE MCQ


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30 Questions MCQ Test - UGEE SUPR Mock Test- 4

UGEE SUPR Mock Test- 4 for JEE 2024 is part of JEE preparation. The UGEE SUPR Mock Test- 4 questions and answers have been prepared according to the JEE exam syllabus.The UGEE SUPR Mock Test- 4 MCQs are made for JEE 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for UGEE SUPR Mock Test- 4 below.
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UGEE SUPR Mock Test- 4 - Question 1
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A particle is performing U.C.M. along the circumference of a circle of diameter 50 cm with frequency 2 Hz, The acceleration of the particle tn m/s2 is

Detailed Solution for UGEE SUPR Mock Test- 4 - Question 1
Given, diameter of circle, d = 50cm

= 50 x 10-2 m

and frequency, f = 2Hz

The acceleration of particle in a uniform circular motion can be given as

a = ω2x

where, ω = angular frequency = 2πf

x = didance from centre = d/2

⇒ a = 4π2f2 x d/2 …….(i)

Substituting given values in Eq. (i), we ge

a = 4π2 x 4 x (50 x 10-2)/2 = 4π2

UGEE SUPR Mock Test- 4 - Question 2
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A convex lens of focal length ‘f’ is placed In contact with a concave lens of the same focal length. The equivalent focal fengfo of the combination is

Detailed Solution for UGEE SUPR Mock Test- 4 - Question 2
Given, focal length of convex lens, f1 = f and focal length of concave lens, f2 = -f.

The focal length of the combination, when two lenses are in contact is given 1/f = 1/f1 + 1/f2 ….(i)

Substituting given value in Eq. (i), we get

⇒ 1/f = 1/f - 1/f = 0 ⇒ f = ∞

Hence, the equivalent focal length of the combination is infinity.

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UGEE SUPR Mock Test- 4 - Question 3
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The range of an ammeter of resistance ‘G’ can be increased from ‘l’ to ‘nl’ by connecting

Detailed Solution for UGEE SUPR Mock Test- 4 - Question 3
To increase the range from I to nI a parallel resistance (shunt S) is connected across the galvanometer.

UGEE SUPR Mock Test- 4 - Question 4
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When a 12000 joule of work is done on a flywheel, its frequency of rotation increases from 10 Hz to 20 Hz. The moment of inertia of flywheel about its axis of rotation is (π2 = 10)
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 4
Given, work done. W = 12000J,

Initial frequency, f1 = 10Hz and final frequency, f2 = 20Hz

Angular velocity for rotational motion is given by ω = 2πf

∴ ω1 = 2πf1 = 2π x 10 = 20π rad/s and ω2 = 2πf2 = 2π x 20 = 40π rad/s

According to work-energy theorem, work done in rotation = change in rotational kinetic energy

.

UGEE SUPR Mock Test- 4 - Question 5
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In the given electrical circuit, which one of the following equations is a correct equation?
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 5
The given circuit can be drawn a

Applying Kircbhoff’s voltage law (KVL) in loop ABCDA, we get

-(i1 + i2)R +E2 - i2r2 = 0 ….(i)

Applying KVL in loop ABFEA we get -

- (i1 + i2)R - i1r1 + E1 = 0 ….(ii)

Applying KVL in loop EFCDE, we get

-E1 + i1r1 + E2 - i2r2 = 0 ….(iii)

From the given options, only option (c) satisfies Eq..(ii), hence it is the correct equation.

UGEE SUPR Mock Test- 4 - Question 6
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A lift is tied with thick iron ropes having mass ‘M’. The maximum acceleration of the lit is ‘a’ m/s2 and the maximum safe stress is ‘S’ N/m2. The minimum diameter of the rope is
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 6
The maximum stress produced in a rope is given by

σmax = Force/Area = Mg/πr2

As the ift is accelerating with acceleration a, then

σmax = M(g ± a)/πr2

⇒ r2 = M(g ± a)/πS [Given , σmax = S]

d2/4 = M(g ± a)/πS [∴ r = d/2]

As acceleration maximum i.e., g’ = g + a, so

UGEE SUPR Mock Test- 4 - Question 7
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An alternating voltage is given by The voltage will be maximum for the first time when is (T = periodic time)
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 7
Given, alternating voltage is

The voltage will be maximum, when

= T/6

Thus, the voltage will be maximum for the first time when t = T/6.

UGEE SUPR Mock Test- 4 - Question 8
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With a resistance of ‘X’ in the left gap and a resistance of 9Ω in the right gap of a meter bridge, the balance point is obtained at 40 cm from the left end.

