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Mechanical Engineering Exam  >  Mechanical Engineering Tests  >  RRB JE ME (CBT I) Mock Test- 5 - Mechanical Engineering MCQ

RRB JE ME (CBT I) Mock Test- 5 - Mechanical Engineering MCQ


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30 Questions MCQ Test - RRB JE ME (CBT I) Mock Test- 5

RRB JE ME (CBT I) Mock Test- 5 for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The RRB JE ME (CBT I) Mock Test- 5 questions and answers have been prepared according to the Mechanical Engineering exam syllabus.The RRB JE ME (CBT I) Mock Test- 5 MCQs are made for Mechanical Engineering 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for RRB JE ME (CBT I) Mock Test- 5 below.
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RRB JE ME (CBT I) Mock Test- 5 - Question 1
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DIRECTIONS: The pie-chart, given here, shows various expenses of a publisher in the production and sale of a book. Study the chart and answer questions based on it.

The measure of central angle for the sector on 'Printing cost' is:

Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 1
According to question 360×35/100 = 126o
RRB JE ME (CBT I) Mock Test- 5 - Question 2
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In an election between two candidates one get 57% of the total votes cast and won the election by 9800 votes. Find the total number of votes cast–

Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 2
winning candidates got = 57% votes

and losing candidates got = 100 – 57 = 43

∴ And won by = 9800 votes which is 57 – 43 = 14

∴ 14% = 9800

∴ 100% = 70000

∴ total votes = 70000

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RRB JE ME (CBT I) Mock Test- 5 - Question 3
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Find the angle of elevation of the sun, if the length of the shadow of a pole is 1/√3 times its height?

Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 3

RRB JE ME (CBT I) Mock Test- 5 - Question 4
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If the point (x, y) (1, 2) and (-3, 4) are collinear, then :
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 4

If (x, y) (1, 2) and (-3, 4) are collinear then the triangle formed by points should be zero

∴1/2 [2x + 4 - 3y - 4x + 6 -y] = 0

-2x- 4y + 10 = 0

x + 2y - 5 = 0

RRB JE ME (CBT I) Mock Test- 5 - Question 5
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The dimensions of a piece of iron in the shape of a cuboid are 270 cm x 100 cm x 64 cm. If it is melted and recast into a cube, then the surface area of the cube will be :
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 5

Volume of cube = volume of cuboid

= 270 x 100 x 64 = 1728000 cm3

∴ Length of one side of the cube = 120 cm

∴ Surface area of cube = 6 x 120 x 120 = 86400 cm2

RRB JE ME (CBT I) Mock Test- 5 - Question 6
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The average age of a family of five persons is 20 years. If the youngest member is 8 years old then, what was the average age of the family at the birth time of the youngest member.
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 6
Sum of the age of family = 5 x 20 = 100 years

8 years before, sum of age = 100 - 8 x 5 = 60 years

RRB JE ME (CBT I) Mock Test- 5 - Question 7
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If a train takes 1.75 sec to cross a telegraph pole and 1.5 sec to a cyclist travelling in opposite direction at 10 m per second, then the length of the train is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 7
Spouse speed of train = x m/s

or length of train = I m

Time taken by trains to cross a telegraph cost

Using (i) and (ii)

RRB JE ME (CBT I) Mock Test- 5 - Question 8
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The semi-perimeter of a right angled triangle ABC is 12 cm and the shortest median is 5 cm. What is area of the triangle which has the largest median of triangle ABC as its longest side?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 8

Given: S = 12 cm & BP = 5 cm

∴ AP = PC = BP = 5 cm

∴ AC = 10 cm

We know the ratio of Right triangle like (3 : 4 : 5)

then we assume the ratio, (6 : 8 : 10)

So, the other two sides = 8 cm , 6 cm

RRB JE ME (CBT I) Mock Test- 5 - Question 9
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If 4 sin2 x - 3 = 0, 0 < x < 2π, then the values of x are:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 9

4 sin2 x - 3 = 0

or sin2 x = 3/4

RRB JE ME (CBT I) Mock Test- 5 - Question 10
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Sum of the lengths of any two sides of a triangle is always greater than
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 10
The sum of the other two sides of a triangle is always greater than the third side.
RRB JE ME (CBT I) Mock Test- 5 - Question 11
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If 391 bananas were distributed among three monkeys in the ratio 1/2:2/3 :3/4, how many bananas did the first monkey get?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 11

The ratio: 1/2 : 2/3 : 3/4

Converts to 6 : 8 : 9 (on multiplying by 12)

Thus, the first monkey would get (391/23) × 6 = 102 bananas.

RRB JE ME (CBT I) Mock Test- 5 - Question 12
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A is twice as good as B and can finish a piece of work in 30 days less than B. In how many days they can complete the whole work working together?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 12
Let A can complete the work in x days.

So, B can complete the work in 2x days.

A.T.Q., 2x - x = 30 ⇒ x = 30 days

They both can complete in

RRB JE ME (CBT I) Mock Test- 5 - Question 13
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What is the correct ascending order for the fractions?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 13

We know that,

22/7 = 3.14

13/17 = 0.76

11/19 = 0.57

2/3 = 0.66

The correct ascending order for the fractions is

11/19, 2/3, 13/17, 22/7

RRB JE ME (CBT I) Mock Test- 5 - Question 14
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The area of a circle is increased by 44 cm2 when its radius is increased by 2 cm. The original radius of the circle is–
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 14
Let the original radius of circle = R

Area of circle = πR2

According to question,

π[(R+2)2−R2] = 44

22/7×[R2+4+4R−R2] = 44

4 + 5R = 14

R = 2 cm.

