All Courses
Get the App Signup / Login
Sign in Open App
Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  RRB JE ME (CBT I) Mock Test- 4 - Mechanical Engineering MCQ

RRB JE ME (CBT I) Mock Test- 4 - Mechanical Engineering MCQ


Test Description

30 Questions MCQ Test - RRB JE ME (CBT I) Mock Test- 4

RRB JE ME (CBT I) Mock Test- 4 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The RRB JE ME (CBT I) Mock Test- 4 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The RRB JE ME (CBT I) Mock Test- 4 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE ME (CBT I) Mock Test- 4 below.
Solutions of RRB JE ME (CBT I) Mock Test- 4 questions in English are available as part of our course for Mechanical Engineering & RRB JE ME (CBT I) Mock Test- 4 solutions in Hindi for Mechanical Engineering course. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free. Attempt RRB JE ME (CBT I) Mock Test- 4 | 100 questions in 90 minutes | Mock test for Mechanical Engineering preparation | Free important questions MCQ to study for Mechanical Engineering Exam | Download free PDF with solutions
RRB JE ME (CBT I) Mock Test- 4 - Question 1
Save

A canal is 5 m wide at the bottom and 8 m wide at the the top. The depth of water is 4 m. Water is flowing in the canal with the speed of 10 m/s. How much cubic m. of water will flow in 1 minute?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 1
Area of the base 1/2 (sum of parallel sides) × Height

= 1/2(8+5)×4 = 26 m2

∵ Speed of water = 10 m/sec.

∴ Volume of water = 26 × 10 × 60 = 15600 m3

RRB JE ME (CBT I) Mock Test- 4 - Question 2
Save

In how many years will a sum of Rs. 3,500 yield an interest of Rs. 2,100 at 15% per annum?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 2
T = 2100×100/3500×15

T = 4 Years

1 Crore+ students have signed up on EduRev. Have you? Download the App
RRB JE ME (CBT I) Mock Test- 4 - Question 3
Save

The average of all the prime and composite numbers up to 100 is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 3
Since 1 is neither prime nor composite number. Thus there are only 99 number viz.

2, 3, 4, 5, 6, ... 99, 100.

RRB JE ME (CBT I) Mock Test- 4 - Question 4
Save

A, B and C can do a work in 6, 8 and 12 days respectively. Doing that work together they get an amount of Rs. 1350, the share of B in that amount is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 4
A’s one day work = 1/6

B’s one day work = 1/8

C’s one day work = 1/12

A’s share: B’s share: C’s share = 1/6:1/8:1/12

= 4 : 3 : 2

∴ B’s share = 1350×3/9 = ₹ 450

RRB JE ME (CBT I) Mock Test- 4 - Question 5
Save

The cost price of an article is ₹ 3,90 and sold at a profit of 3.12%, how much would be its approximate selling price?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 5
S.P. = 390 + 3.12% of 390 = ₹ 402.168
RRB JE ME (CBT I) Mock Test- 4 - Question 6
Save

The two chords AB and CD of a circle cut each other perpendicularly at point O. OA = 2 cm, OC = 3 cm and OB = 6 cm, then what will be the diameter of the circle?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 6

Alternate solution

Now, diameter

Diameter

RRB JE ME (CBT I) Mock Test- 4 - Question 7
Save

17 articles were bought for ₹ 3,910 and sold for ₹ 4,590. How much was the approximate profit percentage per article?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 7
Profit = 4590 - 3910

= Rs. 680

Profit percentage = 680/3910 x 100

= 17.39%

= 17% approximately.

RRB JE ME (CBT I) Mock Test- 4 - Question 8
Save

If cos A + cos 2A = 1, then sin 2A + sin 4A = ?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 8
cos A = 1 – cos2 A

= sin2 A

Now, since

sin2 A + cos2 A = 1

⇒ sin2 A + (sin2 A)2 = 1

⇒ sin2 A + sin4 A = 1

RRB JE ME (CBT I) Mock Test- 4 - Question 9
Save

If θ is a positive acute angle and tan 2θ.tan 3θ = 1, then what will be the value of (2 cos2 5θ/2−1)?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 9

tan2θ.tan3θ = 1

tan2θ = cot3θ

⇒ θ = 180

RRB JE ME (CBT I) Mock Test- 4 - Question 10
Save

A mixture contains spirit and water in the ratio 3:2. If it contains 3 liters more spirit than water, the quantity of spirit in the mixture is?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 10
Let the amount of water be x liters

∴ x+3/x = 3/2

or 2x + 6 = 3x or, x= 6

∴ The quantity of spirit in the mixture = x + 3 = 6 + 3

= 9 liters

RRB JE ME (CBT I) Mock Test- 4 - Question 11
Save

What will be the compound interest on a sum of Rs. 25,000 after three years at the rate of 12% per annum?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 11

RRB JE ME (CBT I) Mock Test- 4 - Question 12
Save

A round balloon of radius r subtends an angle α at the eye of an observer while the angle of elevation of its center is β. The height of the center of the balloon is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 12
Let O be the center of balloon of radius r. The observer’s eye is at C.