In what way and to which resistance 3Ω resistance be connected to obtain the balance at 50 cm from the left end
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 8
The balanced condition of the bridge is shown below in the first case

To get the balance point at 50 cm from the left end. the balanced condition becomes

As, in series combination resistances are added, so to get 9Ω at left gap the 3Ω resistance should be added in series with XΩ (6 + 3 = 9Ω).

UGEE SUPR Mock Test- 4 - Question 9
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P and Q are two non-zero vectors inclined to each other at an angle ‘θ’. ‘p’ and ‘q’ are unit vectors along P and Q respectively. The component of Q in the direction of P will be
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 9

Let two vectors, P and Q are represented by a graph as below

Here, is a vector in the direction of P.

Then, from the right angle triangle, we get

⇒ Op = Q cos θ

As given that, P is the unit vector along P, then

P = P/P ….(iii)

Putting the value of Ptrom Eq. (iii) to Eq. (ii), we get

Qp = P·Q

UGEE SUPR Mock Test- 4 - Question 10
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Find the wrong statement from the following about the equation of stationary wave given by Y = 0.04 cos(πx) sin(50 πt) m where t is in second. Then for the stationary wave.
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 10

UGEE SUPR Mock Test- 4 - Question 11
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Two light belts are suspended as shown in the figure. When a stream of air passes through foe space between them, foe distance between the balls will
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 11
When a stream of air passes through the space between the baits, the pressure reduces between them as compared to the atmospheric pressure on either side. So, according to Bemoulli’s theorem, the pressure energy should be constant and is compensated by the movement of balls toward each other. So, the distance between the balls will decrease.
UGEE SUPR Mock Test- 4 - Question 12
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The critical angle for light going from medium ‘x’ to medium ‘y’ is ‘θ’. The speed of light in medium ‘x’ is ‘vx’ . The speed of Iight in the medium ‘y’ is
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 12
The critical angle is that angle on incidence in the denser medium for which the angle of refraction in rarer medium is 90º , i.e.

⇒ sin θ = μy/μx …(i)

where, μ = refractive index of the medium.

From Eqs, (i) and (iii), we get

Thus, the speed of light in medium y is

UGEE SUPR Mock Test- 4 - Question 13
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A rigid body is rotating with angular velocity ‘ω’ about an axis of rotation. Let ‘v’ be the linear velocity of a particle which is at perpendicular distance ‘r’ from the axis of rotation. Then the rotation ‘v’ = rω Implies that
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 13
Using the given relation,

v = rω

If the perpendicular distance r from the axis of rotation is increased or decreased, then the value of linear velocity v accordingly increases or decreases. Thus, the value of angular velocity ω does not depend on r.

UGEE SUPR Mock Test- 4 - Question 14
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The maximum wavelength of radiation emitted by a star is 289.8 nm. Then intensity of radiation for the star is (Given: Stefan’s constant = 5.67 x 10-6 Wm-2 K-4, Wien’s constant, b = 2898p μmK)
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 14
Given, Maximum wavelength,

λm = 289.8 nm = 289.8 x 10-9 m

= 289.8 x 10-10 m

Stefan's constant, σ = 567 x 10-8 Wm -2 K-4

Wien's constant, b = 2898 μmK = 289.8 x 10-6 mK

According to Wien’s displacement law. the maximum wavelength is given by

λm = b/T ⇒ T = b/λm ….(i)

Substituting given values in Eq. (i), we get

According to Stefan’s law, the energy radiated from a source is given by

E = σ AeT4 ...(ii)

where, A = area of source

e = emissivity (value between 0 to 1)

The intensity of radiations emitted is equal to energy radiated from a given surface area, i.e.,

l = E/A = σeT4 [from Eq.(iii)]

As e is very small, so

l = σeT4 …..(iv)

Substituting the value of T from Eq. (ii) in Eq. (iv), we get

l = σ(104)4 = 5.67 x 10-8 x 1016

[∵ σ = 5.67 x 10-8 (given)]

= 5.67 x 108 Wm-2

UGEE SUPR Mock Test- 4 - Question 15
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In the Balmer series, the wavelength of the first line is ‘λ1’, and in the Brackett series wavelength of the first line is ‘λ2’ then λ1/λ2 is
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 15

UGEE SUPR Mock Test- 4 - Question 16
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In frequency modulated wave
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 16
In frequency modulated waves, the only frequency varies with time, while the amplitude remains constant. This wave can be shown as

It is used in FM broadcasting, telemetry, and RADAR, etc.

