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Test: Mensuration - Class 6 MCQ


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10 Questions MCQ Test - Test: Mensuration

Test: Mensuration for Class 6 2024 is part of Class 6 preparation. The Test: Mensuration questions and answers have been prepared according to the Class 6 exam syllabus.The Test: Mensuration MCQs are made for Class 6 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Test: Mensuration below.
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Test: Mensuration - Question 1

The length and breadth of a rectangle are 40 cm and 10 cm respectively. Its perimeter is

Detailed Solution for Test: Mensuration - Question 1

We know, Perimeter of a rectangle is  2 ( l + b )

 Here Length (l) = 40 cm and Breadth (b) = 10 cm

So putting the values in the above equation we have :

2 ( 40 + 10 ) = 2(50) = 100 cm

So perimeter of a rectangle is 100 cm.

Test: Mensuration - Question 2

The length of a rectangle is 150 cm. If its breadth is 1 m, then its perimeter is

Detailed Solution for Test: Mensuration - Question 2

Length of rectangle=150 cm = 1.5 m
breadth of rectangle=1 m
perimeter=2(length+breadth)
=2(1.5+1)
=2×2.5
=5.0 m

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Test: Mensuration - Question 3

The side of a square is 12 m. Its perimeter is

Detailed Solution for Test: Mensuration - Question 3

Perimeter of square is 4 X side

thus 4 X 12 = 48 m
 

Test: Mensuration - Question 4

If the area of a square is 64 cm2, then its perimeter is

Detailed Solution for Test: Mensuration - Question 4

The correct option is A 
Given: Area of the square =64 cm2
We know, area of a square = side × side
 64 = (side)2

√64 = side

∴ Side of the square = 8 cm
Perimeter of the square = 4 × side
= 4 × 8
= 32 cm
Therefore, perimeter of the square = 32 cm

Test: Mensuration - Question 5

The side of a square is 6 cm. If its side is doubled, then its new perimeter is

Detailed Solution for Test: Mensuration - Question 5

Given:
Side of the square = 6 cm
To find:
New perimeter when the side is doubled
Step 1: Find the perimeter of the original square
- The perimeter of a square is given by the formula P = 4s, where s is the length of a side
- Plugging in the given value, P = 4 * 6 = 24 cm
Step 2: Double the length of the side
- Doubling the side length of the square, we get 6 cm * 2 = 12 cm
Step 3: Find the perimeter of the new square
- Using the formula P = 4s, where s is the length of a side, we have P = 4 * 12 = 48 cm
Step 4: Compare the perimeters
- The new perimeter of the square is 48 cm, which is greater than the original perimeter of 24 cm
Step 5: Conclusion
- The new perimeter when the side of the square is doubled is 48 cm.
Therefore, the correct answer is option A: 48 cm.
Test: Mensuration - Question 6

The area of a rectangular sheet is 500 cm2. If the length of the sheet is 25 cm, what is its width?

Detailed Solution for Test: Mensuration - Question 6

Given:
- The area of a rectangular sheet is 500 cm2.
- The length of the sheet is 25 cm.
To find:
- The width of the sheet.
Let's assume the width of the sheet as 'w'.
We know that the area of a rectangle is given by the formula:
Area = Length × Width
Substituting the given values, we have:
500 = 25 × w
To find the value of 'w', we can rearrange the equation:
w = 500 / 25
Simplifying the equation, we get:
w = 20
Therefore, the width of the rectangular sheet is 20 cm.
Answer:
A:

20 cm

Test: Mensuration - Question 7

The side of a square is 8 cm. Its area is

Detailed Solution for Test: Mensuration - Question 7

To find the area of a square, we need to square the length of one of its sides.
Given:
Side of the square = 8 cm
To find the area of the square, we can use the formula:
Area = side * side
Substituting the given value, we have:
Area = 8 cm * 8 cm
Calculating the area, we get:
Area = 64 cm²
Therefore, the area of the square is 64 cm².
Answer: D. 64 cm²

Test: Mensuration - Question 8

Find the area of a rectangle whose length is 11 cm and breadth is 4 cm.

Detailed Solution for Test: Mensuration - Question 8

The area of a rectangle is calculated using the formula:

Area=Length×Breadth

Substitute the given values:

Area=11×4=44 sq. cm

Test: Mensuration - Question 9

The area of a rectangle is 96 cm2. If the breadth of the rectangle is 8 cm, find its perimeter. 

Detailed Solution for Test: Mensuration - Question 9

Area of rectangle = L×B

96= L x 8
L = 96/8
Length of rectangle = 12cm
Perimeter of rectangle = 2×(l+b)
= 2× (12+8)
= 2×20
Perimeter of rectangle =40 cm

Test: Mensuration - Question 10

Bob wants to cover the floor of a room 3 m wide and 4 m long with square tiles. Each square tile has a side of 0.5 m. How many tiles are required to cover the floor of the room?

Detailed Solution for Test: Mensuration - Question 10

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