RRB JE ME (CBT I) Mock Test- 5 - Question 15
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In the figure, OP ⊥ OA and OQ ⊥ OB.

Find ∠POQ if ∠AOB = 200
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 15
∠BOP = 90o - ∠AOB

= 90o - 70o

= 20o

∴ ∠POQ = 90o - ∠BOP

= 90o - 70o

= 20o

RRB JE ME (CBT I) Mock Test- 5 - Question 16
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If 2 men and 3 women can do a piece of work in 8 days and 3 men and 2 women in 7 days. In how many days can the work be done by 5 men and 4 women working together?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 16
|2 x 8 - 3 x 7| men’s work = |3x 8 - 2 x 7| women’s work.

∴ 5 men’s work = 10 women’s work

∴ 1 men’s work = 2 women’s work

2 men’s work = 4 women’s work

∴ Days taken by 5 men + 4 women = 14 women are = 7×8/14 = 4 days

Alternate method-

⇒ (2 M + 3W) 8 = (3M + 2W)7

⇒ 16M + 24W = 21M + 14 W

⇒ 10W = 5M

⇒ 2W = M

⇒ 14W × (x) = 7W × 8

= (x) = 4 days

RRB JE ME (CBT I) Mock Test- 5 - Question 17
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If the volume of a cube is 729 cm3, then the total surface area of the cube will be :
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 17
Volume of the cube = 729 cm3

∴ Length of one side of the cube = 9 cm

∴ surface are of the cube = 6 x 9 x 9 = 486 cm2

RRB JE ME (CBT I) Mock Test- 5 - Question 18
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Two pipes A and B, can fill a tank in 60 minutes and 75 minutes, respectively. There is also an outlet C. If A, B, and C are opened together, the tank is full in 50 minutes. How much time will be taken by C to empty the full tank?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 18

(A + B) eff = 9

(A + B - C) eff = 6

So, C eff = 3 units

C will empty the tank = 300/3 = 100 min

RRB JE ME (CBT I) Mock Test- 5 - Question 19
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If 10 persons can do a job in 20 days. Then 20 persons with the twice efficiency can do the same job in:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 19
Let the number of days b x.

Here efficiency is 2 : 1

Number of days 20 : x

RRB JE ME (CBT I) Mock Test- 5 - Question 20
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A sum of Rs.1,075 is divided among Aman, Anu and Aradhya such that Aman receives 25% more than Aradhya and Aradhya receive 25% less than Anu. What is Aman’s share in the amount?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 20
Let Anu get x, then Aaradhya get 75% of x and Aman gets 125% amount of 75% of x

75% of x + 125% of 75% of x + x = 1075

x = 400

125/100 × 75/100 × 400

= Rs.375.

RRB JE ME (CBT I) Mock Test- 5 - Question 21
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The horizontal distance between two towers is 90 m and the angular depression of the top of the first as seen from the top of the second is 30o. Find the difference of the heights of the two towers.
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 21

Difference between the height of tower = DE

Again Ab = DC

From △CDE

RRB JE ME (CBT I) Mock Test- 5 - Question 22
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If the ratio of the areas of two squares is 16 : 1, then the ratio of their perimeters is?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 22
Area of square = (side)2

Ratio of sides of two square = 4 : 1

Perimeter of square = 4 x side

Ratio of perimeter of two squares = 16 : 4 = 4 : 1

RRB JE ME (CBT I) Mock Test- 5 - Question 23
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If the ratio areas of two squares is 225 : 256, then the ratio of their perimeters is?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 23

Ratio of their perimeters-

15 ;:16

RRB JE ME (CBT I) Mock Test- 5 - Question 24
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The time duration of 1 hour 45 minutes is what percent of a day?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 24
1 hours 45 minutes = 7/2 hours

= [7/(4×24)]×100 = 7.291%

RRB JE ME (CBT I) Mock Test- 5 - Question 25
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Two circles of radii 4 cm each cuts each other such that each circle passes through the centre of each other. Thus, what is the length of the common chord?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 25

Let the centres be O & O'

In △OPM,

OP2 = OM2 + PM2

16 = 4 + PM2

∴ Length of the common chord

RRB JE ME (CBT I) Mock Test- 5 - Question 26
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In ΔABC, medians BE and CF intersect at G. If the straight line AGD meets BC at D in such a way that GD = 1.5 cm, then, length of AD is:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 26

GD = 1/3 AD

or AD = 3 GD

AD = 3 × 1.5 = 4.5 cm

RRB JE ME (CBT I) Mock Test- 5 - Question 27
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If two person A and B start at the same time in opposite direction from two points and after passing each other they complete the journey in a and b hours respectively, then the ratio of A’s and B’s speed will be:
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 27

Let total distance be D km. and A's speed be x km/hr and B's speed be y km/hr

RRB JE ME (CBT I) Mock Test- 5 - Question 28
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Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 28

RRB JE ME (CBT I) Mock Test- 5 - Question 29
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Students of a class stand in a queue. If Ramesh is 19th in order from both ends. How many students are there in the queue?
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 29
Ramesh is 19th from both ends.

∴ There are 18 student on his each side

∴ Total students in the queue = 18 × 2 + 1 = 37

RRB JE ME (CBT I) Mock Test- 5 - Question 30
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If (a/b)x-1 = (b/a)x-3 , the the value of x is :
Detailed Solution for RRB JE ME (CBT I) Mock Test- 5 - Question 30

∴ x - 1 = 3 - x or 2x = 4

∴ x = 2

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