UGEE SUPR Mock Test- 4 - Question 17
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The excess of pressure, due to surface tension, on a spherical liquid drop of radius ‘R’ is proportional to
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 17
The excess of pressure due to surface tension on a spherical liquid drop is given by p = 2T/R ….(i)

where. T = surface tension and

R = radius of the liquid drop

UGEE SUPR Mock Test- 4 - Question 18
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The volume of 1 mole of any pure gas at standard temperature and pressure is always equal to
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 18
The volume of 1 mole of any pure gas at standard and pressure (STP) is equal to 22.414 L

1 L = 10-3 m3

∴ 22.4 L = 0.022414 m3

UGEE SUPR Mock Test- 4 - Question 19
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Which of the following is also called as nitrogen sesquioxide?
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 19
Nitrogen sesquioxide is an oxide containing three atoms of oxygen with two atoms of nitrogen element. Its chemical formula is N3O3.
UGEE SUPR Mock Test- 4 - Question 20
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Which among the following is a set of nucleophiles?
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 20
Key Idea: Nucleophile is a chemical species that can donate an electron pair to form a chemical bond in relation to a reaction.

All molecules or ions with free pair of electrons or at least one rt-bood can act as nucleophiles.

Among given species CN-, H2O, R—OH are nucleophiles.

UGEE SUPR Mock Test- 4 - Question 21
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In ozone molecule the formal charge on the central oxygen atom is
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 21
Key Idea: The formal charge can be calculated using a formula.

Formal charge = number of valence electron electrons

(number of electrons in bond pairs) - number of electrons in the lone pair.

For O3.

UGEE SUPR Mock Test- 4 - Question 22
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How many total constituent particles are present in a simple cubic unit cell?
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 22
A simple cubic lattice has only eight atoms on the comers. As the contribution by each = 1/8

Therefore, the number of constituent particles (atoms) present in a unit cell

UGEE SUPR Mock Test- 4 - Question 23
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Which among the following is a neutral complex?
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 23
A neutral complex is a complex ion which have no charge on it. Among the given options [Pt(NH3)2Cl2] is a neutral complex. The type of complexes in other options are as follows

(a) [Fe(H2O)6]Cl3- cationic complexes

(b) [Ni(NH3)6]Cl2 - cationic complexes

(d) K[Ag(CN)2] - anionic complexes

UGEE SUPR Mock Test- 4 - Question 24
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Limestone is used as a flux In the extraction of
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 24
Limestone is used as a flux in the extraction of iron because it decomposes in a hot furnace to form calcium oxide and carbon dioxide. The formed calcium oxide actually acts as a flux and is combined with stica to form fustole calcium silicate slag.
UGEE SUPR Mock Test- 4 - Question 25
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How many isomers are possible for an akane having molecular formula C5H12?
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 25
There can be 3 possible isomers (or an alkane having formula C5H12. These are as follows

UGEE SUPR Mock Test- 4 - Question 26
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Two moles of an ideal gas is expanded isothermally and reversibly at 300 K from 1L to 10 L. The enthalpy change in kJ is
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 26
The enthalpy change at constant pressure is given as

ΔH = CpΔT

For isothermal expansion

ΔT = 0

∴ ΔH = 0

UGEE SUPR Mock Test- 4 - Question 27
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The bond angle H—O —O in H2O2 in gaseous phase is
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 27

The molecular dimensions of H2O2 in the gaseous phase is shown in the following figure.

Thus, the bond angle H — O — O in H2O2 in gaseous phase is 94.8º

UGEE SUPR Mock Test- 4 - Question 28
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The activation energy of a reaction is zero. Its rate constant at 280 K is 1.6 x 10-6 s-1, the rate constant at 300 K is
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 28

Key Idea: Arrhenius equation is given as

Given.

Activation energy of a reaction, EA = 0

Rate constant, k1, = 1.6 x 10-6 s-1

Temperature, T1 = 280K,T2 = 300 K

According to Arrhenius equation

k2 =1.6 x 10-6 s-1

UGEE SUPR Mock Test- 4 - Question 29
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Which of the following is not a broad spectrum antibiotics?
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 29
Antibiotics which kill or inhibit a wide range of gram positive and gram negative bacteria are called broad spectrum antibiotics. Among the given options. penicillIn is not a broad spectrum antibiotics. It is a narrow spectrum antibiotics, i.e. it is effective mainly against specific fancies of bacteria.
UGEE SUPR Mock Test- 4 - Question 30
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The reaction in which 2 molecules of chlorobenzene reacts with metallic sodium in presence of dry ether forming diphenyl Is an example of.
Detailed Solution for UGEE SUPR Mock Test- 4 - Question 30
The reaction is which 2 molecules of chlorobenzene reacts with metallic sodium in presence of dry ether forming diphenyl is an example of Wurtz-Fittig reaction.

For reaction can be written as:

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