Test: Linear Equations- 1 - Class 8 MCQ

Given, 2x - 3 = x + 2
Transposing 'x' to L.H.S
⇒ 2x - x - 3 = 2
⇒ x - 3 = 2
Transposing '3' to R.H.S
⇒ x = 2 + 3
⇒ x = 5.
Therefore, option (b) is the correct answer.

Given equation is 5x−2(2x−7) = 2(3x−1)+7/2

after opening the brackets
5x-4x+14 = 6x-2+7/2
taking x to one side constants to other side
6x+4x-5x=14+2-7/2
or 5x = 16-7/2
or 5x = (32-7)/2
or 5x = 25/2
or x = 25/10
or x = 5/2 (answer)

Given, 2x-3=7
Transposing -3 to R.H.S
2x=7+3
⇒ 2x=10
Transposing '2' to R.H.S, we get
x=10/2
⇒ x=5.
Therefore, the correct option is c.

Given, 2y + 9 =4
Transposing '9' to R.H.S, we get
2y = 4-9
⇒ 2y = -5
Therefore, y = -5/2
Hence, option 'A' is correct.

Given, 3x−7=2x+5

Transposing 2x to LHS:

3x−2x−7=5

x−7=5

Transposing −7 to RHS:

x=5+7

x=12

Therefore, option (C) is correct.

An algebraic equation is an equality that involves variables. It states that two expressions are equal to each other, typically connected by an equals sign =. For example, in the equation 2x+3=7, the expression 2x+3 is equal to 7. The equation shows the relationship between the variable x and the constants.

Expanding both sides:

4y−8+3=2y+2+5

4y−5=2y+7

Transposing 2y to LHS and −5 to RHS:

4y−2y=7+5

2y=12

Dividing by 2:

y=6

Therefore, option (A) is correct.

Given, 3x = 12
Transposing '3' to R.H.S, we get
x = 12/3
⇒ x = 4

or
Divide both sides by '3' to get the value of x
3x/3 = 12/3 
⇒ x = 4

We have 4x + 5 = 9
⇒ 4x = 9 – 5 (Transposing 5 to RHS)
⇒ 4x = 4
⇒ x = 1 (Transposing 4 to RHS)

Given, 6a+5=3a+14
Transposing 3a to LHS and 5 to RHS:

6a−3a=14−5

3a=9

Dividing by 3:

a=3

Therefore, option (A) is correct.