∠ACB = α and ∠OCD = β clearly, CA and CB are tangents to the circle. So

∠ACO = ∠BCO = α/2

In right angled ∆OBC,

In right angled △OCD

∴ Height of the center of the balloon is r sin β. cosec α/2

RRB JE ME (CBT I) Mock Test- 4 - Question 13
Save

The largest and the second largest angles of a triangle are in the ratio of 3 : 2 respectively. The smallest angle is 20% of the sum of the rest two angles. What is the sum of the smallest and the second largest angles?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 13
If the largest and the second largest angles be 3x and 2x respectively then, third angle = x

∴ x + 2x + 3x = 180°

⇒ x = 30o

∴ Required sum

= x + 2x = 3x = 90°

RRB JE ME (CBT I) Mock Test- 4 - Question 14
Save

Study the following Pie Chart carefully and answer the questions given below:

Budget estimated by a family for their monthly expenses

What is the budget estimated by the family on Clothing and Grocery together?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 14
Budget estimated on Clothing and Grocery together= (25 + 8)% of ₹ 32,000

= (33/100) × 32000 = ₹ 10,560

RRB JE ME (CBT I) Mock Test- 4 - Question 15
Save

Study the following Pie Chart carefully and answer the questions given below:

Budget estimated by a family for their monthly expenses

Due to a sudden marriage, the family incurs Miscellaneous expenditure of ₹ 3,040. How much is the increase in the amount under this head from that of the budgeted?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 15
Budget estimated on miscellaneous 7% of ₹ 32,000

= (7/100) × 32000 = ₹ 2240

Required change= 3040-2240 = 800

RRB JE ME (CBT I) Mock Test- 4 - Question 16
Save

PQ is a direct common tangent of two circles of radii r1 and r2 touching each other externally at A. Then the value of PQ2 is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 16

Since opposite sides are parallel and interior angles are 90° therefore OPQR is a rectangle.

OP = QR = r1

In △OO'R,

∠ORO' = 90°

By Pythagoras theorem,

OR2 + O'R2 = OO'2

OR2 + (r1 - r2)2 = (r1 + r2)2

OR2 = 4r1r2

∴ PQ2 = OR2 = 4r1r2

RRB JE ME (CBT I) Mock Test- 4 - Question 17
Save

20% of the 4/5th of a number is 60, find the number?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 17

RRB JE ME (CBT I) Mock Test- 4 - Question 18
Save

If a number x is 10% less than another number y and y is 10% more than 125, then x is equal to
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 18
x = y - 10% of y

x = 9/10 y

New, y = 125 + 10% of 125

= 110/100 × 125

∴ x = 9/10 × 110/100 × 125 = 123.75

RRB JE ME (CBT I) Mock Test- 4 - Question 19
Save

If A, B, C, D are four points in a straight line such that distance from A to B is 10, B to C is 5, C to D is 4 and A to D is 1, then their correct sequence is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 19
Given that the distance from A to B = 10 and B to C = 5 and C to D = 4, D to A = 1

∴ The correct sequence is A - D - C - B which is in increasing order.

RRB JE ME (CBT I) Mock Test- 4 - Question 20
Save

The ratio between the speeds of a truck, car and train is 3 : 8: 12. The car moved uniformly and covered a distance of 1040 km in 13 hours. What is the average speed of the truck and the train together?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 20
The ratio between the speeds of the truck, car, and train is 3:8:12

Given that the car covers 1040 km in 13 hours, the speed of the car 80 km/h

Also, if we assume that the speeds of the truck, car, and train are 3x, 8x and 12x

respectively, then

x = 10

Therefore, speed of truck 30 km/h

Speed of train = 120 km/h

The average speed of truck and train is calculated as:

2×30×120/30+120 = 48 km/h

RRB JE ME (CBT I) Mock Test- 4 - Question 21
Save

A, B, and C contract a work for Rs. 550 together. A and B are supposed to do 7/11 of the work. The amount that C gets is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 21

RRB JE ME (CBT I) Mock Test- 4 - Question 22
Save

The radius of a cylinder is the same as that of a sphere. There volumes are equal. The height of the cylinder is how many times of its radius?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 22
Radius of cylinder = Radius of sphere and volume of cylinder = volume of sphere

RRB JE ME (CBT I) Mock Test- 4 - Question 23
Save

A train traveling at 65 kmph leaves Mumbai at 10 A.M. and another train travelling at 75 kmph starts at 12 Noon in the same direction. How many k.m. away from Mumbai will they be together?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 23
In two hours, the first train is 2 x 65 kms i.e, 130 kms ahead of the second train The second train moves 10 kms faster so it will meet the first train in (130 ÷ 10)

i.e.. 13 hours

∴ Distance travelled by the second train = 13 x 75 km = 975 km

Therefore after 975 km both train will meet.

