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Class 9 Exam  >  Class 9 Tests  >  Case Based Questions Test: Real Numbers - 2 - Class 9 MCQ

Case Based Questions Test: Real Numbers - 2 - Class 9 MCQ


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10 Questions MCQ Test - Case Based Questions Test: Real Numbers - 2

Case Based Questions Test: Real Numbers - 2 for Class 9 2024 is part of Class 9 preparation. The Case Based Questions Test: Real Numbers - 2 questions and answers have been prepared according to the Class 9 exam syllabus.The Case Based Questions Test: Real Numbers - 2 MCQs are made for Class 9 2024 Exam. Find important definitions, questions, notes, meanings, examples, exercises, MCQs and online tests for Case Based Questions Test: Real Numbers - 2 below.
Solutions of Case Based Questions Test: Real Numbers - 2 questions in English are available as part of our course for Class 9 & Case Based Questions Test: Real Numbers - 2 solutions in Hindi for Class 9 course. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free. Attempt Case Based Questions Test: Real Numbers - 2 | 10 questions in 20 minutes | Mock test for Class 9 preparation | Free important questions MCQ to study for Class 9 Exam | Download free PDF with solutions
Case Based Questions Test: Real Numbers - 2 - Question 1
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Direction: Read the following text and answer the following questions on the basis of the same:

A seminar is being conducted by an Educational Organisation, where the participants will be educators of different subjects. The number of participants in Hindi, English and Mathematics are 60, 84 and 108 respectively.

108 can be expressed as a product of its primes as

Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 1
All even numbers except 2 are composite numbers, so 108 is a composite number.

Therefore, we can conclude that 108 can be expressed as a product of prime factors by 22 × 33.

Case Based Questions Test: Real Numbers - 2 - Question 2
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Direction: Read the following text and answer the following questions on the basis of the same:

A seminar is being conducted by an Educational Organisation, where the participants will be educators of different subjects. The number of participants in Hindi, English and Mathematics are 60, 84 and 108 respectively.

What is the minimum number of rooms required during the event?

Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 2
Minimum no. of rooms required are total number of students divided by number of students in each room.

= 21

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Case Based Questions Test: Real Numbers - 2 - Question 3
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Direction: Read the following text and answer the following questions on the basis of the same:

A seminar is being conducted by an Educational Organisation, where the participants will be educators of different subjects. The number of participants in Hindi, English and Mathematics are 60, 84 and 108 respectively.

The product of HCF and LCM of 60,84 and 108 is

Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 3
60 = (22 × 3 × 5)

84 = (22 × 3 × 7)

108 = (22 × 33)

HCF(60, 84,108) = (22 × 3) = 12

LCM =

LCM of 60, 84, and 108 is 3780.

Product of HCF x LCM = 3780 x 12 = 45360

Case Based Questions Test: Real Numbers - 2 - Question 4
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Direction: Read the following text and answer the following questions on the basis of the same:

A seminar is being conducted by an Educational Organisation, where the participants will be educators of different subjects. The number of participants in Hindi, English and Mathematics are 60, 84 and 108 respectively.

In each room the same number of participants are to be seated and all of them being in the same subject, hence maximum number participants that can accommodated in each room are
Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 4
No. of participants seated in each room would be HCF of all the three values above.

60 = 2 × 2 × 3 × 5

84 = 2 × 2 × 3 × 7

108 = 2 × 2 × 3 × 3 × 3

Hence, HCF = 12.

Case Based Questions Test: Real Numbers - 2 - Question 5
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Direction: Read the following text and answer the following questions on the basis of the same:

A seminar is being conducted by an Educational Organisation, where the participants will be educators of different subjects. The number of participants in Hindi, English and Mathematics are 60, 84 and 108 respectively.

The LCM of 60, 84 and 108 is
Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 5

LCM = 2 x 2 x 3 x 3 x 3 x 5 x 7

LCM = 3780

Therefore, LCM of 60, 84, and 108 is 3780.

Case Based Questions Test: Real Numbers - 2 - Question 6
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Direction: Read the following text and answer the following questions on the basis of the same:

A Mathematics Exhibition is being conducted in your School and one of your friends is making a model of a factor tree. He has some difficulty and asks for your help in completing a quiz for the audience.

The prime factorisation of 13915 is
Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 6

Using the prime factorization tree, we have

∴ 13915 = 5 × 11 × 11 × 23 = 5 × 112 × 23

Case Based Questions Test: Real Numbers - 2 - Question 7
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Direction: Read the following text and answer the following questions on the basis of the same:

A Mathematics Exhibition is being conducted in your School and one of your friends is making a model of a factor tree. He has some difficulty and asks for your help in completing a quiz for the audience.

What will be the value of y?
Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 7
2783 = y × 253

y = 2783/253

y = 11

Case Based Questions Test: Real Numbers - 2 - Question 8
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Direction: Read the following text and answer the following questions on the basis of the same:

A Mathematics Exhibition is being conducted in your School and one of your friends is making a model of a factor tree. He has some difficulty and asks for your help in completing a quiz for the audience.

According to Fundamental Theorem of Arithmetic 13915 is a
Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 8
The prime factorization of 13,915 is 5 × 112 × 23.

Since it has a total of 4 prime factors, 13,915 is a composite number.

Case Based Questions Test: Real Numbers - 2 - Question 9
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Direction: Read the following text and answer the following questions on the basis of the same:

A Mathematics Exhibition is being conducted in your School and one of your friends is making a model of a factor tree. He has some difficulty and asks for your help in completing a quiz for the audience.

What will be the value of x?
Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 9
x = 2783 × 5

x = 13915

Case Based Questions Test: Real Numbers - 2 - Question 10
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Direction: Read the following text and answer the following questions on the basis of the same:

A Mathematics Exhibition is being conducted in your School and one of your friends is making a model of a factor tree. He has some difficulty and asks for your help in completing a quiz for the audience.

What will be the value of z?
Detailed Solution for Case Based Questions Test: Real Numbers - 2 - Question 10
253 = 11 × z

z = 253/11

z = 23

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