RRB JE ME (CBT I) Mock Test- 4 - Question 24
Save

If the angles of a pentagon are in the ratio 1 : 3 : 6 : 7 : 10, then the smallest angle is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 24
Suppose the angles of a pentagon are

x°, 3x°, 6x°, 7x°, 10x°

But x° + 3x° + 6x° + 7x° + 10x° = (2x5 -4) x 90°

or 27x° = 6 x 90°

or x = 20°

RRB JE ME (CBT I) Mock Test- 4 - Question 25
Save

A bob of length 50 cm makes an arc of 16 cm during its motion. What will be the measure of the angle thus formed (approx.)?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 25
Radius = 50 cm

Arc = 16 cm

Let the angle be θ.

16 = θ/360×2×π×50 ⇒ θ = 8×36×7/5×22 ≈ 18o33 ≈ 18°35'

RRB JE ME (CBT I) Mock Test- 4 - Question 26
Save

If the radius of a cylinder is tripled and the height is halved, what is the ratio between the new volume and the previous volume?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 26
Let the initial radius and height of the cylinder be r cm and h cm respectively.

Then, V1 = πr2 h and V2 = π.(3r).2.h/2 = 9/2 πr2h

New Volume/Previous Volume = 9/2πr2h/πr2h = 9/2 = 9:2

RRB JE ME (CBT I) Mock Test- 4 - Question 27
Save

Find the value of
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 27

RRB JE ME (CBT I) Mock Test- 4 - Question 28
Save

The sides of a triangle are 24 cm, 32 cm and 40 cm. What is the height of the perpendicular drawn on the longest side?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 28
The triangle thus formed is a right-angled triangle.

Thus, the length of perpendicular on the largest side

= 32×24/40 = 19.2 meter.

RRB JE ME (CBT I) Mock Test- 4 - Question 29
Save

If x sin3 θ + ycos3 θ = sin θ.cos θ and xsin θ = ycos θ, sin θ≠ 0, cos θ≠ 0, then x2 + y2 is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 29

RRB JE ME (CBT I) Mock Test- 4 - Question 30
Save

If 42x = 1/32 then x is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 4 - Question 30
42x = 1/32

or (22)2x = 1/25

or 24x = 2-5

∴ 4x = -5

or x = −5/4

View more questions
Information about RRB JE ME (CBT I) Mock Test- 4 Page
In this test you can find the Exam questions for RRB JE ME (CBT I) Mock Test- 4 solved & explained in the simplest way possible. Besides giving Questions and answers for RRB JE ME (CBT I) Mock Test- 4, EduRev gives you an ample number of Online tests for practice

Top Courses for Mechanical Engineering

Download as PDF

Top Courses for Mechanical Engineering

Important Questions for RRB JE ME (CBT I) Mock Test- 4

Find all the important questions for RRB JE ME (CBT I) Mock Test- 4 at EduRev.Get fully prepared for RRB JE ME (CBT I) Mock Test- 4 with EduRev's comprehensive question bank and test resources. Our platform offers a diverse range of question papers covering various topics within the RRB JE ME (CBT I) Mock Test- 4 syllabus. Whether you need to review specific subjects or assess your overall readiness, EduRev has you covered. The questions are designed to challenge you and help you gain confidence in tackling the actual exam. Maximize your chances of success by utilizing EduRev's extensive collection of RRB JE ME (CBT I) Mock Test- 4 resources.

RRB JE ME (CBT I) Mock Test- 4 MCQs with Answers

Prepare for the RRB JE ME (CBT I) Mock Test- 4 within the Mechanical Engineering exam with comprehensive MCQs and answers at EduRev. Our platform offers a wide range of practice papers, question papers, and mock tests to familiarize you with the exam pattern and syllabus. Access the best books, study materials, and notes curated by toppers to enhance your preparation. Stay updated with the exam date and receive expert preparation tips and paper analysis. Visit EduRev's official website today and access a wealth of videos and coaching resources to excel in your exam.

Online Tests for RRB JE ME (CBT I) Mock Test- 4

Practice with a wide array of question papers that follow the exam pattern and syllabus. Our platform offers a user-friendly interface, allowing you to track your progress and identify areas for improvement. Access detailed solutions and explanations for each test to enhance your understanding of concepts. With EduRev's Online Tests, you can build confidence, boost your performance, and ace RRB JE ME (CBT I) Mock Test- 4 with ease. Join thousands of successful students who have benefited from our trusted online resources.
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup